blocks|key|989842|text|尝试使用循环、let和printf作为填充：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|989843|a=1
for+i+in+*.jpg;+do
++new=$(printf+"%2504d.jpg"+"$a")+#04+pad+to+length+of+4
++mv+-i+--+"$i"+"$new"
++let+a=a%2B1
done|code-block|syntax|javascript|989844|使用-i标志可防止自动覆盖现有文件，使用--可防止mv将带有破折号的文件名解释为选项。|989845|entityMap^0|7|3|B|6|0|0|2|2|K|2|P|2|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|N|$]]

Try to use a loop, <code>let</code>, and <code>printf</code> for the padding:
<pre><code>a=1
for i in *.jpg; do
 new=$(printf &quot;%04d.jpg&quot; &quot;$a&quot;) #04 pad to length of 4
 mv -i -- &quot;$i&quot; &quot;$new&quot;
 let a=a+1
done
</code></pre>
using the <code>-i</code> flag prevents automatically overwriting existing files, and using <code>--</code> prevents <code>mv</code> from interpreting filenames with dashes as options.

blocks|key|1204966|text|一句话中的美：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204967|ls+-v+%7C+cat+-n+%7C+while+read+n+f;+do+mv+-n+"$f"+"$n.ext";+done+|code-block|syntax|javascript|1204968|您可以使用.png、.jpg等更改.ext。|offset|length|style|CODE|1204969|entityMap^0|0|0|5|4|A|4|H|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]|$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|X|8|@]|9|@]|A|$]]]|N|$]]

Beauty in one line:

<pre><code>ls -v | cat -n | while read n f; do mv -n "$f" "$n.ext"; done 
</code></pre>

You can change <code>.ext</code> with <code>.png</code>, <code>.jpg</code>, etc.

blocks|key|990649|text|一个非常简单的bash+one+liner，它保留了原来的扩展名，添加了前导零，并且也可以在OSX中工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990650|num=0;+for+i+in+*;+do+mv+"$i"+"$(printf+'%2504d'+$num).${i#*.}";+((num%2B%2B));+done|code-block|syntax|javascript|990651|http://ubuntuforums.org/showthread.php?t=1355021的简化版本|offset|length|990652|entityMap|0|LINK|mutability|MUTABLE|url|http://ubuntuforums.org/showthread.php?t=1355021^0|0|0|0|1C|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

A very simple bash one liner that keeps the original extensions, adds leading zeros, and also works in OSX:

<pre><code>num=0; for i in *; do mv "$i" "$(printf '%04d' $num).${i#*.}"; ((num++)); done
</code></pre>

Simplified version of <a href="http://ubuntuforums.org/showthread.php?t=1355021">http://ubuntuforums.org/showthread.php?t=1355021</a>

blocks|key|1204488|text|使用"rename“命令|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204489|rename+-N+0001+-X+'s/.*/$N/'+*.jpg|code-block|syntax|javascript|1204490|或|1204491|rename+-N+0001+'s/.*/$N.jpg/'+*.jpg|1204492|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

with "rename" command

<pre><code>rename -N 0001 -X 's/.*/$N/' *.jpg
</code></pre>

or

<pre><code>rename -N 0001 's/.*/$N.jpg/' *.jpg
</code></pre>

blocks|key|1204301|text|要在所有情况下都有效，请为名称中包含空格的文件添加\“|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204302|find+.+-name+'*.jpg'+%7C+gawk+'BEGIN{+a=1+}{+printf+"mv+\"%25s\"+%2504d.jpg\n",+$0,+a%2B%2B+}'+%7C+bash|code-block|syntax|javascript|1204303|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To work in all situations, put a \" for files that have space in the name

<pre><code>find . -name '*.jpg' | gawk 'BEGIN{ a=1 }{ printf "mv \"%s\" %04d.jpg\n", $0, a++ }' | bash
</code></pre>

blocks|key|990811|text|按照命令将所有文件重命名为序列和小写扩展名：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990812|rename+--counter-format+000001+--lower-case+--keep-extension+--expr='$_+=+"$N"+if+@EXT'+*|code-block|syntax|javascript|990813|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Follow command rename all files to sequence and also lowercase extension:

