在AEM 6.2中创建自定义路径浏览器谓词
在AEM 6.2中创建自定义路径浏览器谓词
提问于 2017-01-26 15:21:45
我正在尝试为pathbrowser实现自定义的OSGI服务谓词。如果有人知道这段代码出了什么问题:)下面有个例外。可能是@Component或依赖项
<path jcr:primaryType="nt:unstructured"
sling:resourceType="granite/ui/components/foundation/form/pathbrowser"
fieldDescription="List item link"
fieldLabel="List Item link"
name="./path"
predicate="predicate"
rootPath="/content">
</path>谓词实现：
import org.apache.commons.collections.Predicate;
import org.apache.felix.scr.annotations.Component;
import org.apache.felix.scr.annotations.Properties;
import org.apache.felix.scr.annotations.Property;
import org.apache.felix.scr.annotations.Service;
import org.apache.sling.api.resource.Resource;
import com.day.cq.commons.predicate.AbstractResourcePredicate;
import com.day.cq.wcm.api.Page;
@Component(label = "Content-page Predicate", description = "This predicate is used to restricted to allow selection of pages that have template content-page")
@Service(value = Predicate.class)
@Properties({
@Property(label = "Predicate Name", name = "predicate.name", value = "predicate", propertyPrivate = true) })
public class ContentPagePredicate extends AbstractResourcePredicate {
private static final String CQ_TEMPLATE_CONTENT = "/conf/xxx-lab/settings/wcm/templates/content-page";
@Override
public boolean evaluate(Resource resource) {
if (null != resource) {
if (!resource.getResourceType().equals("cq:Page")) {
return false;
}
Page page = resource.adaptTo(Page.class);
return page.getTemplate().getName().equals(CQ_TEMPLATE_CONTENT);
}
return false;
}
}Maven构建输出：
[ERROR] Failed to execute goal org.apache.felix:maven-scr-plugin:1.20.0:scr (generate-scr-scrdescriptor) on project SomethingDemo.core: Execution generate-scr-scrdescriptor of goal org.apache.felix:maven-scr-plugin:1.20.0:scr failed: An API incompatibility was encountered while executing org.apache.felix:maven-scr-plugin:1.20.0:scr: java.lang.VerifyError: Constructor must call super() or this() before return
[ERROR] Exception Details:
[ERROR] Location:
[ERROR] com/day/cq/commons/predicate/AbstractNodePredicate.<init>()V @1: return
[ERROR] Reason:
[ERROR] Error exists in the bytecode
[ERROR] Bytecode:
[ERROR] 0x0000000: 2ab1 Stack Overflow用户
发布于 2017-01-26 20:08:37
只要尝试实现org.apache.commons.collections.Predicate即可。
另外：resource.getResourceType().equals("cq:Page")永远不会是true，因为cq:Page是资源的jcr:pimaryType。page.getTemplate()在发布时不起作用：
public booean evaluate(Resource resource) {
if (null == resource) return false;
final ValueMap map = resource.getValueMap();
return "cq:Page".equals(map.get("jcr:primaryType", "")
&& CQ_TEMPLATE_CONTENT.equals(map.get("cq:template", "")
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/41868527
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