POST请求发送JSON数据Java HttpUrlConnection
POST请求发送JSON数据Java HttpUrlConnection
提问于 2014-01-28 19:23:08
我已经开发了一个Java代码，可以使用URL和HttpUrlConnection将以下cURL转换为java代码。cURL为：
curl -i 'http://url.com' -X POST -H "Content-Type: application/json" -H "Accept: application/json" -d '{"auth": { "passwordCredentials": {"username": "adm", "password": "pwd"},"tenantName":"adm"}}'我已经写了这段代码，但它总是给HTTP代码400错误的请求。我找不到丢失的东西。
String url="http://url.com";
URL object=new URL(url);
HttpURLConnection con = (HttpURLConnection) object.openConnection();
con.setDoOutput(true);
con.setDoInput(true);
con.setRequestProperty("Content-Type", "application/json");
con.setRequestProperty("Accept", "application/json");
con.setRequestMethod("POST");
JSONObject cred = new JSONObject();
JSONObject auth = new JSONObject();
JSONObject parent = new JSONObject();
cred.put("username","adm");
cred.put("password", "pwd");
auth.put("tenantName", "adm");
auth.put("passwordCredentials", cred.toString());
parent.put("auth", auth.toString());
OutputStreamWriter wr = new OutputStreamWriter(con.getOutputStream());
wr.write(parent.toString());
wr.flush();
//display what returns the POST request
StringBuilder sb = new StringBuilder();
int HttpResult = con.getResponseCode();
if (HttpResult == HttpURLConnection.HTTP_OK) {
BufferedReader br = new BufferedReader(
new InputStreamReader(con.getInputStream(), "utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
System.out.println("" + sb.toString());
} else {
System.out.println(con.getResponseMessage());
} Stack Overflow用户
发布于 2021-09-25 09:53:02
这里是完整的代码和解决方案
PostJSONWithHttpURLConnection.java类
import android.util.Log;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.URL;
public class PostJSONWithHttpURLConnection {
String charset = "UTF-8";
HttpURLConnection con;
URL urlObj;
JSONObject jObj = null;
StringBuilder result;
public JSONObject makeHttpRequest(String url,
String paramsJSON) {
try {
urlObj = new URL(url);
con = (HttpURLConnection) urlObj.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "application/json; utf-8");
con.setRequestProperty("Accept", "application/json");
con.setDoOutput(true);
con.setReadTimeout(60000);
con.setConnectTimeout(60000);
try (OutputStream os = con.getOutputStream()) {
byte[] input = paramsJSON.getBytes(charset);
os.write(input, 0, input.length);
}
int code = con.getResponseCode();
Log.d("HTTP CODE", String.valueOf(code));
} catch (IOException e) {
e.printStackTrace();
}
try {
//Receive the response from the server
InputStream in = new BufferedInputStream(con.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("JSON Parser", "result: " + result.toString());
} catch (IOException e) {
e.printStackTrace();
}
con.disconnect();
// try parse the string to a JSON object
try {
jObj = new JSONObject(result.toString());
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return jObj;
}
}在doInBackground上使用代码(字符串...strArr)
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS, false);
String writeValueAsString = objectMapper.writeValueAsString(jSONObject);
PostJSONWithHttpURLConnection jsonPOST = new PostJSONWithHttpURLConnection();
JSONObject json = jsonPOST.makeHttpRequest(SERVER_ADDRESS + "YOUR_API", writeValueAsString);jSONObject是一个Json，如下所示：
{
"Password":"PASSWORD",
"FullName":"Full Name",
"Username":"USER_NAME"
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/21404252
复制相关文章
相似问题
腾讯云开发者
