问使用C#从字符串中提取日期的正则表达式

EN

static void TestRegex()
{
    string s = "Web Application Developer in Acme Infosystem Mohali from 13 Nov 2014 to till present yii2 framework and Node JS.";
    string pattern = 
        @"(?x)
        (3[01]|2[0-9]|1[0-9]|0[1-9])                    # Matches a day
        \s+                                             # Matches spaces
        (Jan|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)   # Matches month
        \s+                                             # Matches space
        [0-9]{4}                                        # Matches year";
    string firstDate = null, secondDate = null;
    var firstMatch = Regex.Match(s, pattern);
    if (firstMatch.Success)
    {
        firstDate = firstMatch.Value;
        // If first date is found, try to match second date
        var secondMatch = firstMatch.NextMatch();
        if (secondMatch.Success)
        {
            secondDate = secondMatch.Value;
        }
        else
        {
            secondDate = Regex.IsMatch(s, "to till present") ? "till present" : null;
        }
    }
    else
    {
        Console.WriteLine("First date not found.");
    }
    Console.WriteLine($"First date: '{firstDate}', secondDate: '{secondDate}'");
}

string str = "Web Application Developer in Acme Infosystem Mohali from 13 Nov 2014 to till present yii2 framework and Node JS. ";

// (?<=from )  -- find a string after "from"
// \d{1,2} [A-Z][a-z]+ \d{4}   -- 1-2 digits, the month (capitalized), 4-digit year
// to  -- include the "to"
// (till present|\d{1,2} [A-Z][a-z]+ \d{4})"  -- "till present" OR another date
// -- The space characters in the regex are important, too.
string rx = @"(?<=from )\d{1,2} [A-Z][a-z]+ \d{4} to (till present|\d{1,2} [A-Z][a-z]+ \d{4})";

System.Text.RegularExpressions.Regex ptrn = new System.Text.RegularExpressions.Regex(rx);
System.Text.RegularExpressions.Match match = ptrn.Match(str);
if (match.Success)
    Console.WriteLine(match.Value);
else
    Console.WriteLine("No match found");