blocks|key|2591469|text|在这里，您已经从userName中删除了第一个字符，所以在倒数第二行时，您不需要再删除它。对于歌曲Verse，您需要删除其中的"(NAME)“，所以在这里您可以使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2591470|songVerse+=+songVerse.replace("(NAME)","");
songVerse+=+songVerse%2BuserName;|code-block|syntax|javascript|2591471|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

here you removed first character already from userName, so at the second last line you again don't need to remove it.
and for the song Verse, you need to remove "(NAME)" from it, so here you can use

<pre><code>songVerse = songVerse.replace("(NAME)","");
songVerse = songVerse+userName;
</code></pre>

blocks|key|80779|text|方法substring(int+begin，int+end)让我们从初始字符串开始选择/创建一个子字符串，指示该子字符串应该开始、结束或仅从其开始的字符数。没有其他变体可以编辑子字符串，而它不会成为新生成的字符串的一部分(在您的示例中为“string+songVerse”)。object.replace()方法应该将所指示的“文本”(在本例中是“(Name)”)更改为您想要插入的任何内容，而不是独立于“Text”之前或之后的字符的数量或类型。Nicholas+K提出的变体是正确的，应该可以工作，或者您可以尝试其较短的版本，但结果将是相同的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|80780|public+class+NameSong++{
++++public+static+void+main+(String+[]+args)+{
++++++++Scanner+scnr+=+new+Scanner(System.in);
++++++++String+userName;
++++++++String+songVerse;

++++++++userName+=+scnr.nextLine();
++++++++songVerse+=+scnr.nextLine();
++++++++songVerse+=+songVerse.replace("(Name)",+userName.substring(1));

++++++System.out.println(songVerse);
+++}

}|code-block|syntax|javascript|80781|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The method substring(int begin, int end) let hoose/create a substring from the initial String indicating the numbers of chars from which the substring should begin and end or begin only. There are no other variants to edit a substring, while it will not become a part of a freshly made string (“String songVerse” in your case). The object.replace() method should change the indicated “Text” (in your case it’s a “(Name)”) onto anything that you’d like to be inserted instead of it independently on the quantity or type of the chars before or after the “Text”. The variant proposed by Nicholas K is correct and should work or you can try its shorter version, however the result will be the same:

<pre><code>public class NameSong {
 public static void main (String [] args) {
 Scanner scnr = new Scanner(System.in);
 String userName;
 String songVerse;

 userName = scnr.nextLine();
 songVerse = scnr.nextLine();
 songVerse = songVerse.replace("(Name)", userName.substring(1));

 System.out.println(songVerse);
 }

}
</code></pre>

blocks|key|2591564|text|代码的问题在于，您没有尝试解决问题中描述的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2591565|尝试执行以下步骤：|2591566|2591567|设计一个用英语编写的步骤列表来解决问题；注意细节。|ordered-list-item|2591568|手动运行步骤1中的步骤列表。|2591569|将步骤1中的步骤转换为代码。|2591570|2591571|以下是一些提示：|2591572|2591573|您将一次读取一行歌词。|unordered-list-item|2591574|某些行有替换，而其他行没有。|2591575|您将收到一次作为输入的名称；生成一次名称替换值，并在每次执行replacement.|2591576|时使用它|2591577|你的代码太糟糕了。这里有一些关于“注意细节”的更多信息。|2591578|2591579|您的代码中没有循环；这将读取一行歌词并执行一次替换。数一数歌词中的行数。如果行数大于1，那么你的技术肯定会失败。|2591580|如果你的代码中有一个循环，但决定不在你的代码中包含它，请停止在你的问题中撒谎。我们无法帮助您修复您假装不存在的代码。|2591581|在一个正常的世界中，用于替换的名称将恰好出现一次。读一遍。|2591582|要替换字符串中的(Name)，必须先在字符串中查找(Name)。|2591583|2591584|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1D|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|1E|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|1F|8|@]|9|@]|A|$]]|$1|H|3|I|5|G|7|1G|8|@]|9|@]|A|$]]|$1|J|3|K|5|G|7|1H|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|1J|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|1L|8|@]|9|@]|A|$]]|$1|S|3|T|5|R|7|1M|8|@]|9|@]|A|$]]|$1|U|3|V|5|R|7|1N|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1O|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1P|8|@]|9|@]|A|$]]|$1|10|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|11|3|12|5|R|7|1R|8|@]|9|@]|A|$]]|$1|13|3|14|5|R|7|1S|8|@]|9|@]|A|$]]|$1|15|3|16|5|R|7|1T|8|@]|9|@]|A|$]]|$1|17|3|18|5|R|7|1U|8|@]|9|@]|A|$]]|$1|19|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]|$1|1A|3|-4|5|6|7|1W|8|@]|9|@]|A|$]]]|1B|$]]

The problem with your code is that you are not attempting to solve the problem that you described in your question.

