使用BeautifulSoup从HTML中提取地址标签
使用BeautifulSoup从HTML中提取地址标签
提问于 2021-01-21 12:49:22
似乎无法将以下HTML字符串：
[<address class="styles_address__zrPvy"><svg class="styles_addressIcon__3Pu3L" height="42" viewbox="0 0 32 42" width="32" xmlns="http://www.w3.org/2000/svg"><path d="M14.381 41.153C2.462 23.873.25 22.1.25 15.75.25 7.051 7.301 0 16 0s15.75 7.051 15.75 15.75c0 6.35-2.212 8.124-14.131 25.403a1.97 1.97 0 01-3.238 0zM16 22.313a6.562 6.562 0 100-13.125 6.562 6.562 0 000 13.124z"></path></svg>Level 1 44 Market Street<!-- -->, <!-- -->Sydney</address>]"title“可以正常工作，但"address”不能提取。
path = "C:\\Users\\mpeter\\Downloads\\lksd\\"
titleList = []
for infile in glob.glob(os.path.join(path, "*.html")):
markup = (infile)
soup = BeautifulSoup(open(markup, "r").read(), 'lxml')
title = soup.find_all("title")
title = soup.title.string
titleList.append(title)
streetAddressList = []
for infile in glob.glob(os.path.join(path, "*.html")):
markup = (infile)
soup = BeautifulSoup(open(markup, "r").read(), 'lxml')
address = soup.find_all("address", class_={"styles_address__zrPvy"})
address = soup.address.string
streetAddressList.append(address)
with open('output2.csv', 'w') as myfile:
writer = csv.writer(myfile)
writer.writerows((titleList, streetAddressList))当我去掉address = soup.address.string时，它可以工作，但会提取整个元素。
Stack Overflow用户
发布于 2021-01-21 15:29:56
使用findall，我们可以获得所有匹配的内容。然后需要迭代结果集以获得每个内容。
使用以下代码：
from bs4 import BeautifulSoup
import pandas as pd
strs = '[<address class="styles_address__zrPvy"><svg class="styles_addressIcon__3Pu3L" height="42" viewbox="0 0 32 42" width="32" xmlns="http://www.w3.org/2000/svg"><path d="M14.381 41.153C2.462 23.873.25 22.1.25 15.75.25 7.051 7.301 0 16 0s15.75 7.051 15.75 15.75c0 6.35-2.212 8.124-14.131 25.403a1.97 1.97 0 01-3.238 0zM16 22.313a6.562 6.562 0 100-13.125 6.562 6.562 0 000 13.124z"></path></svg>Level 1 44 Market Street<!-- -->, <!-- -->Sydney</address>] [<address class="styles_address__zrPvy"><svg class="styles_addressIcon__3Pu3L" height="42" viewbox="0 0 32 42" width="32" xmlns="http://www.w3.org/2000/svg"><path d="M14.381 41.153C2.462 23.873.25 22.1.25 15.75.25 7.051 7.301 0 16 0s15.75 7.051 15.75 15.75c0 6.35-2.212 8.124-14.131 25.403a1.97 1.97 0 01-3.238 0zM16 22.313a6.562 6.562 0 100-13.125 6.562 6.562 0 000 13.124z"></path></svg>14, Bengaluru<!-- -->, <!-- -->India</address>]'
soup = BeautifulSoup(strs, 'lxml')
addresses = soup.find_all(class_={"styles_address__zrPvy"})
addr = []
df = pd.DataFrame()
for address in addresses:
addr.append(address.text)
df['address'] = addr
df输出：
address
0 Level 1 44 Market Street, Sydney
1 14, Bengaluru, India现在地址列表在Dataframe中。您可以使用df.to_csv()将此数据帧写入csv
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原文链接：
https://stackoverflow.com/questions/65821352
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