带有Typescript设计错误的Mongoose模式
我有两个使用mongoose和typescript定义模式的问题。下面是我的代码：
import { Document, Schema, Model, model} from "mongoose";
export interface IApplication {
id: number;
name: string;
virtualProperty: string;
}
interface IApplicationModel extends Document, IApplication {} //Problem 1
let ApplicationSchema: Schema = new Schema({
id: { type: Number, required: true, index: true, unique: true},
name: { type: String, required: true, trim: true },
});
ApplicationSchema.virtual('virtualProperty').get(function () {
return `${this.id}-${this.name}/`; // Problem 2
});
export const IApplication: Model<IApplicationModel> = model<IApplicationModel>("Application", ApplicationSchema);首先：
本行中的
- 问题1
interface IApplicationModel extends Document, IApplication {}
打字稿告诉我：
error TS2320: Interface 'IApplicationModel' cannot simultaneously extend types 'Document' and 'IApplication'. Named property 'id' of types 'Document' and 'IApplication' are not identical.
那么如何更改id属性的定义呢？
- 问题2在内部函数中(
virtualProperty的getter)：
return `${this.id}-${this.name}/；//问题2
错误是：
error TS2683: 'this' implicitly has type 'any' because it does not have a type annotation.
如何定义this的类型
回答 2
Stack Overflow用户
发布于 2018-10-24 07:34:50
问题#1:由于IApplicationModel扩展了Document和IApplication接口，这两个接口声明了不同类型的id属性(分别为any和number )，因此TypeScript不知道IApplicationModel的id属性应该是any类型还是<代码>D9类型。您可以通过使用所需的类型重新声明IApplicationModel中的id属性来修复此问题。(为什么要声明一个单独的IApplication接口，而不是只声明用所有属性扩展Document的IApplicationModel？)
问题#2:只需向函数声明this特殊参数，如下所示。
import { Document, Schema, Model, model} from "mongoose";
export interface IApplication {
id: number;
name: string;
virtualProperty: string;
}
interface IApplicationModel extends Document, IApplication {
id: number;
}
let ApplicationSchema: Schema = new Schema({
id: { type: Number, required: true, index: true, unique: true},
name: { type: String, required: true, trim: true },
});
ApplicationSchema.virtual('virtualProperty').get(function (this: IApplicationModel) {
return `${this.id}-${this.name}/`;
});
export const IApplication: Model<IApplicationModel> = model<IApplicationModel>("Application", ApplicationSchema);Stack Overflow用户
发布于 2021-09-08 16:15:55
对于问题2:只需将this声明为any：.get(function (this: any) {});修复它
https://stackoverflow.com/questions/52947886
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