blocks|key|1322791|text|是的，language+spec定义"2“是结果。如果VM使用不同的方式，那么它就不符合规范。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1322792|大多数编译器都会抱怨这个问题。例如，Eclipse将声明返回块永远不会被执行，但这是错误的。|1322793|编写这样的代码是非常糟糕的做法，千万不要这样做:)|1322794|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/specs/jls/se8/html/jls-14.html#jls-14.20.2^0|3|D|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|U|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]]]

Yes, the <a href="https://docs.oracle.com/javase/specs/jls/se8/html/jls-14.html#jls-14.20.2" rel="noreferrer">language spec</a> defines that "2" is the result. If a VM does it differently, it's not spec-compliant.

Most compilers will complain about it. Eclipse, for example, will claim that the return block will never be executed, but it's wrong.

It's shockingly bad practice to write code like that, don't ever do it :)

blocks|key|1322849|text|将始终执行finally块，但在以下示例中除外：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1322850|String+test()+{
++++try+{
++++++++System.exit(0);
++++}+finally+{
++++++++return+"2";
++++}
}|code-block|syntax|javascript|1322851|在这种情况下，JVM将停止，而不执行finally块。|offset|length|style|CODE|1322852|因此，在您的示例中，返回值将为2。|1322853|entityMap^0|0|0|I|7|0|F|1|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@$I|W|J|X|K|L]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

The finally block will always be executed except in the following example:

<pre><code>String test() {
 try {
 System.exit(0);
 } finally {
 return "2";
 }
}
</code></pre>

In this case, the JVM will stop, without executing the <code>finally</code> block.

So in your example, the return value will be <code>2</code>.

blocks|key|1107798|text|你可以参考下面的链接。我希望它能提供所有细节：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1107799|http://www.programmerinterview.com/index.php/java-questions/will-finally-run-after-return/|offset|length|1107800|它说，最终块将始终执行，即使try或catch块有返回语句。如果finally块也有return语句，那么这将覆盖try或catch块中的return语句，在这种情况下，try/catch中抛出的任何异常都将被丢弃(错误的方法)。|1107801|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|2I|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@$D|Q|E|R|1|S]]|A|$]]|$1|F|3|G|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|U|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|C]]]]

You can refer the below link. I hope it will provide all details:

<a href="http://www.programmerinterview.com/index.php/java-questions/will-finally-run-after-return/" rel="nofollow noreferrer">http://www.programmerinterview.com/index.php/java-questions/will-finally-run-after-return/</a>

It says finally block will always executes even try or catch block has return statement. And if finally block also has return statement then this will override the return statement which is inside try or catch block and in this case any exception thrown in try/catch will be discarded (bad approach).

blocks|key|1107849|text|上面的答案总结得很好，只想在这里再补充一点。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1107850|private+static+int+divide(int+a+,+int+b){
++++try{
++++++++return++a/b;
++++}finally{
++++++++System.out.println("In+finally");
++++++++return+1;
++++}
}|code-block|syntax|javascript|1107851|如果我们传递1,0，那么上面的方法将抑制它抛出的异常，并只返回结果。已经说过，上面的代码不应该在生产环境中使用。|1107852|++private+static+int+divide(int+a+,+int+b){
++++++++int+result+=+0;
++++++++try{
++++++++++++result+=+++a/b;
++++++++}finally{
++++++++++++System.out.println("In+finally");
++++++++++++result+=++1;
++++++++}

++++++++return+result;
++++}|1107853|在finally块之后使用return语句将导致|1107854|Exception+in+thread+"main"+java.lang.ArithmeticException:+/+by+zero|1107855|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Above answer's is very well summarized just want to add one more point here.

<pre><code>private static int divide(int a , int b){
 try{
 return a/b;
 }finally{
 System.out.println("In finally");
 return 1;
 }
}
</code></pre>

If we pass the 1,0 then the above method will suppress the exception thrown by it and just return the result.
Been said, the above code should not be used in production environment.

<pre><code> private static int divide(int a , int b){
 int result = 0;
 try{
 result = a/b;
 }finally{
 System.out.println("In finally");
 result = 1;
 }

 return result;
 }
</code></pre>

using the return statement after the finally block will result in 

<pre><code>Exception in thread "main" java.lang.ArithmeticException: / by zero
</code></pre>

Given this code:

<pre><code>String test() {
 try {
 return "1";
 } finally {
 return "2";
 }
}
</code></pre>

Do the language specifications define the return value of a call to <code>test()</code>? In other words: Is it always the same in every JVM? 

In the Sun JVM the return value is <code>2</code>, but I want to be sure, that this is not VM-dependant.

Multiple returns: Which one sets the final return value?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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给定以下代码：String test() {    try {        return "1";    } finally {        return "2";    }}语言规范是否定义了调用test()的返回值？换句话说:它在每个JVM中都是一样的吗？在Sun JVM中，返回值是2，但我希望确保这不是依赖于...

问多个返回:哪一个设置了最终的返回值？
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问多个返回:哪一个设置了最终的返回值？EN