我正在尝试构建一个按日期范围显示事件的表。它与下面的代码一起工作。我的下一步是分页,边走边学。从我读到的所有内容中,我必须获得行数,以确定是否有足够的行数来开始“下一页”以进入下一步。
我被这一步给难住了。看起来我的
$row_count = sqlsrv_num_rows( $stmt);
echo 'numRows: ',$row_count;
不会返回任何内容。
numRows:‘这是空的’
<head>
<title>Paginate</title>
</head>
<body>
<form method='get'>
<?PHP
$sql = "Select I.IncidentNumber, o.CaseCode , O.CaseDescription, V.HomeAddress
From tblIncident I
left join
tblIncidentType O
on O.IncidentNumber=I.IncidentNumber
left join
tblIncidentCustomer V
on V.IncidentNumber=I.IncidentNumber
Where IncidentDate between '01/01/2017' and '01/02/2017'
order by I.IncidentNumber";
$stmt = sqlsrv_query( $conn, $sql);
if( $stmt === false ) {
die( print_r( sqlsrv_errors(), true)) ;
}
/**
* Put resules in a table
*/
$stmt = sqlsrv_query($conn,$sql);
$row_count = sqlsrv_num_rows( $stmt);
echo 'numRows: ',$row_count;
echo "<table border='5' column width='700'><tr><th><center>Incident Number</center></th><th><center>CaseCode</center></th><th><center>Case Description</center></th><th><center>Home Address</center></th></><th></></tr>";
while( $row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC) )
{
echo "<tr>";
echo "<td><center>" . $row['IncidentNumber']. "</center></td>";
echo "<td><center>" . $row['CaseCode']."</center></td>";
echo "<td><center>" . $row['CaseDescription']."</center></td>";
echo "<td><center>" . $row['HomeAddress']."</center></td>";
}
echo "</table>";
?>
</body>
</html>
我提前道歉,但我正在努力学习,但这让我感到困惑。我确信有一个带有答案的副本,但我在其他QAs中尝试的所有内容都不起作用。如果您能提供任何帮助,我们将不胜感激。
发布于 2018-06-25 00:55:42
从documentation:Function sqlsrv_num_rows()
需要客户端游标、静态游标或键集游标,如果使用前向游标或动态游标(默认游标为前向游标),则返回false。你可以试着这样做:
...
$stmt = sqlsrv_query($conn, $sql, array(), array("Scrollable" => 'static'));
if( $stmt === false ) {
echo "Error (sqlsrv_query): ".print_r(sqlsrv_errors(), true);
exit;
}
$row_count = sqlsrv_num_rows($stmt);
if ($row_count === false) {
echo "Error (sqlsrv_num_rows)";
exit;
}
...
发布于 2018-06-24 22:45:51
我觉得应该是"O.CaseCode“而不是"o.CaseCode”?
https://stackoverflow.com/questions/51010873
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