如何将数组作为参数传递给bash函数?
发布于 2018-01-11 13:37:31
可以尝试如下方法:
takes_ary_as_arg()
{
declare -a argAry1=("${!1}")
echo "${argAry1[@]}"
declare -a argAry2=("${!2}")
echo "${argAry2[@]}"
}
try_with_local_arys()
{
# array variables could have local scope
local descTable=(
"sli4-iread"
"sli4-iwrite"
"sli3-iread"
"sli3-iwrite"
)
local optsTable=(
"--msix --iread"
"--msix --iwrite"
"--msi --iread"
"--msi --iwrite"
)
takes_ary_as_arg descTable[@] optsTable[@]
}
try_with_local_aryssli4-iread sli4-iwrite sli3-iread sli3-iwrite
--msix --iread --msix --iwrite --msi --iread --msi --iwritehttps://stackoverflow.com/questions/-100003157
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