entityMap|blocks|key|drh8m|text|您的$vendor是一个关联数组，而$plucked是一个数组数组。即使它只有一项，它的索引也将为零，因此您需要遍历$plucked并对每一项进行合并。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|8t4o4|$vendor+=+Vendor::find($id)->toArray();
$vendor_detail+=+Vendor_detail::where('vendor_id',$id)->get();
$plucked+=+$vendor_detail->pluck('vendor_name','vendor_value');

$merged+=+[];
foreach($plucked+as+$p){
++++$merged[]+=+array_merge($p,+$vendor);
}
dd($merged);|code-block|syntax|javascript|997cv^0|2|7|I|8|1M|8|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|M|9|@$A|N|B|O|C|D]|$A|P|B|Q|C|D]|$A|R|B|S|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|T|9|@]|E|@]|F|$J|K]]|$2|L|4|-4|6|7|8|U|9|@]|E|@]|F|$]]]]

Your <code>$vendor</code> is one associative array while <code>$plucked</code> is an array of arrays. Even if it has only one item it will be of index zero so you need to loop through <code>$plucked</code> and merge for each one.

<pre><code>$vendor = Vendor::find($id)-&gt;toArray();
$vendor_detail = Vendor_detail::where('vendor_id',$id)-&gt;get();
$plucked = $vendor_detail-&gt;pluck('vendor_name','vendor_value');

$merged = [];
foreach($plucked as $p){
 $merged[] = array_merge($p, $vendor);
}
dd($merged);
</code></pre>

entityMap|blocks|key|a9lb|text|$vendor+=+Vendor::find($id);
$vendor_detail+=+Vendor_detail::select('vendor_id','province')->where('vendor_id',$id)->get()->toArray();

$data=+array_merge($vendor,$vendor_detail);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|cgr3l|unstyled^0|0^^$0|$]|1|@$2|3|4|5|6|7|8|G|9|@]|A|@]|B|$C|D]]|$2|E|4|-4|6|F|8|H|9|@]|A|@]|B|$]]]]

<pre><code>$vendor = Vendor::find($id);
$vendor_detail = Vendor_detail::select('vendor_id','province')-&gt;where('vendor_id',$id)-&gt;get()-&gt;toArray();

$data= array_merge($vendor,$vendor_detail);
</code></pre>

entityMap|blocks|key|eepgn|text|我认为你应该使用数据库连接来获得更快的结果。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|ev4gj|$vendor+=+Vendor::join('vendor_details',+'vendors.id',+'=',+'vendor_details.vendor_id')
++++->select('vendors.*',+'vendor_name','vendor_value')
++++->where('id',+$id)
++++->first();

if+($vendor)++{
++++$vendor+=+$vendor->toArray();
}|code-block|syntax|javascript|deo53^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|I|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|J|9|@]|A|@]|B|$F|G]]|$2|H|4|-4|6|7|8|K|9|@]|A|@]|B|$]]]]

I think you should use database join to get faster results.

<pre><code>$vendor = Vendor::join('vendor_details', 'vendors.id', '=', 'vendor_details.vendor_id')
 -&gt;select('vendors.*', 'vendor_name','vendor_value')
 -&gt;where('id', $id)
 -&gt;first();

if ($vendor) {
 $vendor = $vendor-&gt;toArray();
}
</code></pre>

entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://laravel.com/docs/5.8/collections#method-merge|blocks|key|1hn23|text|++$vendor_detail+=+Vendor_detail::where('vendor_id',$id)->get();+will+give+you+a+collection|code-block|depth|inlineStyleRanges|entityRanges|syntax|javascript|9f25d|$plucked+=+$vendor_detail->pluck('vendor_name','vendor_value');会给你一个集合，所以，你可以使用集合merge，或者你可以像其他答案一样循环遍历一个集合并添加merge另一个集合，但这些不是数组，你得到的是集合。|unstyled|offset|length|style|CODE|55tda^0|0|0|1R|29|5|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|S|G|@]|H|@]|6|$I|J]]|$A|K|C|L|2|M|F|T|G|@$N|U|O|V|P|Q]]|H|@$N|W|O|X|A|Y]]|6|$]]|$A|R|C|-4|2|M|F|Z|G|@]|H|@]|6|$]]]]

<pre><code> $vendor_detail = Vendor_detail::where('vendor_id',$id)-&gt;get(); will give you a collection
</code></pre>

as well as <code>$plucked = $vendor_detail-&gt;pluck('vendor_name','vendor_value');</code> will give you a collection, so, either you can use collection <a href="https://laravel.com/docs/5.8/collections#method-merge" rel="nofollow noreferrer">merge</a> or you may like to loop through one and add merge another as other answer is doing, but these are not array, you are getting collections.

I have a problem here, I want to combine 2 arrays into 1, I've tried using array_merge from php, and merge () from laravel but nothing works 
//$plucked is EAV database

<pre><code>$vendor = Vendor::find($id)-&gt;toArray();
 $vendor_detail = Vendor_detail::where('vendor_id',$id)-&gt;get();
 $plucked = $vendor_detail-&gt;pluck('vendor_name','vendor_value');

 $merged = array_merge($plucked, $vendor);

 // $merged = $vendor-&gt;merge($plucked)-&gt;all(); 
 dd($merged);
</code></pre>

I think because the array is different, there array $plucked

<pre><code>#items: array:10 [▼
 "user_email" =&gt; "cobaupdatelagi@gmail.com"

 ]
</code></pre>

and there my array in $vendor

<pre><code>
array:15 [▼
 "vendor_id" =&gt; 39
 "province" =&gt; "ACEH"

]
</code></pre>

the output that I want

<pre><code>$somearray =[
 "vendor_id" =&gt; 39
 "province" =&gt; "ACEH"
 "user_email" =&gt; "cobaupdatelagi@gmail.com"

]
</code></pre>

How to array merge in laravel

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我这里有个问题，我想把两个数组组合成一个，我试过使用php中的array_merge，和laravel中的merge ()，但都不起作用//$plucked是EAV数据库 $vendor = Vendor::find($id)->toArray();        $vendor_detail = Vendor_de...

问如何在laravel中数组合并
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