blocks|key|973388|text|#!/bin/bash
cd+"$(dirname+"$0")"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|973389|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#!/bin/bash
cd "$(dirname "$0")"
</code></pre>

blocks|key|973476|text|以下方法也适用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|973477|cd+"${0%25/*}"|code-block|syntax|javascript|973478|this+StackOverflow+answer中详细介绍了该语法。|offset|length|973479|entityMap|0|LINK|mutability|MUTABLE|url|http://stackoverflow.com/questions/6393551/what-is-the-meaning-of-0-in-a-bash-script^0|0|0|0|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

The following also works:

<pre><code>cd "${0%/*}"
</code></pre>

The syntax is thoroughly described in <a href="http://stackoverflow.com/questions/6393551/what-is-the-meaning-of-0-in-a-bash-script">this</a> StackOverflow answer.

blocks|key|973424|text|cd+"$(dirname+"${BASH_SOURCE[0]}")"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|973425|很简单。它起作用了。|unstyled|973426|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>cd "$(dirname "${BASH_SOURCE[0]}")"
</code></pre>

It's easy. It works.

blocks|key|1187855|text|公认的答案适用于在其他地方没有符号链接的脚本，比如$PATH。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1187856|#!/bin/bash
cd+"$(dirname+"$0")"|code-block|syntax|javascript|1187857|然而，如果脚本是通过符号链接运行的，|1187858|ln+-sv+~/project/script.sh+~/bin/;+
~/bin/script.sh|1187859|这将进入~/bin/目录，而不是~/project/目录，如果cd的目的是包含与~/project/相关的依赖项，则这可能会中断脚本|1187860|symlink安全答案如下：|1187861|#!/bin/bash
cd+"$(dirname+"$(readlink+-f+"${BASH_SOURCE[0]}")")"++#+cd+current+directory|1187862|需要readlink+-f来解析潜在符号链接文件的绝对路径。|1187863|需要使用引号来支持可能包含空格的文件路径(这是不好的做法，但假设情况并非如此是不安全的)|1187864|entityMap^0|P|5|0|0|0|0|4|6|G|A|V|2|14|A|0|0|0|2|B|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|13|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@$9|17|A|18|B|C]|$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|U|3|V|5|6|7|1H|8|@$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|W|3|X|5|6|7|1K|8|@]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1L|8|@]|D|@]|E|$]]]|Z|$]]

The accepted answer works well for scripts that have not been symlinked elsewhere, such as into <code>$PATH</code>.
<pre><code>#!/bin/bash
cd &quot;$(dirname &quot;$0&quot;)&quot;
</code></pre>
However if the script is run via a symlink,
<pre><code>ln -sv ~/project/script.sh ~/bin/; 
~/bin/script.sh
</code></pre>
This will cd into the <code>~/bin/</code> directory and not the <code>~/project/</code> directory, which will probably break your script if the purpose of the <code>cd</code> is to include dependencies relative to <code>~/project/</code>
The symlink safe answer is below:
<pre><code>#!/bin/bash
cd &quot;$(dirname &quot;$(readlink -f &quot;${BASH_SOURCE[0]}&quot;)&quot;)&quot; # cd current directory
</code></pre>
<code>readlink -f</code> is required to resolve the absolute path of the potentially symlinked file.
The quotes are required to support filepaths that could potentially contain whitespace (bad practice, but its not safe to assume this won't be the case)

blocks|key|1187600|text|这个脚本看起来很适合我：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1187601|#!/bin/bash
mypath=`realpath+$0`
cd+`dirname+$mypath`
pwd|code-block|syntax|javascript|1187602|pwd命令行回显脚本的位置作为当前工作目录，无论我从哪里运行它。|1187603|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This script seems to work for me:

<pre><code>#!/bin/bash
mypath=`realpath $0`
cd `dirname $mypath`
pwd
</code></pre>

The pwd command line echoes the location of the script as the current working directory no matter where I run it from.

blocks|key|973767|text|我吃了这个，它就起作用了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|973768|#!/bin/bash
cd+"$(dirname+"$0")"
CUR_DIR=$(pwd)|code-block|syntax|javascript|973769|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I take this and it works.
<pre><code>#!/bin/bash
cd &quot;$(dirname &quot;$0&quot;)&quot;
CUR_DIR=$(pwd)
</code></pre>

blocks|key|973413|text|获取脚本的实际路径|type|unstyled|depth|inlineStyleRanges|entityRanges|data|973414|if+[+-L+$0+]+;+then
++++ME=$(readlink+$0)
else
++++ME=$0
fi
DIR=$(dirname+$ME)|code-block|syntax|javascript|973415|(这是我在这里提出的问题的答案：Get+the+name+of+the+directory+where+a+script+is+executed)|offset|length|973416|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/3373132/get-name-of-directory-wher-script-is-executed^0|0|0|G|1K|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Get the real path to your script

