我在以下查询中遇到了一个奇怪的问题:
SELECT
doubles_team_members.doubles_team_id,
GROUP_CONCAT(CONCAT(members.first_name,' ',members.last_name) SEPARATOR ' & ') team,
GROUP_CONCAT(DISTINCT CONCAT(members.city,', ',members.state) SEPARATOR ' & ') location,
doubles_teams.deleted_by_id
FROM
doubles_team_members
JOIN
doubles_teams USING(doubles_team_id)
JOIN
members USING(member_id)
JOIN
memberships ON members.member_id=memberships.member_id
WHERE
(memberships.expiration_date>=CURDATE() OR members.lifetime=1) AND
(doubles_teams.deleted_by_id IS NULL OR doubles_teams.deleted_by_id=0) AND
(members.deleted_by_id IS NULL OR members.deleted_by_id=0)
GROUP BY
doubles_team_members.doubles_team_id
HAVING
team='Van Williams & Derek Williams';有时我会得到零、一、二或三个结果。我应该总是得到三个结果。这可能是什么原因造成的?
发布于 2021-10-08 08:36:04
正如Solarflare所指出的,GROUP_CONCAT()可以生成随机顺序的team字符串,例如'Van Williams & Derek Williams'或'Derek Williams & Van Williams'。
为了解决这个问题,你可以使用use an explicit ORDER BY within the GROUP_CONCAT()命令,例如:
GROUP_CONCAT(CONCAT(members.first_name,' ',members.last_name) ORDER BY first_name DESC SEPARATOR ' & ') team有关示例,请参阅documentation和this db<>fiddle。
https://stackoverflow.com/questions/69484917
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