blocks|key|4031148|text|这些数字看起来很像数组的索引。如果是这样的话，你可以把它们全部删除，然后把整个对象变成一个数组。所以你会得到一个数组的数组。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4031149|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Those numbers seem lot like indexes of an array. If that's so you can just delete all of them and make the whole object an array. So you will get an array of arrays.

blocks|key|4031167|text|解决这个问题的方法是通过以下方式编写转换JSON字符串的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4031168|{
++++"object":+{
++++++++"a1":+[{...}],
++++++++"a2":+[{...}],
++++++++"a3":+[{...}],
++++++++"a4":+[{...}],
++++++++"a5":+[{...}],
++++++++"a6":+[{...}],
++++++++"a7":+[{...}]
++++}
}|code-block|syntax|javascript|4031169|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The way to solve the problem is to make the code that converts your JSON string in the following way:

<pre><code>{
 "object": {
 "a1": [{...}],
 "a2": [{...}],
 "a3": [{...}],
 "a4": [{...}],
 "a5": [{...}],
 "a6": [{...}],
 "a7": [{...}]
 }
}
</code></pre>

blocks|key|4031199|text|我现在使用以下解决方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4031200|json.replace("\"1\"","\"one\"")
++++.replace("\"2\"","\"two\"")
++++.replace("\"3\"","\"three\"")
++++.replace("\"4\"","\"four\"")
++++.replace("\"5\"","\"five\"")
++++.replace("\"6\"","\"six\"")
++++.replace("\"7\"","\"seven\"");|code-block|syntax|javascript|4031201|编辑:这个解决方案确实有效，但它相当丑陋。@yegodm的解决方案效果要好得多！谢谢你这么做！|4031202|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I am using the following workaround now:

<pre><code>json.replace("\"1\"","\"one\"")
 .replace("\"2\"","\"two\"")
 .replace("\"3\"","\"three\"")
 .replace("\"4\"","\"four\"")
 .replace("\"5\"","\"five\"")
 .replace("\"6\"","\"six\"")
 .replace("\"7\"","\"seven\"");
</code></pre>

EDIT: This solution did work but it was pretty ugly. The solution from @yegodm works way better! Thank you for that!

blocks|key|4031261|text|下面是使用GSON反序列化JSON的方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4031262|public+static+void+main(String[]+args)+{
++++final+String+json+=+"{\n"+%2B
++++++++"++++\"object\":+{\n"+%2B
++++++++"++++++++\"1\":+[{+\"id\"+:+111+}],\n"+%2B
++++++++"++++++++\"2\":+[{+\"id\"+:+222+}],\n"+%2B
++++++++"++++++++\"3\":+[{+\"id\"+:+333+}]\n"+%2B
++++++++"++++}\n"+%2B
++++++++"}\n";
++++final+Gson+gson+=+new+GsonBuilder()
++++++++.create();
++++final+ObjectWrapper+value+=+gson.fromJson(json,+ObjectWrapper.class);

++++System.out.println(value.object);
++++System.out.println(value.object.keySet());
++++System.out.println(value.object.get(1));
}

//+This+is+top-most+object+we+want+to+deserialize+from+JSON
static+class+ObjectWrapper+{
++++//+Didn't+bother+about+proper+naming+while+it+is+better+to+give+a+meaningful+name+here
++++private+Map<Integer,+List<Element>>+object;
}

static+class+Element+{
++++//+Added+this+attribute+to+demonstrate+that+objects+within+array+are+properly+read
++++private+int+id;
++++@Override
++++public+String+toString()+{
++++++++return+"{id="+%2B+id+%2B+"}";
++++}
}|code-block|syntax|javascript|4031263|entityMap^0|5|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

This is how you can use <code>GSON</code> to deserialize your JSON:

<pre><code>public static void main(String[] args) {
 final String json = "{\n" +
 " \"object\": {\n" +
 " \"1\": [{ \"id\" : 111 }],\n" +
 " \"2\": [{ \"id\" : 222 }],\n" +
 " \"3\": [{ \"id\" : 333 }]\n" +
 " }\n" +
 "}\n";
 final Gson gson = new GsonBuilder()
 .create();
 final ObjectWrapper value = gson.fromJson(json, ObjectWrapper.class);

 System.out.println(value.object);
 System.out.println(value.object.keySet());
 System.out.println(value.object.get(1));
}

// This is top-most object we want to deserialize from JSON
static class ObjectWrapper {
 // Didn't bother about proper naming while it is better to give a meaningful name here
 private Map&lt;Integer, List&lt;Element&gt;&gt; object;
}

static class Element {
 // Added this attribute to demonstrate that objects within array are properly read
 private int id;
 @Override
 public String toString() {
 return "{id=" + id + "}";
 }
}
</code></pre>

first of all i know how to deserialize JSON Objects in general. The specific problem i've got is that i have a Json object which contains arrays named <code>"1", "2", "3"</code>, etc. but in Java i cannot declare the variable <code>ArrayList&lt;AnotherObject&gt; 1;</code> Is there a better way than replacing the numbers by hand?

Json (greatly reduced):

<pre><code>{
 "object": {
 "1": [{...}],
 "2": [{...}],
 "3": [{...}],
 "4": [{...}],
 "5": [{...}],
 "6": [{...}],
 "7": [{...}]
 }
}
</code></pre>

Thanks in advance

Java GSON deserialize JSON when name of object is an Integer

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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首先，我大体上知道如何反序列化JSON对象。我遇到的具体问题是，我有一个Json对象，其中包含名为"1", "2", "3"等的数组，但在Java语言中，我不能声明变量ArrayList<AnotherObject> 1;。有没有比手动替换数字更好的方法？Json (大大减少)：{ "object": { ...

问当对象名为整数时，Java GSON反序列化JSON
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