Try following these steps:

<ol>
<li>Devise a list of steps written in English to solve the problem; pay attention to details.</li>
<li>Run the list of steps in step 1 by hand.</li>
<li>Convert the steps in step 1 to code.</li>
</ol>

Here are some hints:

<ul>
<li>You will be reading the lyrics one line at a time.</li>
<li>Some lines have a replacement and others do not.</li>
<li>You will receive the Name as input one time; generate the name replacement value one time and use it each time you perform a replacement.</li>
</ul>

Your code is terrible.
Here is some more about "Pay attention to details" 

<ul>
<li>You do not have a loop in your code;
this will read one line of lyrics and perform one substitution.
Count the number of lines in the lyrics.
If the number of lines is greater than one,
then your technique is guaranteed to fail.</li>
<li>If you have a loop in your code but decided not to include it in your code,
stop lying in your questions.
We can not help you fix code that you pretend does not exist.</li>
<li>In a sane world,
the name to use for the substitutions will appear exactly one time.
Read it one time.</li>
<li>In order to replace (Name) in a string, you must first find (Name) in a string.</li>
</ul>

blocks|key|2591586|text|这就是你要的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2591587|++userName+=+scnr.nextLine();
++userName+=+userName.substring(1);+//+Remove+first+character

++songVerse+=+scnr.nextLine();

++//+Modify+songVerse+to+replace+(Name)+with+userName+without+first+character

++++songVerse+=+songVerse.replace("(Name)",+userName.substring(0));

++System.out.println(songVerse);|code-block|syntax|javascript|2591588|}}|2591589|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Here you go.

<pre><code> userName = scnr.nextLine();
 userName = userName.substring(1); // Remove first character

 songVerse = scnr.nextLine();

 // Modify songVerse to replace (Name) with userName without first character

 songVerse = songVerse.replace("(Name)", userName.substring(0));

 System.out.println(songVerse);
</code></pre>

}
}

blocks|key|2803734|text|这很简单|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2803735|import+java.util.Scanner;

public+class+NameSong+{
++public+static+void+main+(String+[]+args)+{
++Scanner+scnr+=+new+Scanner(System.in);
++String+userName;
++String+songVerse;

++userName+=+scnr.nextLine();
++userName+=+userName.substring(1);+//+Remove+first+character

++songVerse+=+scnr.nextLine();

++//+Modify+songVerse+to+replace+(Name)+with+userName+without+first+character
+++songVerse+=+songVerse.replace("(Name)",+userName);
++/*+Your+solution+goes+here++*/

++System.out.println(songVerse);
++}
}|code-block|syntax|javascript|2803736|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is pretty easy

<pre><code>import java.util.Scanner;

public class NameSong {
 public static void main (String [] args) {
 Scanner scnr = new Scanner(System.in);
 String userName;
 String songVerse;

 userName = scnr.nextLine();
 userName = userName.substring(1); // Remove first character

 songVerse = scnr.nextLine();

 // Modify songVerse to replace (Name) with userName without first character
 songVerse = songVerse.replace("(Name)", userName);
 /* Your solution goes here */

 System.out.println(songVerse);
 }
}
</code></pre>

I'm not sure where I am going wrong with this particular code. Could someone please lend me some guidance to this? 

Here is my question as well as what I have attempted to have as an outcome.

Modify songVerse to play "The Name Game" (OxfordDictionaries.com), by replacing "(Name)" with userName but without the first letter. 

Ex: If userName = "Katie" and songVerse = "Banana-fana fo-f(Name)!", the program prints: 
Banana-fana fo-fatie!
Ex: If userName = "Katie" and songVerse = "Fee fi mo-m(Name)", the program prints: 
Fee fi mo-matie
Note: You may assume songVerse will always contain the substring "(Name)". 

Code that I tried this last time...and no matter what I put in I keep getting the same results. I've tried different scenarios of the "userName.substring()" and still have the same outcome.

<pre><code>import java.util.Scanner;

public class NameSong {
 public static void main (String [] args) {
 Scanner scnr = new Scanner(System.in);
 String userName;
 String songVerse;

 userName = scnr.nextLine();
 userName = userName.substring(1); // Remove first character

 songVerse = scnr.nextLine();

 // Modify songVerse to replace (Name) with userName without first character

 songVerse = songVerse + userName.substring(1 , userName.length()); // this is where my problem is.

 System.out.println(songVerse);
 }
}
</code></pre>

<blockquote>
 1 test passed
 
 All tests passed
</blockquote>

<pre><code>Run
Testing Katie and Banana-fana fo-f(Name)!
Output differs. See highlights below.
Your output
Banana-fana fo-f(Name)!tie
Expected output
Banana-fana fo-fatie!
Testing Walter and Banana-fana fo-f(Name)!
Output differs. See highlights below.
Your output
Banana-fana fo-f(Name)!lter
Expected output
Banana-fana fo-falter!
Testing Katie and Fee fi mo-m(Name)
Output differs. See highlights below.
Your output
Fee fi mo-m(Name)tie
Expected output
Fee fi mo-matie
</code></pre>

I need some guidance on the substring function in JAVA

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我不确定我在这个特定代码中哪里出了问题。有人能给我一些指导吗？这是我的问题，以及我试图得到的结果。修改songVerse来玩“名字游戏”(OxfordDictionaries.com)，将"( Name )“替换为userName，但不带第一个字母。例如:如果userName = "Katie“和songVerse =...

问我需要一些关于JAVA中子字符串函数的指导
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