我在Bash中有一个数组,例如:
array=(a c b f 3 5)我需要对数组进行排序。不仅仅是以排序的方式显示内容,还可以获得一个包含排序元素的新数组。新的排序数组可以是全新的,也可以是旧的。
发布于 2018-03-08 05:35:11
最小排序:
#!/bin/bash
array=(.....)
index_of_element1=0
while (( ${index_of_element1} < ${#array[@]} )); do
element_1="${array[${index_of_element1}]}"
index_of_element2=$((index_of_element1 + 1))
index_of_min=${index_of_element1}
min_element="${element_1}"
for element_2 in "${array[@]:$((index_of_element1 + 1))}"; do
min_element="`printf "%s\n%s" "${min_element}" "${element_2}" | sort | head -n+1`"
if [[ "${min_element}" == "${element_2}" ]]; then
index_of_min=${index_of_element2}
fi
let index_of_element2++
done
array[${index_of_element1}]="${min_element}"
array[${index_of_min}]="${element_1}"
let index_of_element1++
done发布于 2015-02-07 02:12:51
array=(a c b f 3 5)
new_array=($(echo "${array[@]}" | sed 's/ /\n/g' | sort))
echo ${new_array[@]}new_array的回应内容为:
3 5 a b c f发布于 2020-04-29 02:30:25
This question看起来密切相关。顺便说一句,这是Bash中的mergesort (没有外部进程):
mergesort() {
local -n -r input_reference="$1"
local -n output_reference="$2"
local -r -i size="${#input_reference[@]}"
local merge previous
local -a -i runs indices
local -i index previous_idx merged_idx \
run_a_idx run_a_stop \
run_b_idx run_b_stop
output_reference=("${input_reference[@]}")
if ((size == 0)); then return; fi
previous="${output_reference[0]}"
runs=(0)
for ((index = 0;;)) do
for ((++index;; ++index)); do
if ((index >= size)); then break 2; fi
if [[ "${output_reference[index]}" < "$previous" ]]; then break; fi
previous="${output_reference[index]}"
done
previous="${output_reference[index]}"
runs+=(index)
done
runs+=(size)
while (("${#runs[@]}" > 2)); do
indices=("${!runs[@]}")
merge=("${output_reference[@]}")
for ((index = 0; index < "${#indices[@]}" - 2; index += 2)); do
merged_idx=runs[indices[index]]
run_a_idx=merged_idx
previous_idx=indices[$((index + 1))]
run_a_stop=runs[previous_idx]
run_b_idx=runs[previous_idx]
run_b_stop=runs[indices[$((index + 2))]]
unset runs[previous_idx]
while ((run_a_idx < run_a_stop && run_b_idx < run_b_stop)); do
if [[ "${merge[run_a_idx]}" < "${merge[run_b_idx]}" ]]; then
output_reference[merged_idx++]="${merge[run_a_idx++]}"
else
output_reference[merged_idx++]="${merge[run_b_idx++]}"
fi
done
while ((run_a_idx < run_a_stop)); do
output_reference[merged_idx++]="${merge[run_a_idx++]}"
done
while ((run_b_idx < run_b_stop)); do
output_reference[merged_idx++]="${merge[run_b_idx++]}"
done
done
done
}
declare -ar input=({z..a}{z..a})
declare -a output
mergesort input output
echo "${input[@]}"
echo "${output[@]}"https://stackoverflow.com/questions/7442417
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