blocks|key|50221|text|int+a+=+1;
char+b+=+(char)+a;
System.out.println(b);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|50222|将打印出带有ASCII1的字符(标题开头的字符，这是不可打印的；见下表：C0+Controls+and+Basic+Latin，与Unicode+code+point相同)|unstyled|offset|length|50223|int+a+=+'1';
char+b+=+(char)+a;
System.out.println(b);|50224|将打印带有Unicode代码点49的字符(一个对应于'1')|50225|如果你想转换一个数字(0-9)，你可以在上面加上48，然后进行转换，或者像Character.forDigit(a,+10);这样的东西。|style|CODE|50226|如果您希望转换被视为Unicode代码点的int，则可以使用Character.toChars(48)。|50227|entityMap|0|LINK|mutability|MUTABLE|url|https://en.wikibooks.org/wiki/Unicode/Character_reference/0000-0FFF|1|https://en.wikipedia.org/wiki/Code_point|2|https://docs.oracle.com/javase/10/docs/api/java/lang/Character.html#toChars(int)^0|0|10|R|0|1T|I|1|0|0|0|11|Q|0|L|3|U|L|U|L|2|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|15|8|@]|9|@$G|16|H|17|1|18]|$G|19|H|1A|1|1B]]|A|$]]|$1|I|3|J|5|6|7|1C|8|@]|9|@]|A|$B|C]]|$1|K|3|L|5|F|7|1D|8|@]|9|@]|A|$]]|$1|M|3|N|5|F|7|1E|8|@$G|1F|H|1G|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|1H|8|@$G|1I|H|1J|O|P]|$G|1K|H|1L|O|P]]|9|@$G|1M|H|1N|1|1O]]|A|$]]|$1|S|3|-4|5|F|7|1P|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]|10|$5|V|W|X|A|$Y|11]]|12|$5|V|W|X|A|$Y|13]]]]

<pre><code>int a = 1;
char b = (char) a;
System.out.println(b);
</code></pre>
will print out the char with <a href="https://en.wikipedia.org/wiki/Code_point" rel="noreferrer">Unicode code point</a> 1 (start-of-heading char, which isn't printable; see this table: <a href="https://en.wikibooks.org/wiki/Unicode/Character_reference/0000-0FFF" rel="noreferrer">C0 Controls and Basic Latin</a>, same as ASCII)
<pre><code>int a = '1';
char b = (char) a;
System.out.println(b);
</code></pre>
will print out the char with Unicode code point 49 (one corresponding to '1')
If you want to convert a digit (0-9), you can add 48 to it and cast, or something like <code>Character.forDigit(a, 10);</code>.
If you want to convert an <code>int</code> seen as a Unicode code point, you can use <a href="https://docs.oracle.com/javase/10/docs/api/java/lang/Character.html#toChars(int)" rel="noreferrer"><code>Character.toChars(48)</code></a> for example.

blocks|key|50244|text|int+a+=+1;
char+b+=+(char)+a;
System.out.println(b);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|50245|好的，我也遇到了同样的问题，但我做的是下面的代码。|unstyled|50246|int+a+=+1
char+b+=+Integer.toString(a).charAt(0);
System.out.println(b);|50247|这样，您就可以获得作为char类型的十进制值。我使用索引为0的charAt()，因为该字符串中唯一的值是'a‘，而正如你所知，该字符串中'a’的位置从0开始。|50248|如果我的英语没有被很好的解释，很抱歉，希望能对你有所帮助。|50249|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>int a = 1;
char b = (char) a;
System.out.println(b);
</code></pre>

hola, well i went through the same problem but what i did was the following code.

<pre><code>int a = 1
char b = Integer.toString(a).charAt(0);
System.out.println(b);
</code></pre>

With this you get the decimal value as a char type. I used charAt() with index 0 because the only value into that String is 'a' and as you know, the position of 'a' into that String start at 0.