<pre><code>if [ -L $0 ] ; then
 ME=$(readlink $0)
else
 ME=$0
fi
DIR=$(dirname $ME)
</code></pre>

(This is answer to the same my question here: <a href="https://stackoverflow.com/questions/3373132/get-name-of-directory-wher-script-is-executed">Get the name of the directory where a script is executed</a>)

blocks|key|973570|text|cd+"`dirname+$(readlink+-f+${0})`"|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|973571|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>cd "`dirname $(readlink -f ${0})`"
</code></pre>

blocks|key|973885|text|大多数答案要么不处理通过相对路径符号链接的文件，要么不是一行程序，要么不处理BSD+(Mac)。一个能完成所有这三项任务的解决方案是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|973886|HERE=$(cd+"$(dirname+"$BASH_SOURCE")";+cd+-P+"$(dirname+"$(readlink+"$BASH_SOURCE"+%7C%7C+echo+.)")";+pwd)|code-block|syntax|javascript|973887|首先，cd+to+bash对脚本目录的概念。然后重新链接该文件，以查看它是否是符号链接(相对的或其他的)，如果是，则cd到该目录。如果不是，则cd到当前目录(保持一行程序是必要的)。然后通过pwd回显当前目录。|offset|length|style|CODE|973888|您可以将--添加到cd和readlink的参数中，以避免命名为like选项的目录出现问题，但在大多数情况下，我并不为此费心。|973889|你可以在这里看到完整的解释和插图：|973890|https://www.binaryphile.com/bash/2020/01/12/determining-the-location-of-your-script-in-bash.html|973891|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|2N|3|0|4|2|0|0|0|2O|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|11|8|@$I|12|J|13|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|14|8|@$I|15|J|16|K|L]]|9|@]|A|$]]|$1|O|3|P|5|6|7|17|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|18|8|@]|9|@$I|19|J|1A|1|1B]]|A|$]]|$1|S|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|R]]]]

Most answers either don't handle files which are symlinked via a relative path, aren't one-liners or don't handle BSD (Mac). A solution which does all three is:
<pre><code>HERE=$(cd &quot;$(dirname &quot;$BASH_SOURCE&quot;)&quot;; cd -P &quot;$(dirname &quot;$(readlink &quot;$BASH_SOURCE&quot; || echo .)&quot;)&quot;; pwd)
</code></pre>
First, cd to bash's conception of the script's directory. Then readlink the file to see if it is a symlink (relative or otherwise), and if so, cd to that directory. If not, cd to the current directory (necessary to keep things a one-liner). Then echo the current directory via <code>pwd</code>.
You could add <code>--</code> to the arguments of cd and readlink to avoid issues of directories named like options, but I don't bother for most purposes.
You can see the full explanation with illustrations here:
<a href="https://www.binaryphile.com/bash/2020/01/12/determining-the-location-of-your-script-in-bash.html" rel="nofollow noreferrer">https://www.binaryphile.com/bash/2020/01/12/determining-the-location-of-your-script-in-bash.html</a>

blocks|key|973599|text|echo+$PWD|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|973600|PWD是一个环境变量。|unstyled|973601|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>echo $PWD
</code></pre>

PWD is an environment variable.

blocks|key|1187739|text|如果你只需要打印当前的工作目录，那么你可以按照下面的步骤操作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1187740|$+vim+test

#!/bin/bash
pwd
:wq+to+save+the+test+file.|code-block|syntax|javascript|1187741|授予execute权限：|1187742|chmod+u%2Bx+test|1187743|然后通过./test执行脚本，然后您可以看到当前的工作目录。|offset|length|style|CODE|1187744|entityMap^0|0|0|0|0|4|6|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

If you just need to print present working directory then you can follow this.

<pre><code>$ vim test

#!/bin/bash
pwd
:wq to save the test file.
</code></pre>

Give execute permission:

<pre><code>chmod u+x test
</code></pre>

Then execute the script by <code>./test</code> then you can see the present working directory.

I'm writing a Bash script. I need the current working directory to always be the directory that the script is located in.
The default behavior is that the current working directory in the script is that of the shell from which I run it, but I do not want this behavior.

How can I set the current working directory to the directory of the script in Bash?

我正在写一个Bash脚本。我需要当前工作目录始终是脚本所在的目录。默认行为是脚本中的当前工作目录是我从中运行它的shell的工作目录，但我不想要这种行为。

问如何在Bash中将当前工作目录设置为脚本所在的目录？
EN

回答 11

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问如何在Bash中将当前工作目录设置为脚本所在的目录？EN

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问如何在Bash中将当前工作目录设置为脚本所在的目录？
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