我正在尝试在我的ListView中创建一个表单,它将发布到ListView并按POSTed属性进行过滤。
这是在Django 2.1项目中。
我尝试将self和request argunments都传递给post函数,但是我收到了下面的异常。
def post(self, request):
导致TypeError异常:
post() takes 1 positional argument but 2 were given
如果我试图通过删除其中一个参数来解决错误,以便只将self传递给post() def post(self)函数,我会收到以下TypeError异常:
post() takes 1 positional argument but 2 were given
尽管事实是只有self被传递。我只试着传递请求,结果是一样的。
许多在线示例显示def post(self, request, *args, **kwargs)
这将导致以下明显的例外:too many values to unpack (expected 2)
删除所有参数会产生TypeError:post() takes 0 positional arguments but 2 were given
类thing_dashboard(ListView):‘’已处理所有订单‘’
template_name = 'thing/orders_dashboard.html'
paginate_by = 25 
def post(self, request):
    queryset = Order.objects.all().order_by('-ordered_date')
    rejected = self.request.POST.get('rejected')
    if rejected == 'False':
        queryset = Order.objects.filter(state='rejected')
        return queryset
    return queryset
def get_queryset(self):
    queryset = Order.objects.all().order_by('-ordered_date')
    return queryset我希望能够在一个简单的基于函数的视图中引用self.request.POST.get(),然后处理逻辑以返回我试图实现的过滤查询集。
发布于 2019-06-19 21:27:55
首先,删除post方法,然后尝试它:
template_name = 'thing/orders_dashboard.html'
paginate_by = 25 
def get_queryset(self):
    rejected = self.request.POST.get('rejected') or None
    if rejected:
        return Order.objects.filter(state='rejected').order_by('-ordered_date')
    return Order.objects.all().order_by('-ordered_date')https://stackoverflow.com/questions/56668468
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