Sorry if my english isn't well explained, hope it helps you.

blocks|key|50284|text|我的答案类似于jh314的答案，但我会更深入地解释一下。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|50285|在这种情况下，您应该做的是：|50286|int+a+=+1;
char+b+=+(char)(a+%2B+'0');
System.out.println(b);|code-block|syntax|javascript|50287|在这里，我们使用'0‘，因为字符实际上是由ASCII值表示的。'0‘是一个字符，用值48表示。|50288|我们输入(a+%2B+'0')，为了将它们相加，Java将'0‘转换成它的ASCII值，它是48，a是1，所以和是49。然后我们所做的是：|offset|length|style|CODE|50289|(char)(49)|50290|我们将int转换为char。49的ASCII等价物是'1‘。您可以通过这种方式将任何数字转换为字符，这比使用.toString()方法，然后用.charAt()方法减去数字更智能和更好。|50291|entityMap^0|0|0|0|0|4|9|0|0|3|3|9|4|1I|B|1Z|9|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@$M|11|N|12|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|13|8|@]|9|@]|A|$G|H]]|$1|S|3|T|5|6|7|14|8|@$M|15|N|16|O|P]|$M|17|N|18|O|P]|$M|19|N|1A|O|P]|$M|1B|N|1C|O|P]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|V|$]]

My answer is similar to jh314's answer but I'll explain a little deeper.

What you should do in this case is:

<pre><code>int a = 1;
char b = (char)(a + '0');
System.out.println(b);
</code></pre>

Here, we used '0' because chars are actually represented by ASCII values. '0' is a char and represented by the value of 48. 

We typed <code>(a + '0')</code> and in order to add these up, Java converted '0' to its ASCII value which is 48 and a is 1 so the sum is 49. Then what we did is:

<pre><code>(char)(49)
</code></pre>

We casted <code>int</code> to <code>char</code>. ASCII equivalent of 49 is '1'. You can convert any digit to char this way and is smarter and better way than using <code>.toString()</code> method and then subtracting the digit by <code>.charAt()</code> method.

blocks|key|266893|text|看起来您正在寻找Character.forDigit方法：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|266894|final+int+RADIX+=+10;
int+i+=+4;
char+ch+=+Character.forDigit(i,+RADIX);
System.out.println(ch);+//+Prints+'4'|code-block|syntax|javascript|266895|还有一个方法可以从char转换回int：|266896|int+i2+=+Character.digit(ch,+RADIX);
System.out.println(i2);+//+Prints+'4'|266897|请注意，通过更改RADIX，您还可以支持十六进制(基数16)和最大36的任何基数(或Character.MAX_RADIX，因为它也被称为)。|266898|entityMap^0|8|I|0|0|0|0|8|5|16|J|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

It seems like you are looking for the <code>Character.forDigit</code> method:

<pre><code>final int RADIX = 10;
int i = 4;
char ch = Character.forDigit(i, RADIX);
System.out.println(ch); // Prints '4'
</code></pre>

There is also a method that can convert from a char back to an int:

<pre><code>int i2 = Character.digit(ch, RADIX);
System.out.println(i2); // Prints '4'
</code></pre>

Note that by changing the <code>RADIX</code> you can also support hexadecimal (radix 16) and any radix up to 36 (or <code>Character.MAX_RADIX</code> as it is also known as).

blocks|key|266911|text|这里没有人回答真正的“问题”：您正在正确地将int转换为char；在ASCII表中，十进制值01是“标题的开始”，这是一个非打印字符。尝试查找ASCII表并将int值转换为33和7E之间的值；这将为您提供要查看的字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|266912|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Nobody has answered the real "question" here: you ARE converting int to char correctly; in the ASCII table a decimal value of 01 is "start of heading", a non-printing character. Try looking up an ASCII table and converting an int value between 33 and 7E; that will give you characters to look at.

blocks|key|266926|text|如果你想把一个字符转换成它对应的整数，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|266927|int+a+=+(int)+'a';
char+b+=+(char)+a;
System.out.println(b);|code-block|syntax|javascript|266928|这是因为在ASCII中有一些项目无法正常打印。|266929|例如，数字97至122是与小写字母a至z相对应的整数。|266930|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If you want to convert a character to its corresponding integer, you can do something like this:

<pre><code>int a = (int) 'a';
char b = (char) a;
System.out.println(b);
</code></pre>

This happens because in ASCII there are some items that can not be printed normally.

