Laravel将多个输入表单插入数据库
Laravel将多个输入表单插入数据库
提问于 2016-12-02 12:20:03
我已经创建了一个像下面的图像一样的多输入表单，我想保存到数据库中，问题是当我使用dd()时，它只显示第二行数据。
如何将每一行保存到数据库？
这是我的laravel控制器
public function store(Request $request)
{
$input = Input::all();
$condition = $input['service_id'];
foreach ($condition as $key => $condition) {
$detailorder = new DetailOrder;
$detailorder->serivce_id = $input['service_id'][$key];
$detailorder->order_type = $input['order_type'][$key];
$detailorder->select_plan = $input['select_plan'][$key];
$detailorder->qty = $input['qty'][$key];
$detailorder->unit_price = $input['unit_price'][$key];
//$detailorder->mandays = $input['mandays'][$key];
$detailorder->note = $input['note'][$key];
}
dd($detailorder);
}这里是我的表脚本，我使用jQuery来创建它
function getCorporateService(id){
// get data and parsing to column
$.get("{{ url('salesorder/service')}}/"+id, function(data){
console.log(id);
console.log(data);
$.each(data, function (index, element){
$br = "<tr id='item'>";
$br += "<td> <input class='input-small' type='text' id='order_identifier' name='order_identifier[]' readonly></td>";
$br += "<td><input class='input-small' type='text' id='service_name["+id+"]' name='service_name[]' value='"+element.service_name+"' readonly>"
+"<input class='input-small' type='hidden' id='service_id["+id+"]' name='service_id[]' value='"+element.id+"' readonly></td>";
$br += "<td><select id='order_type["+id+"]' name='order_type[]'> <option> - </option> <option value='add'>Add</option> <option value='change'>Change</option> <option value='cancel'>Cancel</option> </select></td>";
$br += "<td><input class='input-small' type='text' id='select_plan["+id+"]' name='select_plan[]'></td>";
$br += "<td><input class='input-mini' type='text' id='qty["+id+"]' name='qty[]' value='1' onChange='getTotalPrice("+id+")'></td>";
$br += "<td><input class='input-small' type='text' id='unit_price["+id+"]' name='unit_price[]' onChange='getTotalPrice("+id+")'></td>";
$br += "<td><input class='input-small' type='text' id='total_price["+id+"]' name='total_price[]' onChange='getTotalPrice("+id+")'></td>";
$br += "<td><textarea class='input-small' id='notes["+id+"]' name='note[]'></textarea></td>";
$br += "</tr>";
$(".corporatesvc").append($br);
});
});
}Stack Overflow用户
发布于 2016-12-02 12:23:19
检查以下行：
foreach ($condition as $key => $condition) {
$detailorder = new DetailOrder;
// here you are creating a new object on each iteration, means on each iteration new object overrides old one, that's why you are getting the last record only
}要解决此问题，请将此对象创建代码放在循环之外，然后重试。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/40924751
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