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社区首页 >问答首页 >Presto: JSON提取多个层

Presto: JSON提取多个层
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Stack Overflow用户
提问于 2020-01-29 07:12:06
回答 1查看 579关注 0票数 0

我试图在每个服务下提取接受检查的名称和状态(多个)。我试过了

代码语言:javascript
运行
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TRANSFORM(CAST(JSON_PARSE(json_format(json_extract(json_extract(services_data, '$.services'), '$.inspections'))) AS ARRAY<JSON>), x -> JSON_EXTRACT_SCALAR(x, '$.title')) AS inspection,

有办法做到这一点吗?我检查了张贴在相同的其他问题,但没有看到这些复杂的层。

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回答 1

Stack Overflow用户

回答已采纳

发布于 2020-01-29 23:04:26

我获取了您的数据,添加了更多用于测试的内容,并提出了以下SQL查询:

代码语言:javascript
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with example(record) as (
    values(json '{"services":[{"category_id":1,"completed":true,"created_at":"2020-01-27T20:44:57Z","hazmats":[],"inspections":[{"created_at":"2020-01-27T20:44:57Z","detail":null,"inspection_id":10209887,"name":"Accelerator Pedal","state":"green","updated_at":"2020-01-27T20:44:57Z"},{"created_at":"2020-01-27T20:44:57Z","detail":null,"inspection_id":10209887,"name":"Accelerator Pedal 2","state":"orange","updated_at":"2020-01-27T20:44:57Z"}]},{"category_id":1,"completed":true,"created_at":"2020-01-27T20:44:57Z","hazmats":[],"inspections":[{"created_at":"2020-01-27T20:44:57Z","detail":null,"inspection_id":10209887,"name":"Some dummy name","state":"navy","updated_at":"2020-01-27T20:44:57Z"}]}]}')
)

select name, "state"
from example
cross join unnest(cast(json_extract(record, '$.services') as array<json>)) as u(service)
cross join unnest(cast(json_extract(service, '$.inspections') as array(row(name varchar, "state" varchar)))) as x(name,"state");

结果如下所示:

代码语言:javascript
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name                |   state
------------------------------
Accelerator Pedal   |   green
Accelerator Pedal 2 |   orange
Some dummy name     |   navy

在我看来这就是你要找的东西。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/59958462

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