我正在尝试将数据从数据库打印到html表。我希望我的表是这样的:
| username | studio APEX | studio CANVAS | studio ORBIT |
+----------+-------------+---------------+--------------+
| Aaron    |       x     |       x       |              |
| Adel     |             |               |       x      |
| John     |       x     |       x       |              |
| James    |       x     |       x       |              |
| Kate     |             |               |       x      |
| Peter    |       x     |               |              |其中演播室名称取自数据库。我得到的是查询:
$sql2 = '
            select
              p2.proc_leader as username,
                   max(case when studio = "APEX" then "x" else "" end) as APEX,
                   max(case when studio = "BASECAMP" then "x" else "" end) as BASECAMP,
                   max(case when studio = "CANVAS" then "x" else "" end) as CANVAS,
                   max(case when studio = "HORIZON" then "x" else "" end) as HORIZON,
                   max(case when studio = "LAUNCHPAD" then "x" else "" end) as LAUNCHPAD,
                   max(case when studio = "NEBULA" then "x" else "" end) as NEBULA,
                   max(case when studio = "ORBIT" then "x" else "" end) as ORBIT,
                   max(case when studio = "PALETTE" then "x" else "" end) as PALETTE,
                   max(case when studio = "SANDBOX" then "x" else "" end) as SANDBOX,
                   max(case when studio = "STELLAR" then "x" else "" end) as STELLAR,
                   max(case when studio = "THE CLIMB" then "x" else "" end) as THECLIMB,
                   max(case when studio = "TOONIGAMI" then "x" else "" end) as TOONIGAMI,
                   max(case when studio = "TREEHOUSE" then "x" else "" end) as TREEHOUSE
            from process p1
            left join (
              select *
              from proc_leader
              union all
              select *
              from proc_checker
              union all
              select *
              from proc_staff    
            ) p2 on p1.projectNo = p2.projectNo
            and p1.process = p2.process
            group by p2.proc_leader
';然后我尝试打印到html表:
 $query2 = mysqli_query($conn, $sql2);
  while ($data2 = mysqli_fetch_assoc($query2)) {
    $username = $data2['username'];
    $apex = $data2['APEX'];
    $basecamp = $data2['BASECAMP'];
    $canvas = $data2['CANVAS'];
    $horizon = $data2['HORIZON'];
    $launchpad = $data2['LAUNCHPAD'];
    $nebula = $data2['NEBULA'];
    $orbit = $data2['ORBIT'];
    $palette = $data2['PALETTE'];
    $sandbox = $data2['SANDBOX'];
    $stellar = $data2['STELLAR'];
    $theclimb = $data2['THECLIMB'];
    $toonigame = $data2['TOONIGAMI'];
    $treehouse = $data2['TREEHOUSE'];   
            $header =
                '<th>Username</th>
                <th>Studio'.$apex.'</th>
                <th>Studio'.$basecamp.'</th>
                <th>Studio'.$canvas.'</th>
                <th>Studio'.$horizon.'</th>
                <th>Studio'.$launchpad.'</th>
                <th>Studio'.$nebula.'</th>
                <th>Studio'.$orbit.'</th>
                <th>Studio'.$palette.'</th>
                <th>Studio'.$sandbox.'</th>
                <th>Studio'.$stellar.'</th>
                <th>Studio'.$theclimb.'</th>
                <th>Studio'.$toonigame.'</th>
                <th>Studio'.$treehouse.'</th>';
            //body
            $body = '';
                $row = '<td>' . htmlspecialchars($username) . '</td>';
                $body .= "<tr>$row</tr>";
            echo "<thead>$header</thead><tbody>$body</tbody>";      
