entityMap|blocks|key|fij73|text|您问的是一个关于数值比较的问题，所以正则表达式实际上与这个问题无关。你不需要“多个”|type|unstyled|depth|inlineStyleRanges|entityRanges|data|botdh|语句来完成此操作，或者：|6oe4j|if+(x+>=+0.001+&&+x+<=+0.009)+{
++//+something
}|code-block|syntax|javascript|7ifs0|你可以给自己写一个"between()“函数：|2kquk|function+between(x,+min,+max)+{
++return+x+>=+min+&&+x+<=+max;
}
//+...
if+(between(x,+0.001,+0.009))+{
++//+something
}^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|N|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|O|9|@]|A|@]|B|$]]|$2|E|4|F|6|G|8|P|9|@]|A|@]|B|$H|I]]|$2|J|4|K|6|7|8|Q|9|@]|A|@]|B|$]]|$2|L|4|M|6|G|8|R|9|@]|A|@]|B|$H|I]]]]

You're asking a question about numeric comparisons, so regular expressions really have nothing to do with the issue. You don't need "multiple <code>if</code>" statements to do it, either:

<pre><code>if (x &gt;= 0.001 &amp;&amp; x &lt;= 0.009) {
 // something
}
</code></pre>

You could write yourself a "between()" function:

<pre><code>function between(x, min, max) {
 return x &gt;= min &amp;&amp; x &lt;= max;
}
// ...
if (between(x, 0.001, 0.009)) {
 // something
}
</code></pre>

entityMap|blocks|key|fpk4h|text|这是一个只有一个比较的选项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1jrnt|//+return+true+if+in+range,+otherwise+false
function+inRange(x,+min,+max)+{
++++return+((x-min)*(x-max)+<=+0);
}

console.log(inRange(5,+1,+10));+++++//+true
console.log(inRange(-5,+1,+10));++++//+false
console.log(inRange(20,+1,+10));++++//+false|code-block|syntax|javascript^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|H|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|I|9|@]|A|@]|B|$F|G]]]]

Here is an option with only a single comparison.

<pre><code>// return true if in range, otherwise false
function inRange(x, min, max) {
 return ((x-min)*(x-max) &lt;= 0);
}

console.log(inRange(5, 1, 10)); // true
console.log(inRange(-5, 1, 10)); // false
console.log(inRange(20, 1, 10)); // false
</code></pre>

entityMap|blocks|key|7iu8f|text|如果你|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1r9ai|必须|22rbq|使用regexp+(实际上，您不应该这样做！)这将会起作用：|bdkrk|/%5E0\.00([1-8]\d*%7C90*)$/|code-block|syntax|javascript|1pf2l|应该是可行的，即|69ls2|以前什么都没有，|85e5d|紧跟其后的是|ajp1e|(注意:反斜杠转义|bf36q|字符)|b6vio|后跟1到8，以及任意数量的附加数字|c49tf|或9，后跟任意数量的零|9q16p|：后面没有其他内容^0|0|0|0|0|0|0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|11|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|12|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|13|9|@]|A|@]|B|$]]|$2|G|4|H|6|I|8|14|9|@]|A|@]|B|$J|K]]|$2|L|4|M|6|7|8|15|9|@]|A|@]|B|$]]|$2|N|4|O|6|7|8|16|9|@]|A|@]|B|$]]|$2|P|4|Q|6|7|8|17|9|@]|A|@]|B|$]]|$2|R|4|S|6|7|8|18|9|@]|A|@]|B|$]]|$2|T|4|U|6|7|8|19|9|@]|A|@]|B|$]]|$2|V|4|W|6|7|8|1A|9|@]|A|@]|B|$]]|$2|X|4|Y|6|7|8|1B|9|@]|A|@]|B|$]]|$2|Z|4|10|6|7|8|1C|9|@]|A|@]|B|$]]]]

If you must use a regexp (and really, you shouldn't!) this will work:

<pre><code>/^0\.00([1-8]\d*|90*)$/
</code></pre>

should work, i.e.

<ul>
<li><code>^</code> nothing before,</li>
<li>followed by <code>0.00</code> (nb: backslash escape for the <code>.</code> character)</li>
<li>followed by 1 through 8, and any number of additional digits</li>
<li>or 9, followed by any number of zeroes</li>
<li><code>$</code>: followed by nothing else</li>
</ul>

entityMap|blocks|key|es3ma|text|如果您已经在使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|a8a91|，您可以使用|335ne|功能：|bsvek|https://lodash.com/docs/4.17.15#inRange|f24hb|_.inRange(3,+2,+4);
//+=>+true

_.inRange(4,+8);
//+=>+true

_.inRange(4,+2);
//+=>+false

_.inRange(2,+2);
//+=>+false

_.inRange(1.2,+2);
//+=>+true

_.inRange(5.2,+4);
//+=>+false

_.inRange(-3,+-2,+-6);
//+=>+true|code-block|syntax|javascript^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|N|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|O|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|P|9|@]|A|@]|B|$]]|$2|G|4|H|6|7|8|Q|9|@]|A|@]|B|$]]|$2|I|4|J|6|K|8|R|9|@]|A|@]|B|$L|M]]]]

If you're already using <code>lodash</code>, you could use the <code>inRange()</code> function:
<a href="https://lodash.com/docs/4.17.15#inRange" rel="noreferrer">https://lodash.com/docs/4.17.15#inRange</a>

<pre class="lang-js prettyprint-override"><code>_.inRange(3, 2, 4);
// =&gt; true