<pre><code>rename --counter-format 000001 --lower-case --keep-extension --expr='$_ = "$N" if @EXT' *
</code></pre>

blocks|key|990907|text|find+.++%7C+grep+'avi'+%7C+nl+-nrz+-w3+-v1+%7C+while+read+n+f;+do+mv+"$f"+"$n.avi";+done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|990908|find+.将显示文件夹和子文件夹中的所有文件。|unstyled|offset|length|style|CODE|990909|grep+'avi'将过滤所有带有avi扩展名的文件。|990910|nl+-nrz+-w3+-v1将显示从001+002开始的序列号，后跟文件名。|990911|while+read+n+f;+do+mv+"$f"+"$n.avi";+done会将文件名更改为序列号。|990912|entityMap^0|0|0|6|0|0|A|0|0|F|0|0|15|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|T|8|@$G|U|H|V|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|W|8|@$G|X|H|Y|I|J]]|9|@]|A|$]]|$1|M|3|N|5|F|7|Z|8|@$G|10|H|11|I|J]]|9|@]|A|$]]|$1|O|3|P|5|F|7|12|8|@$G|13|H|14|I|J]]|9|@]|A|$]]|$1|Q|3|-4|5|F|7|15|8|@]|9|@]|A|$]]]|R|$]]

<pre><code>find . | grep 'avi' | nl -nrz -w3 -v1 | while read n f; do mv &quot;$f&quot; &quot;$n.avi&quot;; done
</code></pre>
<code>find .</code> will display all file in folder and subfolders.
<code>grep 'avi'</code> will filter all files with avi extension.
<code>nl -nrz -w3 -v1</code> will display sequence number starting 001 002 etc following by file name.
<code>while read n f; do mv &quot;$f&quot; &quot;$n.avi&quot;; done</code> will change file name to sequence numbers.

blocks|key|1204542|text|再次使用Pero的解决方案，只需稍加修改，因为find将按照项目存储在目录条目中的顺序遍历目录树。这将(大部分)在同一台机器上从一次运行到另一次运行是一致的，如果没有删除，则本质上是“文件/目录创建顺序”。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1204543|但是，在某些情况下，您需要获得一些逻辑顺序，比如按名称排序，本例中使用了该名称。|1204544|find+-name+'*.jpg'+%7C+sort+-n+%7C+#+find+jpegs
gawk+'BEGIN{+a=1+}{+printf+"mv+%25s+%2504d.jpg\n",+$0,+a%2B%2B+}'+%7C+#+build+mv+command
bash+#+run+that+command+|code-block|syntax|javascript|1204545|entityMap^0|N|4|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Again using Pero's solution with little modifying, because <code>find</code> will be traversing the directory tree in the order items are stored within the directory entries. This will (mostly) be consistent from run to run, on the same machine and will essentially be "file/directory creation order" if there have been no deletes.

However, in some case you need to get some logical order, say, by name, which is used in this example.

<pre><code>find -name '*.jpg' | sort -n | # find jpegs
gawk 'BEGIN{ a=1 }{ printf "mv %s %04d.jpg\n", $0, a++ }' | # build mv command
bash # run that command 
</code></pre>

blocks|key|1204649|text|我遇到了类似的问题，并为此编写了一个shell脚本。尽管已经有很多不错的答案，但我还是决定把它贴出来，因为我认为它对某些人很有帮助。请随时改进它！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204650|numerate|offset|length|1204651|@Gnutt您想要的行为可以通过键入以下命令来实现：|1204652|./numerate.sh+-d+<path+to+directory>+-o+modtime+-L+4+-b+<startnumber>+-r|code-block|syntax|javascript|1204653|如果省略了选项-r，则只会模拟扩孔(对测试应该很有帮助)。|style|CODE|1204654|选项L描述目标数字的长度(将用前导零填充)也可以使用选项-p+<prefix>+-s+<suffix>添加前缀/后缀。|1204655|如果有人想让文件在编号前按数字排序，只需删除-o+modtime选项即可。|1204656|entityMap|0|LINK|mutability|MUTABLE|url|http://sourceforge.net/projects/numerate/files/numerate.sh/download^0|0|0|8|0|0|0|0|7|2|0|S|B|14|B|0|M|A|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@$D|14|E|15|1|16]]|A|$]]|$1|F|3|G|5|6|7|17|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|18|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|19|8|@$D|1A|E|1B|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1C|8|@$D|1D|E|1E|O|P]|$D|1F|E|1G|O|P]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1H|8|@$D|1I|E|1J|O|P]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

I had a similar issue and wrote a shell script for that reason. I've decided to post it regardless that many good answers were already posted because I think it can be helpful for someone. Feel free to improve it! 

<a href="http://sourceforge.net/projects/numerate/files/numerate.sh/download" rel="nofollow">numerate</a>

@Gnutt The behavior you want can be achieved by typing the following: 

<pre><code>./numerate.sh -d &lt;path to directory&gt; -o modtime -L 4 -b &lt;startnumber&gt; -r
</code></pre>

If the option <code>-r</code> is left out the reaming will be only simulated (Should be helpful for testing).

The otion L describes the length of the target number (which will be filled with leading zeros) 
it is also possible to add a prefix/suffix with the options <code>-p &lt;prefix&gt;</code> <code>-s &lt;suffix&gt;</code>. 