}但它似乎不能像我希望的那样工作。下面是我的表格现在的样子:
| username | studiox     | studiox       | studio       |
+----------+-------------+---------------+--------------+
| Aaron    |             |               |              |
| username | studio      | studio        | studiox      |
| Adel     |             |               |              |
| username | studiox     | studiox       | studio       |
| John     |             |               |              |
| username | studiox     | studiox       | studio       |
| James    |             |               |              |
| username | studio      | studio        | studiox      |
| Kate     |             |               |              |
| username | studiox     | studio        | studio       |
| Peter    |             |               |              |问题出在哪里?我能正确打印表格吗?谢谢
发布于 2017-01-19 15:43:20
如果您想保留while循环:
$query2 = mysqli_query($conn, $sql2);
$header = '<tr><th>Username</th>
            <th>Studio APEX</th>
            <th>Studio BASECAMP</th>
            <th>Studio CANVAS</th>
            <th>Studio HORIZON</th>
            <th>Studio LAUNCHPAD</th>
            <th>Studio NEBULA</th>
            <th>Studio ORBIT</th>
            <th>Studio PALETTE</th>
            <th>Studio SANDBOX</th>
            <th>Studio STELLAR</th>
            <th>Studio THECLIMB</th>
            <th>Studio TOONIGAMI</th>
            <th>Studio TREEHOUSE</th></tr>';
$body = '';
while ($data2 = mysqli_fetch_assoc($query2)) {
    $username = $data2['username'];
    $apex = $data2['APEX'];
    $basecamp = $data2['BASECAMP'];
    $canvas = $data2['CANVAS'];
    $horizon = $data2['HORIZON'];
    $launchpad = $data2['LAUNCHPAD'];
    $nebula = $data2['NEBULA'];
    $orbit = $data2['ORBIT'];
    $palette = $data2['PALETTE'];
    $sandbox = $data2['SANDBOX'];
    $stellar = $data2['STELLAR'];
    $theclimb = $data2['THECLIMB'];
    $toonigame = $data2['TOONIGAMI'];
    $treehouse = $data2['TREEHOUSE'];
    $row = '<td>' . htmlspecialchars($username) . '</td>
                <td>' . $apex . '</td>
                <td>' . $basecamp . '</td>
                <td>' . $canvas . '</td>
                <td>' . $horizon . '</td>
                <td>' . $launchpad . '</td>
                <td>' . $nebula . '</td>
                <td>' . $orbit . '</td>
                <td>' . $palette . '</td>
                <td>' . $sandbox . '</td>
                <td>' . $stellar . '</td>
                <td>' . $tdeclimb . '</td>
                <td>' . $toonigame . '</td>
                <td>' . $treehouse . '</td>';
    $body .= '<tr>' . $row . '</tr>';
}
echo '<table><thead>' . $header . '</thead><tbody>' . $body . '</tbody></table>';只要确保不会循环错误的部分即可。在这种情况下,您只想在循环中构建表的主体。因此,在执行循环之前或之后构建头部,因此您只需执行一次,而不是在每次迭代中。
发布于 2017-01-19 15:22:23
问题是您在循环中制作表头,所以尝试这样做:
echo '<table>';
// This is table header    
echo '<tr> <th>Column Name 1</th> <th>Column Name 2</th> <th>Column Name 3</th></tr><tbody>';
// This is the table body
foreach( .. )
{
    echo '<tr>';
    echo '<td>'.$var.'<td>';
    echo '<td>'.$var.'<td>';
    ...
    echo '</tr>';
}
echo '</tbody></table>';发布于 2017-01-19 20:32:17
这里有一些需要考虑的事情--尽管我应该强调我不是PHP程序员……
<?php
$my_array = array(
    0 => 1,
    1 => 2,
    2 => 3,
    3 => 5,
    4 => 7
);
for($i=0;$i<10;$i++){
echo $i;
if(in_array($i,$my_array)){echo " yes <br>\n";} else {echo " no <br>\n";}
}
?>输出...
0 no
1 yes
2 yes
3 yes
4 no
5 yes
6 no
7 yes
8 no
9 no https://stackoverflow.com/questions/41735948
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