_.inRange(4, 8);
// =&gt; true

_.inRange(4, 2);
// =&gt; false

_.inRange(2, 2);
// =&gt; false

_.inRange(1.2, 2);
// =&gt; true

_.inRange(5.2, 4);
// =&gt; false

_.inRange(-3, -2, -6);
// =&gt; true
</code></pre>

entityMap|blocks|key|fo2an|text|我喜欢尖头的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|d87ke|函数，所以我写了一个类似的函数，在我的场景中工作得很好。|354o7|/**
+*+Checks+if+an+integer+is+within+±x+another+integer.
+*+@param+{int}+op+-+The+integer+in+question
+*+@param+{int}+target+-+The+integer+to+compare+to
+*+@param+{int}+range+-+the+range+±
+*/
function+nearInt(op,+target,+range)+{
++++return+op+<+target+%2B+range+&&+op+>+target+-+range;
}|code-block|syntax|javascript|2ma23|所以如果你想看看|anlj2|在±10范围内|1l00d|var+x+=+100;
var+y+=+115;
nearInt(x,y,10)+=+false|2fvh3|我用它来检测手机上的长按：|bogeq|//make+sure+they+haven't+moved+too+much+during+long+press.
if+(!nearInt(Last.x,Start.x,5)+%7C%7C+!nearInt(Last.y,+Start.y,5))+clearTimeout(t);^0|0|0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|T|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|U|9|@]|A|@]|B|$]]|$2|E|4|F|6|G|8|V|9|@]|A|@]|B|$H|I]]|$2|J|4|K|6|7|8|W|9|@]|A|@]|B|$]]|$2|L|4|M|6|7|8|X|9|@]|A|@]|B|$]]|$2|N|4|O|6|G|8|Y|9|@]|A|@]|B|$H|I]]|$2|P|4|Q|6|7|8|Z|9|@]|A|@]|B|$]]|$2|R|4|S|6|G|8|10|9|@]|A|@]|B|$H|I]]]]

I like Pointy's <code>between</code> function so I wrote a similar one that worked well for my scenario.

<pre><code>/**
 * Checks if an integer is within ±x another integer.
 * @param {int} op - The integer in question
 * @param {int} target - The integer to compare to
 * @param {int} range - the range ±
 */
function nearInt(op, target, range) {
 return op &lt; target + range &amp;&amp; op &gt; target - range;
}
</code></pre>

so if you wanted to see if <code>x</code> was within ±10 of <code>y</code>:

<pre><code>var x = 100;
var y = 115;
nearInt(x,y,10) = false
</code></pre>

I'm using it for detecting a long-press on mobile:

<pre><code>//make sure they haven't moved too much during long press.
if (!nearInt(Last.x,Start.x,5) || !nearInt(Last.y, Start.y,5)) clearTimeout(t);
</code></pre>

entityMap|blocks|key|90s4f|text|如果希望代码选取特定的数字范围，请确保使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|b6u8s|运算符，而不是|b60ok|..。|d2gl7|​|5edsk|if+(x+>=+4+&&+x+<=+9)+{
++//+do+something
}+else+{
++//+do+something+else
}

//+be+sure+not+to+do+this

if+(x+>=+4+%7C%7C+x+<=+9)+{
++//+do+something
}+else+{
++//+do+something+else
}|code-block|syntax|javascript|fpoko^0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|O|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|P|9|@]|A|@]|B|$]]|$2|E|4|F|6|7|8|Q|9|@]|A|@]|B|$]]|$2|G|4|H|6|7|8|R|9|@]|A|@]|B|$]]|$2|I|4|J|6|K|8|S|9|@]|A|@]|B|$L|M]]|$2|N|4|H|6|7|8|T|9|@]|A|@]|B|$]]]]

If you want your code to pick a specific range of digits, be sure to use the <code>&amp;&amp;</code> operator instead of the <code>||</code>. 

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>if (x &gt;= 4 &amp;&amp; x &lt;= 9) {
 // do something
} else {
 // do something else
}

// be sure not to do this

if (x &gt;= 4 || x &lt;= 9) {
 // do something
} else {
 // do something else
}</code></pre>
</div>
</div>

entityMap|blocks|key|287fr|text|在编写条件之前，您必须想要确定下限和上限|type|unstyled|depth|inlineStyleRanges|entityRanges|data|6vhd|function+between(value,first,last)+{

+let+lower+=+Math.min(first,last)+,+upper+=+Math.max(first,last);
+return+value+>=+lower+&&++value+<=+upper+;

}|code-block|syntax|javascript^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|H|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|I|9|@]|A|@]|B|$F|G]]]]

You must want to determine the lower and upper bound before writing the condition

<pre><code>function between(value,first,last) {

 let lower = Math.min(first,last) , upper = Math.max(first,last);
 return value &gt;= lower &amp;&amp; value &lt;= upper ;

}
</code></pre>

I want to check if a value is in an accepted range. If yes, to do something; otherwise, something else.

The range is <code>0.001-0.009</code>. I know how to use multiple <code>if</code> to check this, but I want to know if there is any way to check it in a single <code>if</code> statement.

Check if a value is within a range of numbers

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我想检查某个值是否在可接受的范围内。如果是，则执行某项操作；否则，执行其他操作。 范围是 ..。我知道如何使用多个 来检查它，但我想知道是否有任何方法可以在 语句。

问检查数值是否在数字范围内
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回答 7

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