entityMap|blocks|key|6rp8r|text|在您的示例中，element连续引用多个(九个)不同的整数。因此，它不是一个可以容纳多个值的变量，而是一个可以连续引用任何您喜欢的对象的名称。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5sn1e|例如，它可以在稍后的代码中引用字典：element+=+{'a':+1}。|7biab|这对于Python来说是相当典型的。|95etn^0|7|7|0|I|I|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|L|9|@$A|M|B|N|C|D]]|E|@]|F|$]]|$2|G|4|H|6|7|8|O|9|@$A|P|B|Q|C|D]]|E|@]|F|$]]|$2|I|4|J|6|7|8|R|9|@]|E|@]|F|$]]|$2|K|4|-4|6|7|8|S|9|@]|E|@]|F|$]]]]

In your example, <code>element</code> successively refers to multiple (nine) distinct integers. As such, it is not a variable that can hold multiple values, but rather a name that can successively refer to any object you like.
It could for instance refer to a dictionary later on in your code: <code>element = {'a': 1}</code>.
This is fairly typical for Python.

entityMap|blocks|key|ec5jk|text|在python中，变量是动态的。如果你有例如。整数，则可以通过为其他类型赋值来将其转换为另一种类型，如元组。但是整数总是只有一个值。在代码的最后一行，您只需将元素添加到scoops_sold，例如，如果element为2，scoops_sold为7，则scoops_sold变为9。如果您想存储单个元素，请将scoops_sold声明为列表，如scoops_sold=[]。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|77n9t^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|D|9|@]|A|@]|B|$]]|$2|C|4|-4|6|7|8|E|9|@]|A|@]|B|$]]]]

In python, variables are dynamic. If you have eg. an integer, you can transform it to another type like a tuple by assigning values of other types. But an integer is always only one value. With the last line in your code, you just add element to scoops_sold, for example if element is 2 and scoops_sold is 7, scoops_sold becomes 9. If you want to store the single elements, declare scoops_sold as a list, like scoops_sold=[].

entityMap|blocks|key|9aksu|text|Python+for循环与大多数语言略有不同。我也是Python的新手，但我不认为将多个数字赋给1个变量是可能的，除非它是一个元组或数组。您所拥有的是一个二维数组和一个嵌套的for循环来遍历它。循环for+location+in+sales_data:的外部遍历较大数组中的每个数组。所以它首先会看12，17，22。然后，内部的for循环for+element+in+location:遍历较小的数组，分别打印每个单独的整数。所以从本质上讲，你不会将多个整数赋给一个变量，你有一个由更小的数组组成的数组，这些数组填充了赋给一个值的整数，循环遍历每个值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3rvnd|希望这能有所帮助！|39n94^0|2R|R|4P|O|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|J|9|@$A|K|B|L|C|D]|$A|M|B|N|C|D]]|E|@]|F|$]]|$2|G|4|H|6|7|8|O|9|@]|E|@]|F|$]]|$2|I|4|-4|6|7|8|P|9|@]|E|@]|F|$]]]]

Python for loops are a bit different than most languages. I'm fairly new to Python as well, but I don't think it's possible to have multiple numbers assigned to 1 variable unless it's a tuple or array. What you have is a 2 dimensional array and a nested for loop to iterate through it. The outer part of the loop <code>for location in sales_data:</code> iterates through each array within the larger array. So it would first look at [12, 17, 22]. Then the inner for loop <code>for element in location:</code> iterates through that smaller array printing each individual integer separately. So essentially you don't have multiple integers assigned to one variable, you have an array of smaller arrays filled with integers assigned to one value and the loops iterates through each value.
Hope that helped!

entityMap|blocks|key|a0afs|text|在您编写的代码中，您只是将值添加到单个变量，scoop_sold的最终值是12+%2B+17+%2B+22+%2B+2+%2B+10+%2B+3+%2B+5+%2B+12+%2B+13等于96。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|6b2ts|但是您想要的是“将值存储在一个值中"，这样您就可以对list使用.append|cece8|例如：|1ankn|my_list+=+[1,2,3]
my_value+=+[]
for+element+in+my_list:
++++my_value.append(element)+|code-block|syntax|javascript|1ekhi|现在，在my_value中，您存储了所需的所有变量|9uimp^0|M|A|11|13|26|2|0|Q|4|W|7|0|0|0|4|8|0^^$0|$]|1|@$2|3|4|5|6|7|8|S|9|@$A|T|B|U|C|D]|$A|V|B|W|C|D]|$A|X|B|Y|C|D]]|E|@]|F|$]]|$2|G|4|H|6|7|8|Z|9|@$A|10|B|11|C|D]|$A|12|B|13|C|D]]|E|@]|F|$]]|$2|I|4|J|6|7|8|14|9|@]|E|@]|F|$]]|$2|K|4|L|6|M|8|15|9|@]|E|@]|F|$N|O]]|$2|P|4|Q|6|7|8|16|9|@$A|17|B|18|C|D]]|E|@]|F|$]]|$2|R|4|-4|6|7|8|19|9|@]|E|@]|F|$]]]]

In the code you wrote you just adding values to a single variable, the final value of <code>scoop_sold</code> is <code> 12 + 17 + 22 + 2 + 10 + 3 + 5 + 12 + 13</code> is equal to <code>96</code>.
But the thing u want is &quot; storing values in one value &quot;, so you can use <code>.append</code> to a <code>list</code>
For example :
<pre><code>my_list = [1,2,3]
my_value = []
for element in my_list:
 my_value.append(element) 
</code></pre>
and now in <code>my_value</code> you stored all variables you wanted

I'm a beginner learning python from Codecademy. My question is that We can create a variable with a <code>list</code>, <code>tuple</code>, <code>string</code> , <code>numbers</code>, <code>dictionary</code>, <code>Boolean</code> and etc.
Using single variable, we can add multiple numbers and strings to create a list, tuple and dictionary etc. How to create a single variable and assign multiple values of numbers? When I write a variable for example:
<pre><code>Variable1 = 1,2,3,4,5,6
</code></pre>
This becomes a tuple. I can't add multiples values as numbers to a variable, it changes the data type. I want the data type to be int. From the following example.
<pre><code>sales_data = [[12, 17, 22], [2, 10, 3], [5, 12, 13]]

scoops_sold = 0

for location in sales_data:
 for element in location:
 print(element)
 scoops_sold += element

print(scoops_sold)
</code></pre>
In the above example, the <code>element</code> variable data type is <code>int</code> but it can store multiple values in a single variable? How's it possible in python?
Just curious.

How to assign multiple values as numbers in a variable in Python?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我是一个从Codecademy学习python的初学者。我的问题是，我们可以创建一个包含list、tuple、string、numbers、dictionary、Boolean等的变量。 使用单变量，我们可以添加多个数字和字符串来创建列表、元组和字典等。如何创建单个变量并为数字分配多个值？例如，当我编写一个变量时： ...

问如何在Python中将多个值作为一个变量的数字赋值？
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问如何在Python中将多个值作为一个变量的数字赋值？EN