entityMap|blocks|key|3brgv|text|这应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5p4ci|original_values+=+[{'Chr':+'chrX',+'Start':+'107844640',+'End':+'107844640'}]

dictionary+=+original_values[0]
for+key+in+dictionary:
++++try:
++++++++dictionary[key]+=+int(dictionary[key])
++++except:
++++++++try:
++++++++++++dictionary[key]+=+float(dictionary[key])
++++++++except:
++++++++++++pass
output+=+[dictionary]|code-block|syntax|javascript|9kcd0^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|I|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|J|9|@]|A|@]|B|$F|G]]|$2|H|4|-4|6|7|8|K|9|@]|A|@]|B|$]]]]

This should work:
<pre class="lang-py prettyprint-override"><code>original_values = [{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640'}]

dictionary = original_values[0]
for key in dictionary:
 try:
 dictionary[key] = int(dictionary[key])
 except:
 try:
 dictionary[key] = float(dictionary[key])
 except:
 pass
output = [dictionary]
</code></pre>

entityMap|blocks|key|du0rb|text|创建一个很好的小函数来解析键/值：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|fl33p|def+try_convert(x):
++++try:
++++++++return+int(x)
++++except+ValueError:
++++++++pass
++++try:
++++++++return+float(x)
++++except+ValueError:
++++++++return+x|code-block|syntax|javascript|bbbo8|现在就使用它吧！对于某些字典d，|offset|length|style|CODE|661bj|d+=+{try_convert(k):+try_convert(v)+for+k,+v+in+d.items()}|74spe^0|0|0|E|1|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|Q|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|R|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|S|9|@$J|T|K|U|L|M]]|A|@]|B|$]]|$2|N|4|O|6|E|8|V|9|@]|A|@]|B|$F|G]]|$2|P|4|-4|6|7|8|W|9|@]|A|@]|B|$]]]]

Create a nice little function to parse the keys/values:
<pre><code>def try_convert(x):
 try:
 return int(x)
 except ValueError:
 pass
 try:
 return float(x)
 except ValueError:
 return x
</code></pre>
And now use it! For some dictionary <code>d</code>,
<pre><code>d = {try_convert(k): try_convert(v) for k, v in d.items()}
</code></pre>

entityMap|blocks|key|7g6so|text|试一试。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|a1lip|dictEx+=+[{'Chr':+'chrX',+'Start':+'107844640',+'End':+'107844640.323'}]
for+k+in+dictEx[0]:
++++try:dictEx[0][k]+=+int(dictEx[0][k])
++++except+Exception+as+e:
++++++++try:dictEx[0][k]+=+float(dictEx[0][k])
++++++++except:pass+|code-block|syntax|javascript|1p971|我们检查一个值是否可以转换为int或float，并基于此对其进行更改。|t3va^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|K|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|L|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|M|9|@]|A|@]|B|$]]|$2|J|4|-4|6|7|8|N|9|@]|A|@]|B|$]]]]

Give this a try.
<pre><code>dictEx = [{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640.323'}]
for k in dictEx[0]:
 try:dictEx[0][k] = int(dictEx[0][k])
 except Exception as e:
 try:dictEx[0][k] = float(dictEx[0][k])
 except:pass 
</code></pre>
We check if a value can be turned to int or float and change it based on that.

entityMap|blocks|key|5ekdf|text|下面的代码尝试将字符串转换为浮点型，然后检查它是否是整数，并相应地更新原始字典。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|6k2e7|dict+=+{'Chr':+'chrX',+'Start':+'107844640',+'End':+'107844640.100'}
print('Before:+',+dict)
for+key,+value+in+dict.items():
++++try:
++++++++v+=+float(value)
++++++++if+v.is_integer():
++++++++++++v+=+int(v)
++++++++d+=+{key:+v}
++++++++dict.update(d)
++++except+ValueError:
++++++++continue

print('After:+',+dict)|code-block|syntax|javascript|620d6|输出：|85ro6|{'Chr':+'chrX',+'Start':+'107844640',+'End':+'107844640.100'}
{'Chr':+'chrX',+'Start':+107844640,+'End':+107844640.1}|bghaq^0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|M|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|N|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|O|9|@]|A|@]|B|$]]|$2|J|4|K|6|E|8|P|9|@]|A|@]|B|$F|G]]|$2|L|4|-4|6|7|8|Q|9|@]|A|@]|B|$]]]]

The below code tries to convert the string to float, then checks if that's a integer and updates the original dictionary accordingly.
<pre><code>dict = {'Chr': 'chrX', 'Start': '107844640', 'End': '107844640.100'}
print('Before: ', dict)
for key, value in dict.items():
 try:
 v = float(value)
 if v.is_integer():
 v = int(v)
 d = {key: v}
 dict.update(d)
 except ValueError:
 continue

print('After: ', dict)
</code></pre>
Output:
<pre><code>{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640.100'}
{'Chr': 'chrX', 'Start': 107844640, 'End': 107844640.1}
</code></pre>

entityMap|blocks|key|7hqnn|text|已经有一些类似的答案，但这可以在不改变原始输入的情况下使用列表理解。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5h229|def+convert_value(value):
++++try:
++++++++v_float+=+float(value)
++++++++if+v_float.is_integer():
++++++++++++return+int(v_float)
++++++++else:
++++++++++++return+v_float
++++except+ValueError:
++++++++return+value



input_l+=+[{'Chr':+'chrX',+'Start':+'107844640',+'End':+'107844640'},
+++++++++++{'Chr':+'126chrX',+'Start':+'0.50',+'End':+'1'}]
output_l+=+[{k:+convert_value(v)+for+k,v+in+doc.items()}+for+doc+in+input_l]|code-block|syntax|javascript|ajnb7^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|I|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|J|9|@]|A|@]|B|$F|G]]|$2|H|4|-4|6|7|8|K|9|@]|A|@]|B|$]]]]

There are already some similar answers, but this would do the trick using a list comprehension without altering the original input.
<pre><code>def convert_value(value):
 try:
 v_float = float(value)
 if v_float.is_integer():
 return int(v_float)
 else:
 return v_float
 except ValueError:
 return value



input_l = [{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640'},
 {'Chr': '126chrX', 'Start': '0.50', 'End': '1'}]
output_l = [{k: convert_value(v) for k,v in doc.items()} for doc in input_l]
</code></pre>

Let's say I have a dict like this:
<pre><code>[{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640'}]
</code></pre>
Almost all the key values are strings, not all of them, but almost (I don't know why).
I would like to check all the key values and convert the <code>strings</code> to <code>int or float</code> only if the string contains numbers. <code>'10.020'</code> should be a <code>float</code>, <code>'10.020abc'</code> should remain as a <code>string</code> and '123' should be an <code>int</code>.
This is the desired result:
<pre><code>[{'Chr': 'chrX', 'Start': 107844640, 'End': 107844640}]
</code></pre>
I did something similar in JavaScript with <code>Number()</code>.
Is there any pythonic way to achieve that?

Python - Check all the key - value pairs in a dict and convert to int or float

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 假设我有这样一个字典： [{'Chr': 'chrX', 'Start': '107844640', 'End': '107844640'}] 几乎所有的键值都是字符串，不是全部，但几乎都是(我不知道为什么)。 我想检查所有的键值，并且仅当字符串包含数字时才将strings转换为int or float。'10.02...

问Python -检查字典中的所有键值对并将其转换为int或float
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问Python -检查字典中的所有键值对并将其转换为int或floatEN