blocks|key|1118692|text|在Python语言和许多其他编程语言中，%7C就是bitwise-OR+operation。%7C=之于%7C，正如%2B=之于%2B，即操作和指定的组合。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1118693|所以var+%7C=+value是var+=+var+%7C+value的缩写。|1118694|一个常见的用例是合并两个集合：|1118695|>>>+a+=+{1,2};+a+%7C=+{3,4};+print(a)
{1,+2,+3,+4}|code-block|syntax|javascript|1118696|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Bitwise_operation^0|K|1|18|2|1C|1|1G|2|1K|1|N|K|0|0|2|C|F|H|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|6|7|1A|8|@$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|1F|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|1G|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

In Python, and many other programming languages, <code>|</code> is the <a href="http://en.wikipedia.org/wiki/Bitwise_operation" rel="nofollow noreferrer">bitwise-OR operation</a>. <code>|=</code> is to <code>|</code> as <code>+=</code> is to <code>+</code>, i.e. a combination of operation and asignment.
So <code>var |= value</code> is short for <code>var = var | value</code>.
A common use case is to merge two sets:
<pre class="lang-py prettyprint-override"><code>&gt;&gt;&gt; a = {1,2}; a |= {3,4}; print(a)
{1, 2, 3, 4}
</code></pre>

blocks|key|1118803|text|当与集合一起使用时，它执行联合操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1118804|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

When used with sets it performs union operation.

blocks|key|903993|text|它对赋值的左侧和右侧执行二进制逐位OR，然后将结果存储在左侧变量中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|903994|http://docs.python.org/reference/expressions.html#binary-bitwise-operations|offset|length|903995|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|23|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@$D|O|E|P|1|Q]]|A|$]]|$1|F|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|C]]]]

It performs a binary bitwise OR of the left-hand and right-hand sides of the assignment, then stores the result in the left-hand variable.

<a href="http://docs.python.org/reference/expressions.html#binary-bitwise-operations" rel="noreferrer">http://docs.python.org/reference/expressions.html#binary-bitwise-operations</a>

blocks|key|904080|text|它是按位或。假设我们有32+%7C=+10，图片32和10是二进制的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|904081|32+=+10+0000
10+=+00+1010|code-block|syntax|javascript|904082|现在，因为%7C是or，所以对这两个数字进行逐位or运算|904083|即1或0+-->+1，0或0+-->+0。顺着这条链继续下去|904084|10+0000+%7C+00+1010+=+10+1010.|904085|现在将二进制改为十进制，101010=+42。|904086|对于%7C=，请考虑已知的示例x+%2B=5。它的意思是x+=+x+%2B+5,，所以如果我们有x+%7C=+5，它就意味着x+=+x+bitwiseor+with+5。|904087|entityMap^0|B|8|0|0|0|0|0|0|D|5|O|A|16|6|1I|M|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|11|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|13|8|@]|D|@]|E|$]]|$1|S|3|T|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|U|3|-4|5|6|7|1D|8|@]|D|@]|E|$]]]|V|$]]

It's bitwise or.
Let's say we have <code>32 |= 10</code>, picture 32 and 10 is binary.

<pre><code>32 = 10 0000
10 = 00 1010
</code></pre>

Now because | is or, do a bitwise or on the two numbers

i.e 1 or 0 --> 1, 0 or 0 --> 0. Continue this down the chain

<pre><code>10 0000 | 00 1010 = 10 1010.
</code></pre>

Now change the binary into a decimal, 10 1010 = 42.

For |=, think of the known examples, <code>x +=5</code>. It means <code>x = x + 5,</code> therefore if we have <code>x |= 5</code>, it means <code>x = x bitwiseor with 5</code>.

blocks|key|1118946|text|在Python语言中，%7C=(ior)的工作方式类似于联合运算。例如，如果是x=5和x%7C=5，那么这两个值都将首先转换为二进制值，然后执行联合操作，我们得到答案5。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1118947|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

In Python,|=(ior) works like union operation.
like if x=5 and x|=5 then both the value will first convert in binary value then the union operation will perform and we get the answer 5.

blocks|key|1119013|text|给出一个用例(在花时间回答其他问题之后)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1119014|def+process(item):
+++return+bool(item)+#+imagine+some+sort+of+complex+processing+taking+place+above

def+any_success(data):+#+return+True+if+at+least+one+is+successful
++++at_least_one+=+False
++++for+item+in+data:
+++++++at_least_one+%7C=+process(item)
++++return+at_least_one

>>>+any_success([False,+False,+False])
False
>>>+any_success([True,+False,+False])
True
>>>+any_success([False,+True,+False])
True|code-block|syntax|javascript|1119015|基本上没有短路的any：如果您需要处理每个项目并记录至少一次成功等情况，可能会很有用。|offset|length|style|CODE|1119016|另请参阅this+answer中的警告|1119017|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/3929433/does-python-have-an-or-equals-function-like-in-ruby^0|0|0|8|3|0|4|B|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@$I|12|J|13|1|14]]|A|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

To give a use-case (after spending time with the other answers):

<pre><code>def process(item):
 return bool(item) # imagine some sort of complex processing taking place above

def any_success(data): # return True if at least one is successful
 at_least_one = False
 for item in data:
 at_least_one |= process(item)
 return at_least_one

&gt;&gt;&gt; any_success([False, False, False])
False
&gt;&gt;&gt; any_success([True, False, False])
True
&gt;&gt;&gt; any_success([False, True, False])
True
</code></pre>

Basically <code>any</code> without the short-circuiting: might be useful if you need to process every item and record at least one success etc. 

See also the caveats in <a href="https://stackoverflow.com/questions/3929433/does-python-have-an-or-equals-function-like-in-ruby">this answer</a>

Google won't let me search <code>|=</code> so I'm having trouble finding relevant documentation. Anybody know?

What does |= (ior) do in Python?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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谷歌不让我搜索|=，所以我很难找到相关文档。有人知道吗？

问|= (ior)在Python中做什么？
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回答 6

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