entityMap|blocks|key|1kvbc|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|dbolf|++++var+str+=+"021";
++++var+a+=+str.split("");+//+converts+the+string+into+an+array
++++
++++var+result+=+a.reduce((i,+n)+=>+{
++++++++return+Number(i)%2B+Number(n)
++++},0);+
++++
++++console.log(result)
++++//result+=+3|code-block|syntax|javascript|cu5mu|8f151^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|J|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|K|9|@]|A|@]|B|$F|G]]|$2|H|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|I|4|-4|6|7|8|M|9|@]|A|@]|B|$]]]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>    var str = "021";
    var a = str.split(""); // converts the string into an array
    
    var result = a.reduce((i, n) =&gt; {
        return Number(i)+ Number(n)
    },0); 
    
    console.log(result)
    //result = 3</code></pre>
</div>
</div>
</p>


entityMap|blocks|key|brni1|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|8relq|var+result+=+0;
var+second+=+"021";
var+arr+=+second.split("");

for(var+i+=+0;+i+<+arr.length;+i%2B%2B)
++++result+=+%2Barr[i]+%2B+result;

console.log(result);|code-block|syntax|javascript|tqlv|4c6m0^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|J|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|K|9|@]|A|@]|B|$F|G]]|$2|H|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|I|4|-4|6|7|8|M|9|@]|A|@]|B|$]]]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var result = 0;
var second = "021";
var arr = second.split("");

for(var i = 0; i &lt; arr.length; i++)
    result = +arr[i] + result;

console.log(result);</code></pre>
</div>
</div>
</p>


entityMap|blocks|key|1fmla|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|8hmr2|​|a41jl|var+array+=+"0123456";
var+result+=+array.split("").reduce((acc,+cur)+=>+{return+(%2Bacc)+%2B+(%2Bcur);},0);
console.log(result);|code-block|syntax|javascript|1j0k2|8hov2|正如Bucket在评论中所说，这将把字符串拆分成字符，然后使用array.reduce()将所有字符合并为一个值，方法是使用箭头函数将它们转换为数字并对它们求和。|offset|length|style|CODE|9m1b0^0|0|0|0|0|V|E|0^^$0|$]|1|@$2|3|4|5|6|7|8|R|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|S|9|@]|A|@]|B|$]]|$2|E|4|F|6|G|8|T|9|@]|A|@]|B|$H|I]]|$2|J|4|D|6|7|8|U|9|@]|A|@]|B|$]]|$2|K|4|L|6|7|8|V|9|@$M|W|N|X|O|P]]|A|@]|B|$]]|$2|Q|4|-4|6|7|8|Y|9|@]|A|@]|B|$]]]]

<p>Try this:</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var array = "0123456";
var result = array.split("").reduce((acc, cur) =&gt; {return (+acc) + (+cur);},0);
console.log(result);</code></pre>
</div>
</div>
</p>

<p>As Bucket said in the comments, this will split the string up into characters, then use <code>array.reduce()</code> to merge all the characters into one value by using an arrow function that converts them to numbers and sums them.</p>


entityMap|blocks|key|bfnl5|text|这可能是您所能做到的最有效的方法，但是它不会进行任何输入验证：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|f1m3c|var+input+=+"0021031";
var+zeroCode+=+"0".charCodeAt(0);

function+sum(input)+{
++var+result+=+0;
++for+(var+i+=+0;+i+<+input.length;+%2B%2Bi)+{
++++result+%2B=+input.charCodeAt(i)+-+zeroCode;
++}
++return+result;
}

console.log(sum(input))|code-block|syntax|javascript|4tth8^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|I|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|J|9|@]|A|@]|B|$F|G]]|$2|H|4|-4|6|7|8|K|9|@]|A|@]|B|$]]]]

<p>This is probably as efficient as you can possible make it, but it does not do any input validation:</p>

<pre><code>var input = "0021031";
var zeroCode = "0".charCodeAt(0);

function sum(input) {
  var result = 0;
  for (var i = 0; i &lt; input.length; ++i) {
    result += input.charCodeAt(i) - zeroCode;
  }
  return result;
}

console.log(sum(input))
</code></pre>


entityMap|blocks|key|6g9a7|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|68kk5|function+mathAdd(s)+{
++//+take+input+and+split+it+by+''
++//+use+a+as+the+accumulator
++//+use+v+as+the+value
++//+add+the+value+to+the+accumulator+and+start+at+0
++//+return+the+value
++return+String(s).split('').reduce((a,+v)+=>+a+%2B+parseInt(v,+10),+0);
}

console.log(mathAdd("001"));
console.log(mathAdd("021"));
console.log(mathAdd("031"));|code-block|syntax|javascript|93iqg|2c3up^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|J|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|K|9|@]|A|@]|B|$F|G]]|$2|H|4|5|6|7|8|L|9|@]|A|@]|B|$]]|$2|I|4|-4|6|7|8|M|9|@]|A|@]|B|$]]]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>function mathAdd(s) {
  // take input and split it by ''
  // use a as the accumulator
  // use v as the value
  // add the value to the accumulator and start at 0
  // return the value
  return String(s).split('').reduce((a, v) =&gt; a + parseInt(v, 10), 0);
}

console.log(mathAdd("001"));
console.log(mathAdd("021"));
console.log(mathAdd("031"));</code></pre>
</div>
</div>
</p>


<p>I have some logic within an app that generating strings like the following:</p>

<pre><code>"001"
"021"
"031"
</code></pre>

<p>I want to take the single string and split this and add the numbers in a basic efficient manner.</p>

<p>e.g for the second string above
<code>021</code> - desired outcome would be split this to make the sum <code>0 + 2 + 1 = 3</code> - how do I split the string by each number using vanilla javascript?</p>


What is the easiest method to add individual numbers in a string using javascript

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我在应用程序中有一些生成字符串的逻辑，如下所示： "001""021""031" 我想要将单个字符串拆分，然后以一种基本有效的方式将数字相加。 例如，对于上面的第二个字符串-期望的结果将被拆分，以使和为0 + 2 + 1 = 3 -我如何使用vanilla javascript将字符串拆分为每个数字？ 

问使用javascript在字符串中添加单个数字的最简单方法是什么
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问使用javascript在字符串中添加单个数字的最简单方法是什么EN