Swift Json将嵌套数组/字典解码为平面模型
Swift Json将嵌套数组/字典解码为平面模型
提问于 2021-01-30 05:04:28
我正在尝试将下面的json对象解码为我在Swift中的User模型。
我的问题是将值_id和token解码出tokens数组，其中数组中的第一个标记包含要解码为User.tokenId和User.token的值。
我试图将值直接提取/映射到我的用户模型结构中，而不是在我的用户模型中有另一个嵌套结构(比如struct Token { var id: String , var token: String } )。
let json = """
{
"currentLocation": {
"latitude": 0,
"longitude": 0
},
"profileImageUrl": "",
"bio": "",
"_id": "601453e4aae564fc19075b68",
"username": "johnsmith",
"name": "john",
"email": "johnsmith@gmail.com",
"keywords": ["word", "weds"],
"tokens": [
{
"_id": "213453e4aae564fcqu775b69",
"token": "eyJhbGciOiJIUzqoNiIsInR5cCI6IkpXVCJ9.eyJfaWQiOiI2MDE0NTNlNGFhZTU2NGZjMTkwNzViNjgiLCJpYXQiOjE2MTE5NDQ5MzIsImV4cCI6MTYxMjM3NjkzMn0.PbTsA3B0MAfcVvEF1UAMhUXFiqIL1FcxVFGgMTZ5HCk"
}
],
"createdAt": "2021-01-29T18:28:52.845Z",
"updatedAt": "2021-01-29T18:28:52.883Z"
}
""".data(using: .utf8)!
struct User: Codable {
var latitude: Double
var longitude: Double
var profileImageUrl: String
var bio: String
var userId: String
var username: String
var name: String
var email: String
var keywords: [String]
var tokenId: String
var token: String
var createdAt: Date
var updatedAt: Date
private enum UserKeys: String, CodingKey {
case currentLocation
case profileImageUrl
case bio
case userId = "_id"
case username
case name
case email
case keywords
case tokens
case createdAt
case updatedAt
}
private enum CurrentLocationKeys: String, CodingKey {
case latitude
case longitude
}
private enum TokenKeys: String, CodingKey {
case tokenId = "_id"
case token
}
init(from decoder: Decoder) throws {
let userContainer = try decoder.container(keyedBy: UserKeys.self)
let currentLocationContainer = try userContainer.nestedContainer(keyedBy: CurrentLocationKeys.self, forKey: .currentLocation)
self.latitude = try currentLocationContainer.decode(Double.self, forKey: .latitude)
self.longitude = try currentLocationContainer.decode(Double.self, forKey: .longitude)
self.profileImageUrl = try userContainer.decode(String.self, forKey: .profileImageUrl)
self.bio = try userContainer.decode(String.self, forKey: .bio)
self.userId = try userContainer.decode(String.self, forKey: .userId)
self.username = try userContainer.decode(String.self, forKey: .username)
self.name = try userContainer.decode(String.self, forKey: .name)
self.email = try userContainer.decode(String.self, forKey: .email)
self.keywords = try userContainer.decode([String].self, forKey: .keywords)
let tokensContainer = try userContainer.nestedContainer(keyedBy: TokenKeys.self, forKey: .tokens)
self.tokenId = try tokensContainer.decode(String.self, forKey: .tokenId)
self.token = try tokensContainer.decode(String.self, forKey: .token)
self.createdAt = try userContainer.decode(Date.self, forKey: .createdAt)
self.updatedAt = try userContainer.decode(Date.self, forKey: .updatedAt)
}
}
let user = try! decoder.decode(User.self, from: json)回答 1
Stack Overflow用户
发布于 2021-01-30 05:18:07
首先，我假设您的decoder具有适当的日期解码策略，以便能够将ISO8601字符串解码为Date。
token字典的封闭容器是一个数组。您必须插入一个中间nestedUnkeyedContainer
...
var arrayContainer = try userContainer.nestedUnkeyedContainer(forKey: .tokens)
let tokensContainer = try arrayContainer.nestedContainer(keyedBy: TokenKeys.self)
self.tokenId = try tokensContainer.decode(String.self, forKey: .tokenId)
self.token = try tokensContainer.decode(String.self, forKey: .token)
...将JSON解码为多个结构所需的代码要少得多
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65961704
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