我正在尝试制作一个海龟赛车游戏(使用Python - Turtle),但我不知道如何在每次运行代码时为每只海龟设置一个随机速度(这样海龟x不会每次都赢)
#define race fuction. Move each Turtle fd(random number between 2-10)
red.pensize(10)
blue.pensize(10)
green.pensize(10)
red.speed(random)
blue.speed(random)
green.speed(random)
发布于 2017-02-11 12:55:43
将turtle.speed()
设置为任何值,包括random.randint()
的结果,既不必要也不充分。这非常方便。下面是我的极简主义乌龟赛车代码。turtle.speed()
方法用作存储海龟速度的位置,但如果您更改:
turtle.forward(turtle.speed() + 1)
设置为固定值:
turtle.forward(10)
您将看到,无论turtle.speed()
的设置如何,这些海龟都以相同的速率移动。turtle.speed()
值仅决定海龟绘制其更新的速度。最终,turtle.forward()
参数中的差异控制着向前运动的量:
from random import randint
from turtle import Turtle, Screen
TURTLE_SIZE = 20
MAXIMUM_SPEED = 10
DEFAULTS = {'shape':"turtle", 'visible': False}
screen = Screen()
starting_line = TURTLE_SIZE - screen.window_width()/2
finish_line = screen.window_width()/2 - TURTLE_SIZE - MAXIMUM_SPEED
turtles = dict(red=Turtle(**DEFAULTS), green=Turtle(**DEFAULTS), blue=Turtle(**DEFAULTS))
for i, (color, turtle) in enumerate(turtles.items()):
turtle.color(color)
turtle.penup()
turtle.goto(starting_line, i * TURTLE_SIZE)
turtle.speed(randint(0, MAXIMUM_SPEED))
turtle.showturtle()
racing = True
while racing:
for turtle in turtles.values():
turtle.forward(turtle.speed() + 1)
if turtle.xcor() >= finish_line:
racing = False
break
screen.exitonclick()
要让海龟比赛变得更加复杂,您可能需要使用ontimer()
事件来允许它们更加独立地移动。
https://stackoverflow.com/questions/42170569
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