blocks|key|659052|text|这可能看起来像是一个hack，但它做的正是您需要的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|659053|var+unsortedIps+=
++++new[]
++++{
++++++++"192.168.1.4",
++++++++"192.168.1.5",
++++++++"192.168.2.1",
++++++++"10.152.16.23",
++++++++"69.52.220.44"
++++};

var+sortedIps+=+unsortedIps
++++.Select(Version.Parse)
++++.OrderBy(arg+=>+arg)
++++.Select(arg+=>+arg.ToString())
++++.ToList();|code-block|syntax|javascript|659054|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This might look as a hack, but it does exactly what you need:

<pre><code>var unsortedIps =
 new[]
 {
 "192.168.1.4",
 "192.168.1.5",
 "192.168.2.1",
 "10.152.16.23",
 "69.52.220.44"
 };

var sortedIps = unsortedIps
 .Select(Version.Parse)
 .OrderBy(arg =&gt; arg)
 .Select(arg =&gt; arg.ToString())
 .ToList();
</code></pre>

blocks|key|659104|text|您可以将每个IP地址转换为整数，如下所示...|type|unstyled|depth|inlineStyleRanges|entityRanges|data|659105|69.52.220.44+=>

69+*+255+*+255+*+255+%2B
52+*+255+*+255+%2B
220+*+255+%2B
44|code-block|syntax|javascript|659106|然后按整数表示进行排序。|659107|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can convert each IP address into an integer like so ...

<pre><code>69.52.220.44 =&gt;

69 * 255 * 255 * 255 +
52 * 255 * 255 +
220 * 255 +
44
</code></pre>

Then sort by the integer representation.

blocks|key|659139|text|你可能会发现这个函数也很有用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|659140|public+static+class+ExtensionMethods
{
++public+static+int+CompareTo(this+IPAddress+x,+IPAddress+y)
++{
++++var+result+=+x.AddressFamily.CompareTo(y.AddressFamily);
++++if+(result+!=+0)
++++++return+result;

++++var+xBytes+=+x.GetAddressBytes();
++++var+yBytes+=+y.GetAddressBytes();

++++var+octets+=+Math.Min(xBytes.Length,+yBytes.Length);
++++for+(var+i+=+0;+i+<+octets;+i%2B%2B)
++++{
++++++var+octetResult+=+xBytes[i].CompareTo(yBytes[i]);
++++++if+(octetResult+!=+0)
++++++++return+octetResult;
++++}
++++return+0;
++}
}|code-block|syntax|javascript|659141|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You may find this function useful too.

<pre><code>public static class ExtensionMethods
{
 public static int CompareTo(this IPAddress x, IPAddress y)
 {
 var result = x.AddressFamily.CompareTo(y.AddressFamily);
 if (result != 0)
 return result;

 var xBytes = x.GetAddressBytes();
 var yBytes = y.GetAddressBytes();

 var octets = Math.Min(xBytes.Length, yBytes.Length);
 for (var i = 0; i &lt; octets; i++)
 {
 var octetResult = xBytes[i].CompareTo(yBytes[i]);
 if (octetResult != 0)
 return octetResult;
 }
 return 0;
 }
}
</code></pre>

blocks|key|659220|text|您可以将Array.Sort函数与我们将创建的用于比较两个IP的函数一起使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|659221|//ips+is+string+array
Array.Sort(ips,+IpCompare);|code-block|syntax|javascript|659222|然后将此函数放入代码中。|659223|private+static+int+IpCompare(string+x,+string+y)
++++{
++++++++string+ip1+=+x+%2B+'.',+ip2+=+y+%2B+'.';
++++++++string+xSection+=+"",+ySection+=+"";
++++++++for+(int+i+=+0;+i+<+ip1.Length+&&+i+<+ip2.Length;+i%2B%2B)
++++++++{
++++++++++++if+(ip1[i]+==+'.'+&&+ip2[i]+==+'.')
++++++++++++{
++++++++++++++++if+(xSection+!=+ySection)
++++++++++++++++++++return+int.Parse(xSection)+-+int.Parse(ySection);
++++++++++++++++xSection+=+"";+//+Start+compare+the+next+section
++++++++++++++++ySection+=+"";
++++++++++++}
++++++++++++else+if+(ip1[i]+==+'.')+return+-1;+//The+first+section+is+smaller+because+it's+length+is+smaller
++++++++++++else+if+(ip2[i]+==+'.')+return+1;
++++++++++++else
++++++++++++{
++++++++++++++++xSection+%2B=+ip1[i];
++++++++++++++++ySection+%2B=+ip2[i];
++++++++++++}
++++++++}
++++++++return+0;+
++++++++//If+we+would+find+any+difference+between+any+section+it+would+already+return+something.
++++++++//so+that+mean+that+both+IPs+are+the+same
+++}|659224|entityMap|0|LINK|mutability|MUTABLE|url|http://www.csharp-examples.net/sort-array/^0|4|A|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

