blocks|key|1644724|text|您可以通过使用从0到31的范围迭代字符串来创建字符串列表，并在每次迭代后添加到新的索引31，然后只需迭代新列表并打印结果：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1644725|+my_string+=+"this+is+my+really+long+string,+really+really,+string,+
really+really,+string,+really+really,+string,+really+really+long..."

for+elem+in+[my_string[i:i%2B31]+for+i+in+range(0,+len(my_string),+31)]:
++++print+elem|code-block|syntax|javascript|1644726|您还可以阅读有关isslice的文章，它可以提供更优雅的解决方案。|offset|length|1644727|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/dev/library/itertools.html#itertools.islice^0|0|0|8|7|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

You can create a list of strings by iterating over the string using range from 0 to 31 and after each iteration add to the new index 31, Then just iterate the new list and print the result:

<pre><code> my_string = "this is my really long string, really really, string, 
really really, string, really really, string, really really long..."

for elem in [my_string[i:i+31] for i in range(0, len(my_string), 31)]:
 print elem
</code></pre>

You can also read about <a href="https://docs.python.org/dev/library/itertools.html#itertools.islice" rel="nofollow">isslice</a> which can supply a more elegant solution.

blocks|key|1644733|text|将元素分组为n长度组的另一种常见方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1644734|for+custom_string+in+map(''.join,+zip(*[iter(really_long_string)]*32)):
++++print+hex(custom_string)|code-block|syntax|javascript|1644735|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another common way of grouping elements into n-length groups:

<pre><code>for custom_string in map(''.join, zip(*[iter(really_long_string)]*32)):
 print hex(custom_string)
</code></pre>

blocks|key|1644729|text|您可以懒惰地将可迭代程序分成块。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1644730|from+itertools+import+takewhile,+count,+islice


def+slice_iterable(iterable,+chunk):
++++_it+=+iter(iterable)
++++return+takewhile(bool,+(tuple(islice(_it,+chunk))+for+_+in+count(0)))


for+chunk+in+slice_iterable(it,+32):
++++print(chunk)|code-block|syntax|javascript|1644731|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can lazily slice the iterable into chunks

<pre><code>from itertools import takewhile, count, islice


def slice_iterable(iterable, chunk):
 _it = iter(iterable)
 return takewhile(bool, (tuple(islice(_it, chunk)) for _ in count(0)))


for chunk in slice_iterable(it, 32):
 print(chunk)
</code></pre>

blocks|key|1734173|text|for+i+in+range(0,+len(string_value),+32):+
++++print(string_value[i:i%2B32])|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1734174|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>for i in range(0, len(string_value), 32): 
 print(string_value[i:i+32])
</code></pre>

I want to be able to print on the screen a large amount of data, but I want to make sure each line has only 32 characters, the string contains binary data and I want to be able to do do 32 bytes on one line but I dont know how to do this with python loops.

<pre><code>for c in string_value:
 print( hex(c) )
</code></pre>

The above works, but only prints one character per line as it should. How can I iterate more than 1 character per for loop. I searched online but couldnt figure out a way.

Any help would be greatly appreciated. Thanks in advance

Print string 32 characters at a time in Python

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我希望能够在屏幕上打印大量数据，但我希望确保每行只有32个字符，字符串包含二进制数据，我希望能够在一行上打印32个字节，但我不知道如何使用python循环做到这一点。for c in string_value:   print( hex(c) )上面的代码行得通，但每行只打印一个字符。如何在每个for循环中迭代超过1个...

问在Python中一次打印32个字符的字符串
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