如何使用漂亮的汤从li标签中抓取日期？
如何使用漂亮的汤从li标签中抓取日期？
提问于 2021-08-16 20:51:09
我抓取了特定类的所有li标记，并得到了输出：
<li>Aug 14-18, <a href="https://ai4good.org/fragile-earth-2021/">Fragile Earth 2021</a>, develop radically new technological foundations for advancing and meeting the Sustainable Development Goals. Online KDD-21 workshop.
</li>
<li>Aug 19-26, <a href="https://ijcai-21.org/">IJCAI-21: 30th Int. Joint Conference on Artificial Intelligence</a>. Montreal-themed Virtual Reality, Online.
</li>我可以分别提取href和text，但是我也希望将日期存储在一列数据帧中，或者至少分别获取日期。你知道我该怎么做吗？
以下是该网站的链接：https://www.kdnuggets.com/meetings/index.html#Y21-10
回答 2
Stack Overflow用户
发布于 2021-08-16 20:57:14
我认为这应该可以做到这一点：
from bs4 import BeautifulSoup
soup = BeautifulSoup("""<li>Aug 14-18, <a href="https://ai4good.org/fragile-earth-2021/">Fragile Earth 2021</a>, develop radically new technological foundations for advancing and meeting the Sustainable Development Goals. Online KDD-21 workshop.
</li>
<li>Aug 19-26, <a href="https://ijcai-21.org/">IJCAI-21: 30th Int. Joint Conference on Artificial Intelligence</a>. Montreal-themed Virtual Reality, Online.
</li>""", "lxml")
dates = [x.text.split(',')[0] for x in soup.find_all('li')]
print(dates)输出：
['Aug 14-18', 'Aug 19-26']Stack Overflow用户
发布于 2021-08-16 21:00:12
可以使用.contents方法访问特定元素：
from bs4 import BeautifulSoup
html = """
<li>Aug 14-18, <a href="https://ai4good.org/fragile-earth-2021/">Fragile Earth 2021</a>, develop radically new technological foundations for advancing and meeting the Sustainable Development Goals. Online KDD-21 workshop. </li>
<li>Aug 19-26, <a href="https://ijcai-21.org/">IJCAI-21: 30th Int. Joint Conference on Artificial Intelligence</a>. Montreal-themed Virtual Reality, Online. </li>
"""
soup = BeautifulSoup(html, "html.parser")
dates = [tag.contents[0].strip(', ') for tag in soup.find_all("li")]
print(dates)输出：
['Aug 14-18', 'Aug 19-26']页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/68809053
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