You can use the <a href="http://www.csharp-examples.net/sort-array/" rel="nofollow noreferrer">Array.Sort</a> function with a function we will create for comparing two IPs:

<pre><code>//ips is string array
Array.Sort(ips, IpCompare);
</code></pre>

And then put this function in the code.

<pre><code>private static int IpCompare(string x, string y)
 {
 string ip1 = x + '.', ip2 = y + '.';
 string xSection = "", ySection = "";
 for (int i = 0; i &lt; ip1.Length &amp;&amp; i &lt; ip2.Length; i++)
 {
 if (ip1[i] == '.' &amp;&amp; ip2[i] == '.')
 {
 if (xSection != ySection)
 return int.Parse(xSection) - int.Parse(ySection);
 xSection = ""; // Start compare the next section
 ySection = "";
 }
 else if (ip1[i] == '.') return -1; //The first section is smaller because it's length is smaller
 else if (ip2[i] == '.') return 1;
 else
 {
 xSection += ip1[i];
 ySection += ip2[i];
 }
 }
 return 0; 
 //If we would find any difference between any section it would already return something.
 //so that mean that both IPs are the same
 }
</code></pre>

blocks|key|659314|text|对于一个简单的解决方案，不需要破解。只需拆分()地址段，用零填充这些段，然后将它们连接在一起。将这一行静态方法放入一个静态类中，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|659315|public+static+class+StringHelper
{
++++public+static+string+IpAddressLabel(string+ipAddress)
++++++++=>+string.Join(".",+ipAddress.Split('.').Select(part+=>+part.PadLeft(3,+'0')));
}|code-block|syntax|javascript|659316|然后随意调用它：|659317|+=>+new[]+{"192.168.1.100",+"192.168.1.1",+"192.168.1.19"}
++++++.OrderBy(ip+=>+StringHelper.IpAddressLabel(ip));|659318|此外，当需要可排序标签时，可以将其用作文件名或其他地方：|659319|192.168.001.001.log
192.168.001.019.log
192.168.001.100.log|659320|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

No hackery required for a simple solution. Just Split() the address segments, pad the segments with zeros, and then join them back together. Put this one line static method into a static class like this:
<pre><code>public static class StringHelper
{
 public static string IpAddressLabel(string ipAddress)
 =&gt; string.Join(&quot;.&quot;, ipAddress.Split('.').Select(part =&gt; part.PadLeft(3, '0')));
}
</code></pre>
And then call it at will:
<pre><code> =&gt; new[] {&quot;192.168.1.100&quot;, &quot;192.168.1.1&quot;, &quot;192.168.1.19&quot;}
 .OrderBy(ip =&gt; StringHelper.IpAddressLabel(ip));
</code></pre>
Also, this can be used as a filename or elsewhere when a sortable label is desired:
<pre><code>192.168.001.001.log
192.168.001.019.log
192.168.001.100.log
</code></pre>

I've a list of IP addresses as follows

<pre><code>192.168.1.5
69.52.220.44
10.152.16.23
192.168.3.10
192.168.1.4
192.168.2.1
</code></pre>

I'm looking for such a way to sort this list to match the below order

<pre><code>10.152.16.23
69.52.220.44
192.168.1.4
192.168.1.5
192.168.2.1
</code></pre>

How to sort list of Ip Addresses using c#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个IP地址列表，如下所示192.168.1.569.52.220.4410.152.16.23192.168.3.10192.168.1.4192.168.2.1我正在寻找这样一种方法来对此列表进行排序，以匹配以下顺序10.152.16.2369.52.220.44192.168.1.4192.168.1.519...

问如何使用c#对Ip地址列表进行排序
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