blocks|key|1630633|text|您需要告诉构建系统在编译时链接到共享库。这允许依赖项存储在编译的PHP扩展中，它将在第一次使用时加载。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1630634|为此，您需要修改config.m4以添加库。您可以通过PHP_ADD_LIBRARY宏来执行此操作。此宏将一个库添加到链接行中，格式为PHP_ADD_LIBRARY($name,$append,$var)。第一个参数是库的名称；这是不带lib前缀的*.so文件的名称(例如xxx)。第二个参数决定(我假设)该行是被追加还是被覆盖；它通常应该设置为1。最后一个参数是存储该行的变量名。必须通过PHP_SUBST将此变量替换到输出文件中。|offset|length|style|CODE|1630635|您应该将PHP_ADD_LIBRARY行放在config.m4文件中PHP_NEW_EXTENSION宏之前的某个位置。此外，将PHP_ADD_LIBRARY包装在PHP_CHECK_LIBRARY调用中也是一个好主意。这确保了在添加库之前，构建系统可以找到该库。请参见下面的示例。|1630636|Here是另一个和你的问题类似的问题。它有一些可供您参考的工作示例。此外，我将在这里提供一个快速示例：|1630637|PHP_CHECK_LIBRARY(xxx,xxxfunction,[
++++PHP_ADD_LIBRARY(xxx,1,XXX_SHARED_LIBADD)
],[
++++AC_MSG_ERROR([Please+install+libxxx+on+the+system])
],
[])

PHP_SUBST([XXX_SHARED_LIBADD])|code-block|syntax|javascript|1630638|注意：PHP_CHECK_LIBRARY的第二个参数是一个函数，构建系统将检查该函数是否找到给定库。|1630639|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/29609438/php-linking-to-a-shared-library-in-an-extension^0|0|8|9|R|F|1V|Z|3A|3|3G|4|3S|3|4T|1|5F|9|0|4|F|M|9|Y|H|1S|F|2A|H|0|0|4|0|0|0|3|H|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]|$D|14|E|15|F|G]|$D|16|E|17|F|G]|$D|18|E|19|F|G]|$D|1A|E|1B|F|G]|$D|1C|E|1D|F|G]|$D|1E|E|1F|F|G]|$D|1G|E|1H|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|1I|8|@$D|1J|E|1K|F|G]|$D|1L|E|1M|F|G]|$D|1N|E|1O|F|G]|$D|1P|E|1Q|F|G]|$D|1R|E|1S|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1T|8|@]|9|@$D|1U|E|1V|1|1W]]|A|$]]|$1|L|3|M|5|N|7|1X|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|1Y|8|@$D|1Z|E|20|F|G]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|21|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

You need to tell the build system to link against the shared library at compile time. This allows the dependency to be stored in the compiled PHP extension, where it will be loaded at first use.

To do this, you need to modify the <code>config.m4</code> to add a library. You can do this via the <code>PHP_ADD_LIBRARY</code> macro. This macro adds a library to the link line and has the form <code>PHP_ADD_LIBRARY($name,$append,$var)</code>. The first parameter is the name of the library; this is the name of the <code>*.so</code> file without the <code>lib</code> prefix (e.g. <code>xxx</code>). The second parameter determines (I presume) whether the line is appended or overwritten; this should usually be set to <code>1</code>. The final parameter is the variable name into which the line is stored. This variable must be substituted into the output file via <code>PHP_SUBST</code>.

You should place your <code>PHP_ADD_LIBRARY</code> line somewhere before the <code>PHP_NEW_EXTENSION</code> macro in the <code>config.m4</code> file. In addition, it's a good idea to wrap the <code>PHP_ADD_LIBRARY</code> in a <code>PHP_CHECK_LIBRARY</code> call. This ensures the library can be found by the build system before adding it. See my example below.

<a href="https://stackoverflow.com/questions/29609438/php-linking-to-a-shared-library-in-an-extension">Here</a> is another SO question that is similar to yours. It has some working examples you can follow. Additionally, I'll include a quick example here:

<pre><code>PHP_CHECK_LIBRARY(xxx,xxxfunction,[
 PHP_ADD_LIBRARY(xxx,1,XXX_SHARED_LIBADD)
],[
 AC_MSG_ERROR([Please install libxxx on the system])
],
[])

PHP_SUBST([XXX_SHARED_LIBADD])
</code></pre>

Note: The second parameter to <code>PHP_CHECK_LIBRARY</code> is a function for which the build system will check if it finds the given library.

I was given a <code>libxxx.so</code> file which i can't view it's source code and i can compile my c file with the next command:

<pre><code>gcc -ldl libxxx.so my.c -a a.out
</code></pre>

<code>a.out</code> worked well in command line. But after i wrapped it into a <code>PHP</code> extension, <code>PHP</code> showed a message like this:

<pre><code>PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib64/php/modules/myextension.so' - /usr/lib64/php/modules/myextension.so: undefined symbol: xxxfunction in Unknown on line 0
</code></pre>

xxxfunction is a function exported by <code>libxxx.so</code>.

I'm new to <code>C</code> and I think the problem is the way of compiling my <code>PHP</code> extension, i searched google but didn't find the answer. 
I'm wondering whether there is an option like -ldl in gcc so i can specify that i'm going to use the libxxx.so in my <code>PHP</code> extention. 
I compiled my extension by next steps:

<pre><code>cd myextension/
phpize
./configure
make
make install
</code></pre>

I have moved <code>libxxx.so</code> file to <code>/usr/local/lib</code>. 
My /etc/ld.so.conf:

<pre><code>include ld.so.conf.d/*.conf
/usr/local/lib
</code></pre>

I have runed <code>lddconfig</code>.

How to load my own libxxx.so in php extension source code?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我得到了一个libxxx.so文件，我无法查看它的源代码，我可以用下面的命令编译我的c文件：gcc -ldl libxxx.so my.c -a a.outa.out在命令行中工作得很好。但在我将其封装到PHP扩展中后，PHP显示了如下消息：PHP Warning:  PHP Startup: Unable to lo...

如何在php扩展源码中加载自己的libxxx.so？-腾讯云开发者社区-腾讯云

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