错误:实体类必须使用@Entity进行注释
错误:实体类必须使用@Entity进行注释
提问于 2018-02-02 01:52:32
我决定将kotlin与Room库一起使用，我真的面临着很多问题，我已经厌倦了阅读参考资料和寻找解决方案我的数据类：
@Entity
data class HistorySong(
@PrimaryKey
var SongId: Int =0,
@ColumnInfo(name = "song_name")
var songName: String="",
@ColumnInfo(name = "song_artist")
var songArtist: String="",
@ColumnInfo(name = "song_link")
var songLink: String="",
@ColumnInfo(name = "image_path")
var songImagePath: String="",
@ColumnInfo(name="is_favoutire")
var songisFavourite: Boolean= false
)我的Dao类：
@Dao
interface HistorySongDao {
@Delete
fun deleteSong(historySongDao: HistorySongDao)
@Insert(onConflict = OnConflictStrategy.REPLACE)
fun insert(vararg historySongDao: HistorySongDao)
@Query("SELECT * FROM HistorySong")
fun loadAllSongs(): Array<HistorySong>
@Query("SELECT * FROM HistorySong WHERE songId = :mId")
fun findById(mId: Int): HistorySong
@Query("SELECT * FROM HistorySong WHERE is_favoutire = :getFavourite ")
fun getFavourite(getFavourite : Boolean) : Array<HistorySong>
@Update
fun updateUsers(vararg historySong: HistorySong)
}数据库类：
@Database(entities = arrayOf(QueuedSong::class, HistorySongDao::class), version = 2)
abstract class AppDataBase : RoomDatabase() {
abstract fun queuedSongDao(): QueuedSongDao
abstract fun historySongDao(): HistorySongDao
}QueuedSong运行得很好，但historySong中的问题是：
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:7: error: Entity class must be annotated with @Entity
public abstract interface HistorySongDao {
^
w: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\AppDataBase.java:10: warning: Room cannot create an SQLite connection to verify the queries. Query verification will be disabled. Error: [SQLITE_ERROR] SQL error or missing database (near ")": syntax error)
public abstract class AppDataBase extends android.arch.persistence.room.RoomDatabase {
^
w: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySong.java:10: warning: There are multiple good constructors and Room will pick the no-arg constructor. You can use the @Ignore annotation to eliminate unwanted constructors.
public final class HistorySong {
^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:15: error: Type of the parameter must be a class annotated with @Entity or a collection/array of it.
com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao... historySongDao);
^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:11: error: Type of the parameter must be a class annotated with @Entity or a collection/array of it.
com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao historySongDao);
^
e: F:\SmartStreamer\app\build\tmp\kapt3\stubs\debug\com\pro\smartstreamer\Database\QueuedDatabase\HistorySongDao.java:30: error: com.pro.smartstreamer.Database.QueuedDatabase.HistorySongDao is part of com.pro.smartstreamer.Database.QueuedDatabase.AppDataBase but this entity is not in the database. Maybe you forgot to add com.pro.smartstreamer.Database.QueuedDatabase.HistorySong to the entities section of the @Database?
public abstract void updateUsers(@org.jetbrains.annotations.NotNull()和：
FAILURE: Build failed with an exception.
* What went wrong:
Execution failed for task ':app:kaptDebugKotlin'.
> Compilation error. See log for more details我真的找不到解决办法..提前感谢
回答 5
Stack Overflow用户
回答已采纳
发布于 2018-02-02 03:46:04
正如它在第一条评论中所说的，您正在尝试插入和删除HistorySongDao对象，而不是HistorySong，您的代码将变成：
@Dao
interface HistorySongDao {
@Delete
fun deleteSong(vararg historySong: HistorySong)
@Insert(onConflict = OnConflictStrategy.REPLACE)
fun insert(vararg historySong: HistorySong)
@Query("SELECT * FROM HistorySong")
fun loadAllSongs(): Array<HistorySong>
@Query("SELECT * FROM HistorySong WHERE songId = :mId")
fun findById(mId: Int): HistorySong
@Query("SELECT * FROM HistorySong WHERE is_favoutire = :getFavourite ")
fun getFavourite(getFavourite : Boolean) : Array<HistorySong>
@Update
fun updateUsers(vararg historySong: HistorySong)
}Stack Overflow用户
发布于 2019-02-16 03:14:37
我通过更改@数据库的参数(RoomDatabase类)解决了这个问题，我没有意识到并将我的DAO放在了应该是我的实体的地方。
在我的例子中：
@Database(entities = [WordDao::class],version = 1)更改为：
@Database(entities = [WordEntity::class],version = 1)因此，当有人收到这个错误时，可能不仅应该检查实体被声明的位置，还应该检查它被使用的位置。
Stack Overflow用户
发布于 2018-09-26 17:08:51
将数据库类更新为此
@Database(entities = arrayOf(QueuedSong::class, HistorySong::class), version = 2)
abstract class AppDataBase : RoomDatabase() {
abstract fun queuedSongDao(): QueuedSongDao
abstract fun historySongDao(): HistorySongDao
}我将HistorySongDao.class更改为HistorySong.class
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/48568906
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