我的代码部分如下;
Dim Column1 As String
Worksheets("Graph").Activate
Column1 = Cells(1, "P").Value
Dim Column2 As String
Worksheets("Graph").Activate
Column2 = Cells(2, "P").Value
Cells.Find(What:=Column1).Activate
StartP3Column = ActiveCell.Column
Cells.Find(What:=Column2).Activate
StartP4Column = ActiveCell.Column
EndP3Column = StartP4Column - 1
Cells.Find(What:="End Column").Activate
StartEndColumn = ActiveCell.Column
EndP4Column = StartEndColumn - 1我正在尝试这样做,以便P1和P2中的值将确定在运行宏时选择哪些列。因此,在前两个Cell.Find(What:=)函数中,我希望" Column1“选择Column1变量(P1中的值)。
当我运行宏时,我得到错误“运行时错误:91.WITH block variable not set”,而当我调试时,问题出在Cells.Find(What:=Column1).Activate行
有什么想法吗?
发布于 2017-01-23 19:00:19
如果您在sheet Sheet1上搜索这些数据,则将运行以下命令:
Dim wsG As Worksheet
Dim wsS As Worksheet
Dim Rg As Range
Dim Column1 As String
Dim Column2 As String
Set wsG = ThisWorkbook.Sheets("Graph")
Set wsS = ThisWorkbook.Sheets("Sheet1")
wsG.Activate
Column1 = wsG.Cells(1, "P").Value
Column2 = wsG.Cells(2, "P").Value
Set Rg = wsS.Cells.Find(What:=Column1)
If Not Rg Is Nothing Then
StartP3Column = Rg.Column
Else
MsgBox Column1 & " not found in " & wsS.Name
End If
Set Rg = wsS.Cells.Find(What:=Column2)
If Not Rg Is Nothing Then
StartP4Column = Rg.Column
EndP3Column = Rg.Column - 1
Else
MsgBox Column2 & " not found in " & wsS.Name
End If
Set Rg = wsS.Cells.Find(What:="End Column")
If Not Rg Is Nothing Then
StartEndColumn = Rg.Column
EndP4Column = Rg.Column - 1
Else
MsgBox "End Column" & " not found in " & wsS.Name
End Ifhttps://stackoverflow.com/questions/41804284
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