有没有一种方法可以在上面的行后面加上"java版本或许可被拒绝“这一行,在它们之间加一个?我希望在用于red hat 6的bash上实现数据操作目的。
谢谢
/apps/orautil/app/oracle/product/12.1.0/client_1/jdk/jre/lib/
java version "1.6.0_75"
/export/file/node/jre1.8.0_171/lib/
java version "1.8.0_171"
/test/jre1.8.0_171_linux/lib/
java version "1.8.0_171"
/usr/local/tripwire/te/agent/jre/lib/
sh: line 4: /usr/local/tripwire/te/agent/jre/lib/../bin/java: Permission denied
预期结果
/apps/orautil/app/oracle/product/12.1.0/client_1/jdk/jre/lib/,java version "1.6.0_75"
/export/file/node/jre1.8.0_171/lib/,java version "1.8.0_171"
/test/jre1.8.0_171_linux/lib/,java version "1.8.0_171"
/usr/local/tripwire/te/agent/jre/lib/,sh: line 4: /usr/local/tripwire/te/agent/jre/lib/../bin/java: Permission denied
发布于 2018-08-28 03:42:21
使用bash
while true; do
IFS= read -r line1
IFS= read -r line2
IFS= read -r line3
status=$?
printf "%s, %s\n%s\n" "$line1" "$line2" "$line3"
(( status != 0 )) && break
done < file
和awk
awk '
/java version/ || /Permission denied/ {printf ", %s\n\n", $0; next}
{printf "%s", $0}
' file
# which can also be written as
awk '{
format = (/java version/ || /Permission denied/) ? ", %s\n\n" : "%s"
printf format, $0
}' file
或者,通过操作输入/输出字段和记录分隔符
awk '
BEGIN {FS="\n"; RS=""; OFS=", "; ORS="\n\n"}
{$1 = $1; print}
' file
# or, more tersely
awk '{$1=$1}1' FS='\n' RS='' OFS=', ' ORS='\n\n' file
https://stackoverflow.com/questions/52044227
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