awk和printf插入额外的换行符
awk和printf插入额外的换行符
提问于 2021-11-03 02:11:04
我正在处理显示以下文件：
V 220504203222Z 553A21806C0B711ED9E112E0B6680BED unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=ovpn-server-2020/emailAddress=m@icloud.com
R 220925164608Z 211103011032Z E5D625C06F3D6DA4D3A92C092E8D12A0 unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=grom/emailAddress=m2@icloud.com
V 220925165555Z 185B52B7D6ABFF011FB0D7F826DE8851 unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=bind9/emailAddress=martinschmid82@icloud.com
V 220925171609Z 8764585492AE0097F76DFD7C9E2E75C7 unknown /C=DE/ST=BY/L=FU/O=a/OU=msc-dev/CN=bind-9/emailAddress=martinschmid82@icloud.com
V 220925171854Z 5B7D28350F750F5745553E0647B79F63 unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=qnap/emailAddress=m@icloud.com
V 220929131353Z 99E85C7B92BFF646480854B282288E2A unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=ftp/emailAddress=m@icloud.com
V 221012163300Z 39403EA3995349FF8FEC487BD59A1F98 unknown /C=DE/ST=BY/L=FU/O=akaritech.com/OU=msc-dev/CN=masc-mbp/emailAddress=martinschmid82@icloud.com
V 221012163553Z 80668723276AB0B93CF6765F5EA56837 unknown /C=DE/ST=BY/L=FU/O=akaritech.com/OU=msc-dev/CN=masc-ipad/emailAddress=m@icloud.com
V 221016205831Z 7ABD06B289E35D084D19EA170B8F2EC0 unknown /C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=monitoring.brave-vesperia.com/emailAddress=m@icloud.com我想要的是第一列、第二列和第五列在同一行上用空格分隔。我使用的是awk：
#!/bin/bash
index="/opt/easy-rsa/easyrsa3/pki/index.txt"
for line in $(awk '{printf "%c %i %s\n", $1, $2, $5} ' ${index}); do
if ! [[ ${line} =~ ^R.* ]]; then
printf "%s\n" $line ;
fi
done但是，我得到的输出是：
V
220504203222
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=ovpn-server-2020/emailAddress=m@icloud.com
220925164608
unknown
V
220925165555
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=bind9/emailAddress=m@icloud.com
V
220925171609
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=bind-9/emailAddress=m@icloud.com
V
220925171854
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=qnap/emailAddress=m@icloud.com
V
220929131353
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=ftp/emailAddress=m@icloud.com
V
221012163300
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=masc-mbp/emailAddress=m@icloud.com
V
221012163553
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=masc-ipad/emailAddress=m@icloud.com
V
221016205831
/C=DE/ST=BY/L=FU/O=a.com/OU=msc-dev/CN=monitoring.brave-vesperia.com/emailAddress=m@icloud.com我不明白额外的换行符是从哪里来的。
回答 1
Stack Overflow用户
回答已采纳
发布于 2021-11-03 02:15:50
添加空格是因为for line in $(awk ...)将awk的输出拆分为空格，而不是换行符。
您可以通过将IFS设置为只包含换行符或将awk管道到while read line循环来解决此问题。但在awk中只做所有的事情会更简单。
awk '$1 != "R" {printf "%c %i %s\n", $1, $2, $5} ' "${index}"页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/69818903
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