For example, numbers 97 to 122 are integers corresponding to the lowercase letters a to z.

blocks|key|266966|text|如果您希望根据ascii代码打印ascii字符，并且不想超出此范围(如unicode字符)，则可以将变量定义为字节，然后使用(char)转换。即：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|266967|public+static+void+main(String[]+args)+{
++++byte+b+=+65;
++++for+(byte+i=b;+i<=b%2B25;+i%2B%2B)+{
++++++++System.out.print((char)i+%2B+",+");
++++}|code-block|syntax|javascript|266968|顺便说一句，字母'A‘的ascii代码是65|266969|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

if you want to print ascii characters based on their ascii code and do not want to go beyond that (like unicode characters), you can define your variable as a byte, and then use the (char) convert. i.e.:

<pre><code>public static void main(String[] args) {
 byte b = 65;
 for (byte i=b; i&lt;=b+25; i++) {
 System.out.print((char)i + ", ");
 }
</code></pre>

BTW, the ascii code for the letter 'A' is 65

blocks|key|50404|text|如果我们讨论的是类类型，而不是基元类型，则必须完成以下技巧：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|50405|Integer+someInt;
Character+someChar;

someChar+=+(char)Integer.parseInt(String.valueOf(someInt));|code-block|syntax|javascript|50406|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If we are talking about class types - not primitives, the following trick has to be done:

<pre><code>Integer someInt;
Character someChar;

someChar = (char)Integer.parseInt(String.valueOf(someInt));
</code></pre>

blocks|key|266992|text|public+class+String_Store_In_Array+
{
++++public+static+void+main(String[]+args)+
++++{
++++++++System.out.println("+Q.37+Can+you+store+string+in+array+of+integers.+Try+it.");

++++++++String+str="I+am+Akash";
++++++++int+arr[]=new+int[str.length()];
++++++++char+chArr[]=str.toCharArray();
++++++++++char++ch;
++++++++for(int+i=0;i<str.length();i%2B%2B)
++++++++{

++++++++++++arr[i]=chArr[i];
++++++++}
++++++++System.out.println("\nI+have+stored+it+in+array+by+using+ASCII+value");
++++++++for(int+i=0;i<arr.length;i%2B%2B)
++++++++{

++++++++++++System.out.print("+"%2Barr[i]);
++++++++}
++++++++System.out.println("\nI+have+stored+it+in+array+by+using+ASCII+value+to+original+content");
++++++++for(int+i=0;i<arr.length;i%2B%2B)
++++++++{
+++++++++++++ch=(char)arr[i];

++++++++++++System.out.print("+"%2Bch);
++++++++}
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|266993|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public class String_Store_In_Array 
{
 public static void main(String[] args) 
 {
 System.out.println(" Q.37 Can you store string in array of integers. Try it.");

 String str="I am Akash";
 int arr[]=new int[str.length()];
 char chArr[]=str.toCharArray();
 char ch;
 for(int i=0;i&lt;str.length();i++)
 {

 arr[i]=chArr[i];
 }
 System.out.println("\nI have stored it in array by using ASCII value");
 for(int i=0;i&lt;arr.length;i++)
 {

 System.out.print(" "+arr[i]);
 }
 System.out.println("\nI have stored it in array by using ASCII value to original content");
 for(int i=0;i&lt;arr.length;i++)
 {
 ch=(char)arr[i];

 System.out.print(" "+ch);
 }
 }
}
</code></pre>

blocks|key|50453|text|确保整数值为字母/字符的ASCII值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|50454|如果没有，那就去做吧。|50455|for+e.g.+if+int+i=1|code-block|syntax|javascript|50456|然后再加上64，这样它就变成了65+=+'A‘的ASCII值，然后使用|50457|char+x+=+(char)i;

print+x

//+'A'+will+be+printed+|50458|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Make sure the integer value is ASCII value of an alphabet/character.

If not then make it.

