可以将标签作为变量吗?我有多个标签:
@IBOutlet weak var FL1at0: UIButton!
@IBOutlet weak var FL1at3: UIButton!
@IBOutlet weak var FL1at6: UIButton!
@IBOutlet weak var FL1at9: UIButton!
@IBOutlet weak var FL1at12: UIButton!
@IBOutlet weak var FL1at15: UIButton!
@IBOutlet weak var FL1at18: UIButton!
@IBOutlet weak var FL1at21: UIButton!示例函数:
else
{
UserDefaults.standard.set(true, forKey: "RedFl1")
self.FL1at0.setTitleColor(UIColor.red, for: .normal); self.ProgressUpdate()
}有没有一种方法可以这样设置表格:
self.FL1at"\(TimeStamp)".setTitleColor(UIColor.red, for: .normal)//TimeStamp comes from function发布于 2020-04-29 20:14:11
试试这个:
let dict: Dictionary<String, UIButton> = ["FL1at0": FL1at0, "FL1at3": FL1at3, ...]
let x = "FL1at\(TimeStamp)"
if let y = dict[x] as? UIButton {
y.setTitleColor(UIColor.red, for: .normal)
}发布于 2020-04-29 20:05:27
你不能。但你可以将按钮保存在字典中:
var dic: [String: UIButton] = ["FL1at0": FL1at0]然后您可以使用name来访问它,如下所示:
dic["FL1at\(TimeStamp)"]?.setTitleColorxxxx..https://stackoverflow.com/questions/61501105
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