Python暂停线程
Python暂停线程
提问于 2020-07-27 12:20:19
我真的是python的新手，我甚至不知道这个python问题的标题是否正确。无论如何，我正面临着一个错误代码，我在过去的几个小时里一直试图找到修复它的方法。错误是这样的:提升RuntimeError(“线程只能启动一次”)。
现在我用谷歌搜索了这个错误，我得到了几个解决方案。我试了几个，看起来都不管用。我知道你不能多次使用start函数，但是我怎么能让我的脚本再次工作呢？
import pyautogui, requests, pyperclip
from pynput import mouse, keyboard
from tkinter import filedialog
url = "https://poxgur.com/"
file_path = filedialog.asksaveasfilename(defaultextension='.png')
def on_click(x, y, button, pressed):
global currentMouseX, currentMouseY
if pressed:
currentMouseX, currentMouseY = x, y
if not pressed:
mouse_listener.stop()
im = pyautogui.screenshot(region=(
currentMouseX, currentMouseY, abs(currentMouseX - x), abs(currentMouseY - y)))
im.save(file_path)
print(file_path)
files = {"file": open(file_path, "rb")}
r = requests.post(url + "api.php", files=files)
pyperclip.copy(url + r.text + ".png")
# os.remove(file_path)
mouse_listener.stop()
return False
mouse_listener = mouse.Listener(on_click=on_click)
def on_scroll_lock_release(key):
if key == keyboard.Key.scroll_lock:
if not mouse_listener.is_alive():
mouse_listener.start()
with keyboard.Listener(on_release=on_scroll_lock_release) as listener:
listener.join()错误的含义是：
Unhandled exception in listener callback
Traceback (most recent call last):
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\_util\__init__.py", line 162, in inner
return f(self, *args, **kwargs)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\keyboard\_win32.py", line 283, in _process
self.on_release(key)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\_util\__init__.py", line 78, in inner
if f(*args) is False:
File "C:/Users/marti/Documents/PythonProjects/Acutal Projects/The 100 Projects/Screenshot2.0.py", line 33, in on_scroll_lock_release
mouse_listener.start()
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\threading.py", line 848, in start
raise RuntimeError("threads can only be started once")
RuntimeError: threads can only be started once
Traceback (most recent call last):
File "C:/Users/marti/Documents/PythonProjects/Acutal Projects/The 100 Projects/Screenshot2.0.py", line 37, in <module>
listener.join()
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\_util\__init__.py", line 210, in join
six.reraise(exc_type, exc_value, exc_traceback)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\six.py", line 702, in reraise
raise value.with_traceback(tb)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\_util\__init__.py", line 162, in inner
return f(self, *args, **kwargs)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\keyboard\_win32.py", line 283, in _process
self.on_release(key)
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\site-packages\pynput\_util\__init__.py", line 78, in inner
if f(*args) is False:
File "C:/Users/marti/Documents/PythonProjects/Acutal Projects/The 100 Projects/Screenshot2.0.py", line 33, in on_scroll_lock_release
mouse_listener.start()
File "C:\Users\marti\anaconda3\envs\The 100 Projects\lib\threading.py", line 848, in start
raise RuntimeError("threads can only be started once")
RuntimeError: threads can only be started once
Process finished with exit code 1回答 1
Stack Overflow用户
回答已采纳
发布于 2020-07-27 13:35:50
一种可能的解决方案是在每次启动侦听器之前初始化一个新的侦听器。
您可以通过以下方式重新编码您的解决方案：
mouse_listener = mouse.Listener(on_click=on_click)
def on_scroll_lock_release(key):
if key == keyboard.Key.scroll_lock:
if not mouse_listener.is_alive():
mouse_listener = mouse.Listener(on_click=on_click)
mouse_listener.start()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/63108669
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