从给定的多行字符串中，给出未使用内置函数时单词“the”出现的次数
从给定的多行字符串中，给出未使用内置函数时单词“the”出现的次数
提问于 2021-04-19 19:54:04
我有一个多行字符串：
Str1 = """I thought a thought.
But the thought I thought
Wasn’t the thought I thought I thought.
If the thought I thought I thought,
Had been the thought I thought ."""从给定的多行字符串中，给出未使用内置函数时单词“the”出现的次数
回答 2
Stack Overflow用户
发布于 2021-04-19 19:57:50
这并不难，只需拆分字符串并对其进行计数：
s = """I thought a thought. But the thought I thought Wasn’t the thought I thought I thought. If the thought I thought I thought, Had been the thought I thought ."""
words = s.split()
count = 0
for word in words:
if word.strip(',.') == 'thought': # remove dots and commers possibly preceding it
count += 1
print(count)
# 12Stack Overflow用户
发布于 2021-04-19 19:57:01
print(Str1.count('thought'))就这样。
如果你正计划做一件事，你可以用“思想”这个词
count = 0
for n in Str1.split():
if 'thought' in n:
count += 1
print(count)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/67161507
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