In case somebody wants the files to be sorted numerically before they get numbered, just remove the <code>-o modtime</code> option.

blocks|key|990285|text|a=1

for+i+in+*.jpg;+do
+mv+--+"$i"+"$a.jpg"
+a=`expr+$a+%2B+1`
done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|990286|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

blocks|key|990472|text|大多数其他解决方案将覆盖已命名为数字的现有文件。如果运行脚本，添加更多文件，然后再次运行脚本，这将是一个特别的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990473|此脚本首先重命名现有的数字文件：|990474|#!/usr/bin/perl

use+strict;
use+warnings;

use+File::Temp+qw/tempfile/;

my+$dir+=+$ARGV[0]
++++or+die+"Please+specify+directory+as+first+argument";

opendir(my+$dh,+$dir)+or+die+"can't+opendir+$dir:+$!";

#+First+rename+any+files+that+are+already+numeric
while+(my+@files+=+grep+{+/%5E[0-9]%2B(\..*)?$/+}+readdir($dh))
{
++++for+my+$old+(@files)+{
++++++++my+$ext+=+$old+=~+/(\.[%5E.]%2B)$/+?+$1+:+'';
++++++++my+($fh,+$new)+=+tempfile(DIR+=>+$dir,+SUFFIX+=>+$ext);
++++++++close+$fh;
++++++++rename+"$dir/$old",+$new;
++++}
}

rewinddir+$dh;
my+$i;
while+(my+$file+=+readdir($dh))
{
++++next+if+$file+=~+/\A\.\.?\z/;
++++my+$ext+=+$file+=~+/(\.[%5E.]%2B)$/+?+$1+:+'';
++++rename+"$dir/$file",+sprintf("%25s/%2504d%25s",+$dir,+%2B%2B$i,+$ext);+
}|code-block|syntax|javascript|990475|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The majority of the other solutions will overwrite existing files already named as a number. This is particularly a problem if running the script, adding more files, and then running the script again.

This script renames existing numerical files first:

<pre><code>#!/usr/bin/perl

use strict;
use warnings;

use File::Temp qw/tempfile/;

my $dir = $ARGV[0]
 or die "Please specify directory as first argument";

opendir(my $dh, $dir) or die "can't opendir $dir: $!";

# First rename any files that are already numeric
while (my @files = grep { /^[0-9]+(\..*)?$/ } readdir($dh))
{
 for my $old (@files) {
 my $ext = $old =~ /(\.[^.]+)$/ ? $1 : '';
 my ($fh, $new) = tempfile(DIR =&gt; $dir, SUFFIX =&gt; $ext);
 close $fh;
 rename "$dir/$old", $new;
 }
}

rewinddir $dh;
my $i;
while (my $file = readdir($dh))
{
 next if $file =~ /\A\.\.?\z/;
 my $ext = $file =~ /(\.[^.]+)$/ ? $1 : '';
 rename "$dir/$file", sprintf("%s/%04d%s", $dir, ++$i, $ext); 
}
</code></pre>

blocks|key|990717|text|按时间排序，仅限于jpg、前导零和基名(如果您可能需要一个基名)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990718|ls+-t+*.jpg+%7C+cat+-n+%7C+++++++++++++++++++++++++++++++++++++++++++\
while+read+n+f;+do+mv+"$f"+"$(printf+thumb_%2504d.jpg+$n)";+done|code-block|syntax|javascript|990719|(全部在一行上，不带\)|offset|length|style|CODE|990720|entityMap^0|0|0|A|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Sorted by time, limited to jpg, leading zeroes and a basename (in case you likely want one):

<pre><code>ls -t *.jpg | cat -n | \
while read n f; do mv "$f" "$(printf thumb_%04d.jpg $n)"; done
</code></pre>

(all on one line, without the <code>\</code>)

