如何将msg中的附件附加到Mime中，以便在Python中作为电子邮件发送？
如何将msg中的附件附加到Mime中，以便在Python中作为电子邮件发送？
提问于 2021-08-09 15:06:31
我想打开一个.msg文件，获取附件，并将它们发送到特定的邮件地址。我使用extract_msg，我似乎不能只将.msg中的附件附加到我的邮件中。
到目前为止，我所拥有的：
mail = f"{path}/{attachment}"
msg = extract_msg.Message(mail)
msg_sender = str(msg.sender)
msg_subj = str(msg.subject)
msg_message = str(msg.body)
email_sender = 'automailsender123@gmail.com'
password = 'XXX'
send_to_email = send_to
print("----------------------------------------------------------------------------------------------------")
print(f"Send to: {send_to}\nAttachement: {attachment}\n")
msgMime = MIMEMultipart()
msgMime['From'] = msg_sender
msgMime['To'] = send_to_email
msgMime['Subject'] = msg_subj
body = MIMEText(msg_message)
msgMime.attach(body)
resources_dir = "resources"
attachments_dir = os.path.join(resources_dir, "attachments")
part = MIMEBase('application', 'octet-stream')
if msg.attachments:
with tempfile.TemporaryDirectory() as tmp_dir_name:
for att in msg.attachments:
att_save_path = os.path.join(tmp_dir_name, att.longFilename)
att.save(customPath=tmp_dir_name)
attachment_stream = open(att_save_path, 'rb')
part.set_payload(attachment_stream.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % att_save_path)
msgMime.attach(part)
else: print("No attachments")
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
try:
server.login(email_sender, password)
except:
print(f"Login failed for user: {email_sender}\nWith password: {password}")
text = msgMime.as_string()
server.sendmail(email_sender, send_to_email, text)
server.quit()我得到了错误：
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 596, in _rmtree_unsafe
with os.scandir(path) as scandir_it:
NotADirectoryError: [WinError 267] The directory name is invalid: 'C:\\Users\\XXX.XXX\\AppData\\Local\\Temp\\tmpguckqnkr\\image001.jpg'我写信给temp的唯一原因是，似乎不可能只将原始.msg的附件附加到Mime上。
欢迎任何帮助，有错误或更好的方法来处理附件。
编辑:堆栈跟踪：
Traceback (most recent call last):
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 616, in _rmtree_unsafe
os.unlink(fullname)
PermissionError: [WinError 32] The process cannot access the file because it is being used by another process: 'C:\\Users\\KENNET~1.VAN\\AppData\\Local\\Temp\\tmpguckqnkr\\image001.jpg'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\tempfile.py", line 801, in onerror
_os.unlink(path)
PermissionError: [WinError 32] The process cannot access the file because it is being used by another process: 'C:\\Users\\KENNET~1.VAN\\AppData\\Local\\Temp\\tmpguckqnkr\\image001.jpg'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\tempfile.py", line 804, in onerror
cls._rmtree(path)
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\tempfile.py", line 812, in _rmtree
_shutil.rmtree(name, onerror=onerror)
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 740, in rmtree
return _rmtree_unsafe(path, onerror)
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 599, in _rmtree_unsafe
onerror(os.scandir, path, sys.exc_info())
File "C:\Users\Kenneth.VanGysegem\AppData\Local\Programs\Python\Python39\lib\shutil.py", line 596, in _rmtree_unsafe
with os.scandir(path) as scandir_it:
NotADirectoryError: [WinError 267] The directory name is invalid: 'C:\\Users\\KENNET~1.VAN\\AppData\\Local\\Temp\\tmpguckqnkr\\image001.jpg'回答 2
Stack Overflow用户
发布于 2021-08-10 09:55:06
目前还不清楚Message()部件从何而来，也不清楚它到底是做什么的。我将假设它如您所希望的那样工作，并推测您可能是Outlook的受害者，幸运的是找到了一个可以处理其专有消息的库。
您的代码有两个有问题的流程:即使没有提取附件，它也会发送电子邮件；即使连接到SMTP服务器失败，它也会尝试发送。您想要将这些重构为类似于
else:
print("No attachments")
sys.exit(0)在没有提取任何东西的时候退出，并且
try:
server.login(email_sender, password)
except:
print(f"Login failed for user: {email_sender}\nWith password: {password}")
sys.exit(1)在无法继续时退出并返回错误(或者干脆取出try / except并让脚本崩溃并进行回溯；如果它仅供您个人使用，这可能是可以接受的，而且当您看到调试信息时也更容易进行调试)。
(这不是一个恰当的答案，但我觉得我也需要指出这些问题。)
Stack Overflow用户
发布于 2021-08-10 07:19:04
好了，伙计们，这就是我的工作原理：
def send_mails_from_msg(attachment, send_to, path):
mail = f"{path}/{attachment}"
msg = extract_msg.Message(mail)
msg_sender = str(msg.sender)
msg_subj = str(msg.subject)
msg_message = str(msg.body)
email_sender = 'mailsender123@gmail.com'
password = 'XXXXXX'
print("----------------------------------------------------------------------------------------------------")
print(f"Send to: {send_to}\nAttachement: {attachment}\n")
msgMime = MIMEMultipart()
msgMime['From'] = msg_sender
msgMime['To'] = send_to
msgMime['Subject'] = msg_subj
body = MIMEText(msg_message)
msgMime.attach(body)
resources_dir = "resources"
attachments_dir = os.path.join(resources_dir, "attachments")
part = MIMEBase('application', 'octet-stream')
if msg.attachments:
for x in msg.attachments:
x.save(customPath=attachments_dir)
for files in os.listdir(attachments_dir):
print(f"Files: {files}")
attachment = open(f"{attachments_dir}/{files}", 'rb')
part.set_payload(attachment.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; 附件%s“% filename= )msgMime.attach(零件)
else: print("No attachments")
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
try:
server.login(email_sender, password)
except:
print(f"Login failed for user: {email_sender}\nWith password: {password}")
text = msgMime.as_string()
server.sendmail(email_sender, send_to, text)
server.quit()现在这个用邮件发送jpg，任务完成了！但是...附件看起来像这样：__io.BufferedReader name='resources_attachments_image001.jpg'_，它注册为附件，但不能打开...我现在正在试着解决这个问题
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/68714370
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