问如何合并具有相同值的Js对象？

EN

const findDuplicates = arr => arr.filter((item, index) => arr.indexOf(item) !== index);
    
const rearangeObject = providedObj => {
     const newObj = {};
     const keys = Object.keys(providedObj);
    
      for (let i = 0; i < keys.length; i++) {
          for (let j = i + 1; j < keys.length; j++) {
              let str = keys[i] + ", " + keys[j];
              newObj[str] = findDuplicates([...providedObj[keys[i]], ...providedObj[keys[j]]]);
          }
      }
      return newObj;
}
    
const providedObj = {
      "harsh": ["cricket", "vollyball"],
      "aasim": ["cricket", "football", "ludo", "COD", "rugb", "vollyball", "Racing"],
      "jignesh": ["cycling", "cricket"],
      "jimish": ["cycling"],
      "prince": ["vollyball", "football"],
      "raj": ["ludo", "cricket", "cycling"]
};
console.log(rearangeObject(providedObj));

  var name = [
        "harsh",
        "aasim",
        "jignesh",
        "jimish",
        "prince",
        "raj"
    ]
    var array1 = [
        ["cricket", "vollyball"],
        ["cricket", "football", "ludo", "COD", "rugb", "vollyball", "Racing"],
        ["cycling", "cricket"],
        ["cycling"],
        ["vollyball", "football"],
        ["ludo", "cricket", "cycling"]
    ];
    //array1= console.log(array1);
    array = [];
    for (var i = 0; i < array1.length; i++) {

        for (var k = 1; k < array1.length; k++) {
            var array5 = array1[i].filter(function(obj) {
                return array1[k].indexOf(obj) == -1;
            });
            
            if(array5.length!=0){
            array[name[i]] = array5
            
            }

        }
    }

    console.log(array);

const input = {
    "harsh" : ["cricket", "vollyball"],
    "aasim" : ["cricket", "football", "ludo", "COD", "rugb", "vollyball", "Racing"],
    "jignesh" : ["cycling", "cricket"],
    "jimish" : ["cycling"],
    "prince" : ["vollyball","football"],
    "raj" : ["ludo","cricket","cycling"]
};

const inputKeys = Object.keys(input);
const keyCombinations = [];
while (inputKeys.length) {
  const k0 = inputKeys.shift();
  inputKeys.forEach(k1 => keyCombinations.push([k0, k1]));
}
const output = {};
keyCombinations.forEach(k => output[k.join(', ')] = input[k[0]].filter(k0 => input[k[1]].includes(k0)));
console.log(output);