entityMap|blocks|key|cgsnn|text|我建议不要使用LIKE来实现搜索，它有很多局限性。但是如果你的用例很简单，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|38mdc|SELECT+1+as+orderby,+*
FROM+Customers
WHERE+Country+LIKE+'land%25'
union+all
SELECT+2,+*
FROM+Customers
WHERE+Country+LIKE+'_%25land%25'
order+by+orderby|code-block|syntax|javascript|epr3d|此方法允许您创建多个级别的排序|a5qcr^0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|K|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|L|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|M|9|@]|A|@]|B|$]]|$2|J|4|-4|6|7|8|N|9|@]|A|@]|B|$]]]]

I suggest not to use LIKE to implement search, it has a lot of limitations. But if your use case is simple, here you go:

<pre><code>SELECT 1 as orderby, *
FROM Customers
WHERE Country LIKE 'land%'
union all
SELECT 2, *
FROM Customers
WHERE Country LIKE '_%land%'
order by orderby
</code></pre>

this approach allows you to create several levels of sorting

entityMap|blocks|key|38rhs|text|这将首先返回所有以land开头的内容，然后返回其他所有内容。您需要特别列出您的字段。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|7spf8|SELECT+field1,+field2,+field3,+etc
FROM+customers
WHERE+country+LIKE+'land%25'
UNION+ALL
SELECT+field1,+field2,+field3,+etc
FROM+customers
WHERE+country+LIKE+'%25land%25'
AND+country+NOT+LIKE+'land%25'|code-block|syntax|javascript|2k0d6|或者，如果您有一个customerid字段，则在查询的第二部分使用子查询。|1kti|SELECT+field1,+field2,+field3,+etc
FROM+customers
WHERE+country+LIKE+'land%25'
UNION+ALL
SELECT+field1,+field2,+field3,+etc
FROM+customers
WHERE+country+LIKE+'%25land%25'
AND+customerid+NOT+IN+(SELECT+customerid
+++++++++++++++++++++++FROM+customers
+++++++++++++++++++++++WHERE+country+LIKE+'land%25')|fjftn^0|9|4|0|0|9|A|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|Q|9|@$A|R|B|S|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|T|9|@]|E|@]|F|$J|K]]|$2|L|4|M|6|7|8|U|9|@$A|V|B|W|C|D]]|E|@]|F|$]]|$2|N|4|O|6|I|8|X|9|@]|E|@]|F|$J|K]]|$2|P|4|-4|6|7|8|Y|9|@]|E|@]|F|$]]]]

This will return anything beginning with <code>land</code> first then everything else.
You will need to specifically list you fields.

<pre><code>SELECT field1, field2, field3, etc
FROM customers
WHERE country LIKE 'land%'
UNION ALL
SELECT field1, field2, field3, etc
FROM customers
WHERE country LIKE '%land%'
AND country NOT LIKE 'land%'
</code></pre>

Or use sub query in second part of query if you have say a <code>customerid</code> field.

<pre><code>SELECT field1, field2, field3, etc
FROM customers
WHERE country LIKE 'land%'
UNION ALL
SELECT field1, field2, field3, etc
FROM customers
WHERE country LIKE '%land%'
AND customerid NOT IN (SELECT customerid
 FROM customers
 WHERE country LIKE 'land%')
</code></pre>

entityMap|0|type|LINK|mutability|MUTABLE|data|url|http://dev.mysql.com/doc/refman/5.7/en/union.html|blocks|key|5utsb|text|UNION运算符就是您要查找的运算符：|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|5v2ra|SELECT+*+FROM+Customers+
WHERE+Country+LIKE+'land%25'+
UNION+
SELECT+*+FROM+Customers+
WHERE+Country+LIKE+'%25land%25';|code-block|syntax|javascript|aehp8^0|0|5|0|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|Q|G|@]|H|@$I|R|J|S|A|T]]|6|$]]|$A|K|C|L|2|M|F|U|G|@]|H|@]|6|$N|O]]|$A|P|C|-4|2|E|F|V|G|@]|H|@]|6|$]]]]

The <a href="http://dev.mysql.com/doc/refman/5.7/en/union.html" rel="nofollow">UNION</a> operator is what you're looking for:

<pre><code>SELECT * FROM Customers 
WHERE Country LIKE 'land%' 
UNION 
SELECT * FROM Customers 
WHERE Country LIKE '%land%';
</code></pre>

entityMap|blocks|key|75vg6|text|您可以根据国家/地区是否以land开头进行排序。我猜您正在使用的MySQL有一个巧妙的特性，当在数值上下文中引用时，它可以将true/false转换为1/0，所以这将非常容易做到：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5shks|SELECT+++*+
FROM+++++Customers+
WHERE++++Country+LIKE+'%25land%25'
ORDER+BY+Country+LIKE+'land%25'+DESC|code-block|syntax|javascript|crfof|其他RDBMS可能没有这种处理布尔值的方法，但您始终可以使用case表达式自己实现它：|eeqcq|SELECT+++*+
FROM+++++Customers+
WHERE++++Country+LIKE+'%25land%25'
ORDER+BY+CASE+WHEN+Country+LIKE+'land%25'+THEN+1+ELSE+0+END+DESC|6to0t^0|D|4|0|0|U|4|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|Q|9|@$A|R|B|S|C|D]]|E|@]|F|$]]|$2|G|4|H|6|I|8|T|9|@]|E|@]|F|$J|K]]|$2|L|4|M|6|7|8|U|9|@$A|V|B|W|C|D]]|E|@]|F|$]]|$2|N|4|O|6|I|8|X|9|@]|E|@]|F|$J|K]]|$2|P|4|-4|6|7|8|Y|9|@]|E|@]|F|$]]]]

You could order by whether or not the country begins with <code>land</code>. MySQL, which I'm guessing you're using, has a neat feature of translating true/false to 1/0 when referenced in numerical context, so this would be really easy to do:

<pre><code>SELECT * 
FROM Customers 
WHERE Country LIKE '%land%'
ORDER BY Country LIKE 'land%' DESC
</code></pre>

Other RDBMSs may not have such a treatment of booleans, but you can always implement it yourself with a <code>case</code> expression:

<pre><code>SELECT * 
FROM Customers 
WHERE Country LIKE '%land%'
ORDER BY CASE WHEN Country LIKE 'land%' THEN 1 ELSE 0 END DESC
</code></pre>

I want to make a good search using PHP and SQL. I'm thinking to use the operator LIKE of SQL (for example: <code>SELECT * FROM Customers WHERE Country LIKE '%land%</code>'), but i want that the first elements to be displayed are the ones that begin with "land". How can I do this? I don't want to perform several query to the db because I think it's a bad idea (but I can be wrong).

Search with SQL

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

 我想做一个很好的搜索使用PHP和SQL。我在考虑使用操作符LIKE of SQL (例如：SELECT * FROM Customers WHERE Country LIKE '%land%')，但我希望显示的第一个元素是以"land“开头的元素。我该怎么做呢？我不想对数据库执行几次查询，因为我认为这不是一个好主意(...

问使用SQL进行搜索
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问使用SQL进行搜索EN