$select_pic = "SELECT pic.photo_link,od.* from orders as od inner join photo as pic ON pic.user_id = od.user_id WHERE od.id = '".$orderid."'";
$pic = $common->select_inner($select_pic);
foreach($pic as $photo){
}
我在$photo‘photo_link’中得到了图片;我想在点击下载按钮时下载图片,我该如何使用php或javascript来做到这一点。
<a download="<?php echo $photo['photo_link']; ?>" title="ImageName">
<img alt="ImageName" src="uploads/category/<?php echo $photo['photo_link']; ?>">
</a>
我试过了,但不起作用。
发布于 2017-12-15 14:45:41
标记中缺少href属性。
我已经检查了以下代码的工作情况:
<a href="" download="<?php echo $photo['photo_link']; ?>" title="ImageName">
<img alt="ImageName" src="uploads/category/<?php echo $photo['photo_link']; ?>">
</a>
请参阅以下链接以供参考:href image link download on click
发布于 2019-08-13 19:17:19
试试这段代码
<a href="uploads/category/<?php echo $photo['photo_link']; ?" download>
<button>Download</button>
</a>
https://stackoverflow.com/questions/47826392
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