blocks|key|990854|text|我花了3-4个小时为这篇文章开发了这个解决方案：https://www.cloudsavvyit.com/8254/how-to-bulk-rename-files-to-numeric-file-names-in-linux/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|990855|if+[+!+-r+_e+-a+!+-r+_c+];+then+echo+'pdf'+>+_e;+echo+1+>+_c+;find+.+-name+"*.$(cat+_e)"+-print0+%7C+xargs+-0+-t+-I{}+bash+-c+'mv+-n+"{}"+$(cat+_c).$(cat+_e);echo+$[+$(cat+_c)+%2B+1+]+>+_c';+rm+-f+_e+_c;+fi|code-block|syntax|javascript|990856|这适用于任何类型的文件名(空格、特殊字符)，方法是使用find和xargs的正确\0转义，并且如果愿意，可以通过将echo+1增加到任何其他数字来设置起始文件命名偏移量。|style|CODE|990857|在开始时设置扩展名(此处示例中的pdf)。它也不会覆盖任何现有的文件。|990858|entityMap|0|LINK|mutability|MUTABLE|url|https://www.cloudsavvyit.com/8254/how-to-bulk-rename-files-to-numeric-file-names-in-linux/^0|O|2I|0|0|0|R|4|W|5|14|2|1L|6|0|G|3|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@$A|12|B|13|K|L]|$A|14|B|15|K|L]|$A|16|B|17|K|L]|$A|18|B|19|K|L]]|9|@]|C|$]]|$1|M|3|N|5|6|7|1A|8|@$A|1B|B|1C|K|L]]|9|@]|C|$]]|$1|O|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I spent 3-4 hours developing this solution for an article on this:
<a href="https://www.cloudsavvyit.com/8254/how-to-bulk-rename-files-to-numeric-file-names-in-linux/" rel="nofollow noreferrer">https://www.cloudsavvyit.com/8254/how-to-bulk-rename-files-to-numeric-file-names-in-linux/</a>
<pre><code>if [ ! -r _e -a ! -r _c ]; then echo 'pdf' &gt; _e; echo 1 &gt; _c ;find . -name &quot;*.$(cat _e)&quot; -print0 | xargs -0 -t -I{} bash -c 'mv -n &quot;{}&quot; $(cat _c).$(cat _e);echo $[ $(cat _c) + 1 ] &gt; _c'; rm -f _e _c; fi
</code></pre>
This works for any type of filename (spaces, special chars) by using correct <code>\0</code> escaping by both <code>find</code> and <code>xargs</code>, and you can set a start file naming offset by increasing <code>echo 1</code> to any other number if you like.
Set extension at start (<code>pdf</code> in example here). It will also not overwrite any existing files.

blocks|key|1204280|text|此脚本将在Mac+OS+bash上按创建日期对文件进行排序。我用它来批量重命名视频。只需更改扩展名和名称的第一部分。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204281|ls+-trU+*.mp4%7C+awk+'BEGIN{+a=0+}{+printf+"mv+%25s+lecture_%2503d.mp4\n",+$0,+a%2B%2B+}'+%7C+bash|code-block|syntax|javascript|1204282|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This script will sort the files by creation date on Mac OS bash. I use it to mass rename videos. Just change the extension and the first part of the name.

<pre><code>ls -trU *.mp4| awk 'BEGIN{ a=0 }{ printf "mv %s lecture_%03d.mp4\n", $0, a++ }' | bash
</code></pre>

blocks|key|990238|text|下面是另一个使用"rename“命令的解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990239|find+-name+'access.log.*.gz'+%7C+sort+-Vr+%7C+rename+'s/(\d%2B)/$1%2B1/ge'|code-block|syntax|javascript|990240|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here a another solution with "rename" command:

<pre><code>find -name 'access.log.*.gz' | sort -Vr | rename 's/(\d+)/$1+1/ge'
</code></pre>

blocks|key|1205171|text|Pero的回答让我来到了这里:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1205172|我想相对于时间重命名文件，因为图像查看器不会按时间顺序显示图像。|1205173|ls+-tr+*.jpg+%7C+#+list+jpegs+relative+to+time
gawk+'BEGIN{+a=1+}{+printf+"mv+%25s+%2504d.jpg\n",+$0,+a%2B%2B+}'+%7C+#+build+mv+command
bash+#+run+that+command|code-block|syntax|javascript|1205174|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Pero's answer got me here :)

I wanted to rename files relative to time as the image viewers did not display images in time order.

<pre><code>ls -tr *.jpg | # list jpegs relative to time
gawk 'BEGIN{ a=1 }{ printf "mv %s %04d.jpg\n", $0, a++ }' | # build mv command
bash # run that command
</code></pre>

blocks|key|1204800|text|要对一个文件夹中的6000个文件重新编号，您可以使用ACDsee程序的“重命名”选项。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1204801|要定义前缀，请使用以下格式：####"*"|offset|length|style|CODE|1204802|然后设置起始号并按Rename，程序将用序列号重命名所有6000个文件。|1204803|entityMap^0|0|E|7|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

To renumber 6000, files in one folder you could use the 'Rename' option of the ACDsee program.

For defining a prefix use this format: <code>####"*"</code>

Then set the start number and press Rename and the program will rename all 6000 files with sequential numbers.

I want to rename the files in a directory to sequential numbers. Based on creation date of the files.

For Example <code>sadf.jpg</code> to <code>0001.jpg</code>, <code>wrjr3.jpg</code> to <code>0002.jpg</code> and so on, the number of leading zeroes depending on the total amount of files (no need for extra zeroes if not needed).

Renaming files in a folder to sequential numbers

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想将目录中的文件重命名为序列号。基于文件的创建日期。例如，sadf.jpg到0001.jpg，wrjr3.jpg到0002.jpg等等，前导零的数量取决于文件的总量(如果不需要，则不需要额外的零)。

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