发布于 2020-04-17 01:47:02
我建议将卡片文本的String
存储在一个变量中,然后你要做的就是调用卡片的onTap
,你创建了一个函数,并传递了存储文本的字符串为showMyDialog(textVariable)
的变量,它将调用该函数来显示对话框,然后使用textVariable
显示文本。
我附上了一个更准确的例子来实现你想要的。你可以随心所欲地调整UI
import 'package:flutter/material.dart';
void main() => runApp(MyApp());
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
theme: ThemeData(
primarySwatch: Colors.blue,
),
home: HomePage(),
);
}
}
class HomePage extends StatefulWidget {
@override
_HomePageState createState() => _HomePageState();
}
class _HomePageState extends State<HomePage> {
String displayText = "Same Text Everywhere";
@override
Widget build(BuildContext context) {
return Scaffold(
body: Center(
child: GestureDetector(
onTap: ()=> showMyDialog(context,displayText),
child: Card(
child: Padding(
padding: const EdgeInsets.all(10.0),
child: Text(displayText),
),
),
)
),
);
}
Future<void> showMyDialog(BuildContext context, String displayText) {
return showDialog<void>(
context: context,
builder: (BuildContext context) {
return AlertDialog(
content: Text(displayText),
);
},
);
}
}
https://stackoverflow.com/questions/61256560
复制相似问题