我希望有人能帮我找出最好的方法来安排我的DataFrame来做散点图。散点图应该在x轴上有年份,在y轴上有外国玩家百分比。DataFrame大约有400行,为方便起见,我将显示具有较少值的头部。
我从一个更大的DataFrame的DataFrame开始:
df1 = df.head(5).loc[:, ['Year', 'Nationality', 'Foreign Player']]
    Year    Nationality Foreign Player
0   2016    United States   False
1   2016    United States   False
2   2016    United States   False
3   2016    United States   False
4   2016    United States   False我根据年份和外国球员做了一个分组,这是一个多指标DataFrame:
df2 = df.groupby(['Year','Foreign Player']).count()[['Player']].head(6)
                          Player
Year    Foreign Player  
2000    False              26
        True               2
2001    False              21
        True               5
2002    False              20
        True               5我重置了索引,使单个索引成为DataFrame:
df3 = df2.reset_index(level = [0,1]).head(6)
    Year    Foreign Player  Player
0   2000    False             26
1   2000    True              2
2   2001    False             21
3   2001    True              5
4   2002    False             20如您所见,True和False与不同列中的相应值交替出现。我想这样做:
df3['Percent Foreign'] = df3[['Foreign Player']= False] / (df3[['Foreign Player']= False ] + df3[['Foreign Player']= True)显然这是行不通的。我的目标是一个新的DataFrame:
Year    Percent Foreign 
0   2000    15
1   2001    12          
2   2002    5           
3   2003    22          
4   2004    17例如,我可以使用Matplotlib绘制x= Year和x= Percent。无论如何,如果在更早的步骤中有更简单的方法来绘制这一点,那就更好了。
再次感谢!
发布于 2021-03-01 13:58:06
For select
值用于反转掩码
,转换值
按合计编制索引和划分
print (df3)
  Year  Foreign Player  Player
0  2000           False      26
1  2000            True       2
2  2001           False      21
3  2001            True       5
4  2002           False      20
4  2002            True      10df4 = (df3[~df3['Foreign Player']].set_index('Year')['Player'] / 
       df3.groupby('Year')['Player'].sum()).mul(100).reset_index(name='Percent Foreign')
print (df4)
   Year  Percent Foreign
0  2000        92.857143
1  2001        80.769231
2  2002        66.666667另一个想法是改变
由
df22 = df.groupby(['Year','Foreign Player'])['Player'].count().unstack()
print (df22)
Foreign Player  False  True 
Year                        
2000               26      2
2001               21      5
2002               20     10然后除以
列和两列:
df4 = (df22[False] / df22.sum(axis=1)).mul(100).reset_index(name='Percent Foreign')
print (df4)
   Year  Percent Foreign
0  2000        92.857143
1  2001        80.769231
2  2002        66.666667对于百分比
s:
df5 = (df22[True] / df22.sum(axis=1)).reset_index(name='Percent Foreign')https://stackoverflow.com/questions/66417281
复制相似问题