我有一个需要从给定句子中删除的短语(n-gram)列表。
removed = ['range', 'drinks', 'food and drinks', 'summer drinks']
sentence = 'Oranges are the main ingredient for a wide range of food and drinks'我想要得到:
new_sentence = 'Oranges are the main ingredient for a wide of'我试过Remove list of phrases from string,但它不起作用(‘橙子’变成了‘O’,‘饮料’被删除,而不是一个短语‘食物和饮料’)
有人知道怎么解决这个问题吗?谢谢!
发布于 2020-06-18 06:37:39
正则表达式时间!
In [116]: removed = ['range', 'drinks', 'food and drinks', 'summer drinks']
...: removed = sorted(removed, key=len, reverse=True)
...: sentence = 'Oranges are the main ingredient for a wide range of food and drinks'
...: new_sentence = sentence
...: import re
...: removals = [r'\b' + phrase + r'\b' for phrase in removed]
...: for removal in removals:
...: new_sentence = re.sub(removal, '', new_sentence)
...: new_sentence = ' '.join(new_sentence.split())
...: print(sentence)
...: print(new_sentence)
Oranges are the main ingredient for a wide range of food and drinks
Oranges are the main ingredient for a wide of发布于 2020-06-18 06:34:08
由于您只想匹配整个单词,我认为第一步是将所有内容都转换为单词列表,然后从最长到最短的短语进行迭代,以便找到要删除的内容:
>>> removed = ['range', 'drinks', 'food and drinks', 'summer drinks']
>>> sentence = 'Oranges are the main ingredient for a wide range of food and drinks'
>>> words = sentence.split()
>>> for ngram in sorted([r.split() for r in removed], key=len, reverse=True):
... for i in range(len(words) - len(ngram)+1):
... if words[i:i+len(ngram)] == ngram:
... words = words[:i] + words[i+len(ngram):]
... break
...
>>> " ".join(words)
'Oranges are the main ingredient for a wide of'注意,这种简单的方法有一些缺陷--相同n元语法的多个副本不会被删除,但是在修改words之后,您也不能继续使用该循环(长度将不同),所以如果您想处理重复的内容,则需要对更新进行批量处理。
发布于 2020-06-18 06:51:21
import re
removed = ['range', 'drinks', 'food and drinks', 'summer drinks']
sentence = 'Oranges are the main ingredient for a wide range of food and drinks'
# sort the removed tokens according to their length,
removed = sorted(removed, key=len, reverse=True)
# using word boundaries
for r in removed:
sentence = re.sub(r"\b{}\b".format(r), " ", sentence)
# replace multiple whitspaces with a single one
sentence = re.sub(' +',' ',sentence)我希望这会有所帮助:首先,你需要根据长度对删除的字符串进行排序,这样“食品和饮料”就会在“饮料”之前被替换。
https://stackoverflow.com/questions/62439244
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