entityMap|blocks|key|f5t1g|text|当您在一行中编写一个变量并执行它时，jupyter+notebook假定您想知道该变量的值，并将其隐式转换为print(变量)，因此打印出该变量的值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|6lvir|当您使用多个语句时，您很少想要打印语句中使用的所有变量。所以它没有在这种情况下实现。|ca6ce^0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|F|9|@]|A|@]|B|$]]|$2|C|4|D|6|7|8|G|9|@]|A|@]|B|$]]|$2|E|4|-4|6|7|8|H|9|@]|A|@]|B|$]]]]

When you write a variable in a line and execute it jupyter notebook assumes that you want to know the value of the variable and implicitly converts it to print(variable) so the value of the variable is printed.

When you use multiple statement you will rarely want to print all variables used in the statements. So it is not implemented for this case

entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://docs.python.org/3/reference/expressions.html|1|https://docs.python.org/3/reference/expressions.html#atom-identifiers|2|https://docs.python.org/3/reference/lexical_analysis.html#literals|3|https://docs.python.org/3/reference/lexical_analysis.html#operators|4|https://docs.python.org/3/reference/simple_stmts.html|5|https://docs.python.org/3/reference/compound_stmts.html|blocks|key|f5756|text|这与expression和python中的语句(参见下面的链接)之间的区别有关。|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|arndi|表达式只能包含identifiers、literals和operators。|9ek59|语句可能要复杂得多。请参阅simple+statements和compound+statements|9hcgn|python+shell将输出表达式的计算结果，但不会与语句一起输出，因为不能保证它的计算结果可以输出。您应该使用print从语句中输出值。|style|CODE|6lmto|考虑一下如果将x替换为它的值(2)会发生什么：|3vr8p|if+2+==+2:
++++2|code-block|syntax|javascript|evg0n|您希望解释器输出2吗|7fo07^0|2|A|0|0|7|B|1|J|8|2|S|9|3|0|D|H|4|V|J|5|0|1L|5|0|7|1|F|1|0|0|8|1|0^^$0|$1|$2|3|4|5|6|$7|8]]|9|$2|3|4|5|6|$7|A]]|B|$2|3|4|5|6|$7|C]]|D|$2|3|4|5|6|$7|E]]|F|$2|3|4|5|6|$7|G]]|H|$2|3|4|5|6|$7|I]]]|J|@$K|L|M|N|2|O|P|1C|Q|@]|R|@$S|1D|T|1E|K|1F]]|6|$]]|$K|U|M|V|2|O|P|1G|Q|@]|R|@$S|1H|T|1I|K|1J]|$S|1K|T|1L|K|1M]|$S|1N|T|1O|K|1P]]|6|$]]|$K|W|M|X|2|O|P|1Q|Q|@]|R|@$S|1R|T|1S|K|1T]|$S|1U|T|1V|K|1W]]|6|$]]|$K|Y|M|Z|2|O|P|1X|Q|@$S|1Y|T|1Z|10|11]]|R|@]|6|$]]|$K|12|M|13|2|O|P|20|Q|@$S|21|T|22|10|11]|$S|23|T|24|10|11]]|R|@]|6|$]]|$K|14|M|15|2|16|P|25|Q|@]|R|@]|6|$17|18]]|$K|19|M|1A|2|O|P|26|Q|@$S|27|T|28|10|11]]|R|@]|6|$]]|$K|1B|M|-4|2|O|P|29|Q|@]|R|@]|6|$]]]]

This has to do with the difference between an <a href="https://docs.python.org/3/reference/expressions.html" rel="nofollow noreferrer">expression</a> and a statement (see below for links) in python.

An expression can only contain <a href="https://docs.python.org/3/reference/expressions.html#atom-identifiers" rel="nofollow noreferrer">identifiers</a>, <a href="https://docs.python.org/3/reference/lexical_analysis.html#literals" rel="nofollow noreferrer">literals</a> and <a href="https://docs.python.org/3/reference/lexical_analysis.html#operators" rel="nofollow noreferrer">operators</a>.

Statements can be significantly more complex. See <a href="https://docs.python.org/3/reference/simple_stmts.html" rel="nofollow noreferrer">simple statements</a> and <a href="https://docs.python.org/3/reference/compound_stmts.html" rel="nofollow noreferrer">compound statements</a>

The python shell will output the evaluation of an expression, but won't with a statement because there's no guarantee it evaluates to something that can be outputted. You should use <code>print</code> to output values from a statement.

Consider what would happen if you replaced <code>x</code> with its value (<code>2</code>):

<pre><code>if 2 == 2:
 2
</code></pre>

Would you expect the interpreter to output <code>2</code>?

I follow a tutorial about Jupyter and Python, where it says that if two consecutive commands are the following:

<pre><code>in: x = 2
in: x
</code></pre>

I should get

<pre><code>out: 2
</code></pre>

as an result. However, the x on single line in a combined block like:

<pre><code>in: x = 2
in: if x == 2:
 x
</code></pre>

does not print the x variable. Is this x on single line somewhat different from x as a single command? When I write this I see, a line is different as whole command but what is the underlying concept or thing that makes the first two commands result 2 but the second three commands nothing?

Jupyter lab: why variable on single line does not generate output?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我遵循了一个关于Jupyter和Python的教程，其中提到如果两个连续的命令如下： in: x = 2in: x 我应该得到 out: 2 结果就是。但是，组合块中单行上的x如下所示： in: x = 2in: if x == 2:       x 不打印x变量。单行中的x与作为单个命令的x有什么不同吗？当我写这篇...

问Jupyter实验室:为什么单行上的变量不能生成输出？
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