创建经过消毒的字符串类型时的对称相等(使用scala.Proxy)
创建经过消毒的字符串类型时的对称相等(使用scala.Proxy)
提问于 2017-01-18 05:39:14
我有一个scala (2.10.4)应用程序，其中电子邮件地址被大量传递，我想实现一个在IO调用的抽象来“清理”已经验证的电子邮件地址。
使用scala.Proxy几乎就是我想要的，但是我遇到了不对称相等的问题。
class SanitizedEmailAddress(s: String) extends Proxy with Ordered[SanitizedEmailAddress] {
val self: String = s.toLowerCase.trim
def compare(that: SanitizedEmailAddress) = self compareTo that.self
}
object SanitizedEmailAddress {
def apply(s: String) = new SanitizedEmailAddress(s)
implicit def sanitize(s: String): SanitizedEmailAddress = new SanitizedEmailAddress(s)
implicit def underlying(e: SanitizedEmailAddress): String = e.self
}我想要一份
val sanitizedEmail = SanitizedEmailAddress("Blah@Blah.com")
val expected = "blah@blah.com"
assert(sanitizedEmail == expected) // => true
assert(expected == sanitizedEmail) // => true, but this currently returns false :(或者具有类似功能的东西。有什么不麻烦的方法可以做到这一点吗？
assert(sanitizedEmail.self == expected) // => true (but pretty bad, and someone will forget)
// can have a custom equality method and use the "pimp-my-lib" pattern on strings, but then we have to remember to use that method every time谢谢你的帮助。
回答 3
Stack Overflow用户
发布于 2017-02-07 19:59:23
我不认为这是可能的，对不起。
我也不确定这样做是不是对的。如果String真的等于SanitizedEmailAddress，那么SanitizedEmailAddress包装器实际上表示什么？
我认为更一致的做法是让String不能与SanitizedEmailAddress相提并论，并要求用户在比较输入之前对其进行“消毒”。
Stack Overflow用户
发布于 2017-02-08 03:13:16
您希望使用标记特征来表示符合的字符串。
接受Email字符串的函数知道该字符串是正确的。
如果将普通字符串与Email字符串进行比较，则它也必须是正确的。
package object email {
type Tagged[U] = { type Tag = U }
type @@[T, U] = T with Tagged[U]
def smartly[A](s: String): String @@ A = Email(s).asInstanceOf[String @@ A]
}
package email {
trait Email extends Any
object Email {
def apply(s: String) = s.toLowerCase.trim
}
object Test extends App {
def f(ok: String @@ Email) = {
assert(ok.forall(c => !c.isLetter || c.isLower))
}
val x = smartly[Email]("Joe@ACME.com")
println(x)
f(x)
assert("joe@acme.com" == x)
/*
f("Junk@Yahoo.com") // DNC
email.scala:22: error: type mismatch;
found : String("Junk@Yahoo.com")
required: email.@@[String,email.Email]
(which expands to) String with AnyRef{type Tag = email.Email}
f("Junk@Yahoo.com")
^
one error found
*/
}
} Stack Overflow用户
发布于 2017-02-13 03:55:13
如何保持所有的电子邮件类型为字符串，并隐式地拉皮条‘清理’信息：
object SanitizedEmailAddress {
def apply(s: String): String = synchronized {
val verified = s.toLowerCase.trim
sanitized.update(verified, true)
verified
}
def isSanitized(s: String): Boolean = synchronized {
sanitized.contains(s)
}
private val sanitized = scala.collection.mutable.WeakHashMap.empty[String, Boolean]
}
implicit class emailOps(val email: String) extends AnyVal {
def isSanitized: Boolean = SanitizedEmailAddress.isSanitized(email)
}现在：
val sanitizedEmail = SanitizedEmailAddress("Blah@Blah.com")
val expected = "blah@blah.com"
assert(sanitizedEmail == expected) // => true
assert(expected == sanitizedEmail) // => true
assert(sanitizedEmail.isSanitized == true) // => true
assert("blah@blah.com".isSanitized == true) // => true
assert("Blah@Blah.com".isSanitized == false) // => true页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/41707483
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