过滤对象数组中的对象键
过滤对象数组中的对象键
提问于 2020-07-30 00:21:23
假设我正在从Node Repository获取一个对象数组，例如：
results = [
{
name: "John",
surname: "Fool",
age: 22
},
{
name: "Erik",
surname: "Owl",
age: 38
}
]我如何过滤每个对象，只取我需要的键，例如避免'age‘键？
filteredResults = [
{
name: "John",
surname: "Fool",
},
{
name: "Erik",
surname: "Owl",
}
]我已经通过创建另一个空数组并通过在原始数组上循环来填充它来获得它，但如果是大数据，这将是繁重的。
repository.retrieve((error, result) => {
let filteredData = [];
result.forEach(r => {
filteredData.push({
name: r.name,
description: r.description,
});
});
});在SQL中，我将通过以下方式获取它：
SELECT `name, description` FROM results;回答 5
Stack Overflow用户
回答已采纳
发布于 2020-07-30 00:57:26
看一下Array.map.It创建了转换后的数组。
let arr = [
{
name: "John",
surname: "Fool",
age: 22
},
{
name: "Erik",
surname: "Owl",
age: 38
}
]
let result = arr.map((elem) => {
return {
name: elem.name,
surname: elem.surname
}
});
console.log(result);
Stack Overflow用户
发布于 2020-07-30 00:24:11
您可以根据需要重新构建对象
{
name: rec.name,
surname: rec.surname
}
const results = [
{
name: "John",
surname: "Fool",
age: 22
},
{
name: "Erik",
surname: "Owl",
age: 38
}
]
const result = results.map((rec) => {
return {
name: rec.name,
surname: rec.surname
}
})
console.log(result)
或无用的delete字段
const results = [
{
name: "John",
surname: "Fool",
age: 22
},
{
name: "Erik",
surname: "Owl",
age: 38
}
]
const result = results.map((rec) => {
delete rec.age
return rec
})
console.log(result)
Stack Overflow用户
发布于 2020-07-30 00:28:04
您可以使用map和reduce来简化这一过程，这样就不需要创建新的数组了。
var results = [ { name: "John", surname: "Fool", age: 22 }, { name: "Erik", surname: "Owl", age: 38 } ];
let keys = ['name', 'surname'];
var filtered = results.map(obj=>
keys.reduce((acc,curr)=>(acc[curr]=obj[curr],acc), {}));
console.log(filtered);
您也可以使用对象解构。
var results = [ { name: "John", surname: "Fool", age: 22 }, { name: "Erik", surname: "Owl", age: 38 } ];
var filtered = results.map(({name,surname})=>({name,surname}));
console.log(filtered);
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/63158094
复制相关文章
相似问题
腾讯云开发者