<pre><code>for e.g. if int i=1
</code></pre>

then add 64 to it so that it becomes 65 = ASCII value of 'A'
Then use

<pre><code>char x = (char)i;

print x

// 'A' will be printed 
</code></pre>

blocks|key|50485|text|int+a+=+1;
char+b+=+(char)+(a+%2B+48);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|50486|在ASCII中，每个字符都有自己的编号。字符'0‘是小数的48，'1’是49，依此类推。所以如果|unstyled|50487|char+b+=+'2';
int+a+=+b+=+50;|50488|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>int a = 1;
char b = (char) (a + 48);
</code></pre>

In ASCII, every char have their own number. And char '0' is 48 for decimal, '1' is 49, and so on. So if

<pre><code>char b = '2';
int a = b = 50;
</code></pre>

blocks|key|50510|text|有一种方法可以将int转换为char，甚至不使用ASCII值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|50511|示例：|50512|int+i+=+2;
char+ch+=+Integer.toString(i).charAt(0);
System.out.println(ch);|code-block|syntax|javascript|50513|解释：|50514|首先将整数转换为字符串，然后使用字符串函数charAt()从字符串中提取字符。由于整数只有一位数，因此将索引0赋给charAt()函数。|50515|entityMap^0|8|3|E|4|0|0|0|0|L|8|1I|1|1L|8|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|R|$]]

There is one method by which <code>int</code> can be converted to <code>char</code> and even without using ASCII values.
Example:
<pre><code>int i = 2;
char ch = Integer.toString(i).charAt(0);
System.out.println(ch);
</code></pre>
Explanation :
First the integer is converted to string and then by using String function <code>charAt()</code>, character is extracted from the string. As the integer only has one single digit, the index <code>0</code> is given to <code>charAt()</code> function.

blocks|key|50547|text|首先，将int+(或其他类型)转换为String，|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|50548|int+a+=+1;
String+value+=+String.valueOf(a);|code-block|syntax|javascript|50549|然后，将该String转换为char。|50550|char+newValue+=+value.charAt(0);|50551|您可以通过这种方式避免输出为空。|50552|System.out.println(newValue);|50553|entityMap^0|4|3|I|6|0|0|5|6|E|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|S|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|T|$]]

First, convert the <code>int</code> (or another type) to <code>String</code>,
<pre><code>int a = 1;
String value = String.valueOf(a);
</code></pre>
Then, convert that <code>String</code> to <code>char</code>.
<pre><code>char newValue = value.charAt(0);
</code></pre>
You can avoid empty output in this way...
<pre><code>System.out.println(newValue);
</code></pre>

blocks|key|50609|text|您可能希望将其打印为“1”或“a”。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|50610|如果您想要'1‘作为输入，那么：|50611|int+a+=+1;
char+b+=+(char)(a+%2B+'0');
System.out.println(b);|code-block|syntax|javascript|50612|如果你想要'a‘作为输入，那么：|50613|int+a+=+1;
char+b+=+(char)(a-1+%2B+'a');
System.out.println(b);|50614|java将ascii值转换为char+:)|50615|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

you may want it to be printed as '1' or as 'a'.
In case you want '1' as input then :
<pre><code>int a = 1;
char b = (char)(a + '0');
System.out.println(b);
</code></pre>
In case you want 'a' as input then :
<pre><code>int a = 1;
char b = (char)(a-1 + 'a');
System.out.println(b);
</code></pre>
java turns the ascii value to char :)

Below is a code snippet,

<pre><code>int a = 1;
char b = (char) a;
System.out.println(b);
</code></pre>

But what I get is empty output.

<pre><code>int a = '1';
char b = (char) a;
System.out.println(b);
</code></pre>

I will get 1 as my output. 

Can somebody explain this? And if I want to convert an int to a char as in the first snippet, what should I do?

Convert int to char in java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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下面是一个代码片段，int a = 1;char b = (char) a;System.out.println(b);但我得到的是空输出。int a = '1';char b = (char) a;System.out.println(b);我将得到1作为我的输出。有人能解释一下吗？如果我想像第一个代码片段中那样将i...

问在java中将int转换为char
EN

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