blocks|key|1337917|text|要舍入到最接近的0.10，可以乘以10，然后舍入(使用Math.round)，然后除以10|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1337918|entityMap^0|R|A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

to round to nearest 0.10 you can multiply by 10, then round (using <code>Math.round</code>), then divide by 10

blocks|key|1337954|text|乘以10，然后进行舍入，然后再除以10|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1337955|(Math.round(12.362+*+10)+/+10).toFixed(2)|code-block|syntax|javascript|1337956|另一种选择是：|1337957|Number(12.362.toFixed(1)).toFixed(2)|1337958|在你的代码中：|1337959|var+panel;+
if+(routeNodes.length+>+0+&&+(panel+=+document.getElementById('distance')))++++
{+++++++++++++++
++++panel.innerHTML+=+Number((dist/1609.344).toFixed(1)).toFixed(2)
++++++++++++++++++++%2B+"+miles+=+&#163;"+
++++++++++++++++++++%2B+Number((((dist/1609.344+-+1)+*+1.20)+%2B+2.80).toFixed(1)).toFixed(2);++
}|1337960|要声明最小值，请使用Math.max函数：|offset|length|style|CODE|1337961|var+a+=+10.1,+b+=+2.2,+c+=+3.5;
alert(Math.max(a,+2.8));+//+alerts+10.1+(a);
alert(Math.max(b,+2.8));+//+alerts+2.8+because+it+is+larger+than+b+(2.2);
alert(Math.max(c,+2.8));+//+alerts+3.5+(c);|1337962|entityMap^0|0|0|0|0|0|0|A|8|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|14|8|@$Q|15|R|16|S|T]]|9|@]|A|$]]|$1|U|3|V|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

Multiply by 10, then do your rounding, then divide by 10 again

<pre><code>(Math.round(12.362 * 10) / 10).toFixed(2)
</code></pre>

Another option is:

<pre><code>Number(12.362.toFixed(1)).toFixed(2)
</code></pre>

In your code:

<pre><code>var panel; 
if (routeNodes.length &gt; 0 &amp;&amp; (panel = document.getElementById('distance'))) 
{ 
 panel.innerHTML = Number((dist/1609.344).toFixed(1)).toFixed(2)
 + " miles = &amp;#163;" 
 + Number((((dist/1609.344 - 1) * 1.20) + 2.80).toFixed(1)).toFixed(2); 
}
</code></pre>

To declare a minimum, use the <code>Math.max</code> function:

<pre><code>var a = 10.1, b = 2.2, c = 3.5;
alert(Math.max(a, 2.8)); // alerts 10.1 (a);
alert(Math.max(b, 2.8)); // alerts 2.8 because it is larger than b (2.2);
alert(Math.max(c, 2.8)); // alerts 3.5 (c);
</code></pre>

blocks|key|1337982|text|var+miles+=+dist/1609.344
miles+=+Math.round(miles*10)/10;
miles+=+miles+<+2.80+?+2.80+:+miles;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1337983|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var miles = dist/1609.344
miles = Math.round(miles*10)/10;
miles = miles &lt; 2.80 ? 2.80 : miles;
</code></pre>

blocks|key|1122973|text|var+number+=+123.123;

Math.max(+Math.round(number+*+10)+/+10,+2.8+).toFixed(2);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1122974|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>var number = 123.123;

Math.max( Math.round(number * 10) / 10, 2.8 ).toFixed(2);
</code></pre>

blocks|key|1123009|text|四舍五入到最接近的第十位：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1123010|Math.max(x,+2.8).toFixed(1)+%2B+'0'|code-block|syntax|javascript|1123011|向上舍入：|1123012|Math.max(Math.ceil(x+*+10)+/+10,+2.8).toFixed(2)|1123013|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Round to the nearest tenth:

<pre><code>Math.max(x, 2.8).toFixed(1) + '0'
</code></pre>

Round up:

<pre><code>Math.max(Math.ceil(x * 10) / 10, 2.8).toFixed(2)
</code></pre>

blocks|key|1123044|text|这是google在js中四舍五入的热门文章。这个答案更多地是关于那个一般的问题，而不是这个特定的问题。作为广义舍入函数，您可以内联：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1123045|const+round+=+(num,+grainularity)+=>+Math.round(num+/+grainularity)+*+grainularity;|offset|length|style|CODE|1123046|在下面进行测试：|1123047|​|1123048|const+round+=+(num,+grainularity)+=>+Math.round(num+/+grainularity)+*+grainularity;


const+test+=+(num,+grain)+=>+{
++console.log(`Rounding+to+the+nearest+${grain}+for+${num}+->+${round(num,+grain)}`);
}


test(1.5,+1);
test(1.5,+0.1);
test(1.5,+0.5);
test(1.7,+0.5);
test(1.9,+0.5);
test(-1.9,+0.5);
test(-1.2345,+0.214);|code-block|syntax|javascript|1123049|1123050|entityMap^0|0|0|2B|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|U|8|@$D|V|E|W|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|X|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|Y|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|Z|8|@]|9|@]|A|$O|P]]|$1|Q|3|K|5|6|7|10|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|S|$]]

This is a top hit on google for rounding in js. This answer pertains more to that general question, than this specific one. As a generalized rounding function you can inline:

<code>const round = (num, grainularity) =&gt; Math.round(num / grainularity) * grainularity;</code>

Test it out below:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const round = (num, grainularity) =&gt; Math.round(num / grainularity) * grainularity;


const test = (num, grain) =&gt; {
 console.log(`Rounding to the nearest ${grain} for ${num} -&gt; ${round(num, grain)}`);
}


test(1.5, 1);
test(1.5, 0.1);
test(1.5, 0.5);
test(1.7, 0.5);
test(1.9, 0.5);
test(-1.9, 0.5);
test(-1.2345, 0.214);</code></pre>
</div>
</div>

I need to round up to the nearest 0.10 with a minimum of 2.80

<pre><code> var panel;
 if (routeNodes.length &gt; 0 &amp;&amp; (panel = document.getElementById('distance'))) 
 { 
 panel.innerHTML = (dist/1609.344).toFixed(2) + " miles = &amp;#163;" + (((dist/1609.344 - 1) * 1.20) + 2.80).toFixed(2); 
 }
</code></pre>

any help would be appreciated

round up nearest 0.10

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要向上舍入到最接近的0.10，最小值为2.80 var panel; if (routeNodes.length > 0 && (panel = document.getElementById('distance')))    {                 panel.innerHTML = (dist/16...

问向上舍入最接近的0.10
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