blocks|key|3114081|text|基于another+question+on+stackoverflow，我得到了这个代码..这将以米为单位计算结果，而不是以英里为单位:)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3114082|+public+static+float+distFrom(float+lat1,+float+lng1,+float+lat2,+float+lng2)+{
++++double+earthRadius+=+6371000;+//meters
++++double+dLat+=+Math.toRadians(lat2-lat1);
++++double+dLng+=+Math.toRadians(lng2-lng1);
++++double+a+=+Math.sin(dLat/2)+*+Math.sin(dLat/2)+%2B
+++++++++++++++Math.cos(Math.toRadians(lat1))+*+Math.cos(Math.toRadians(lat2))+*
+++++++++++++++Math.sin(dLng/2)+*+Math.sin(dLng/2);
++++double+c+=+2+*+Math.atan2(Math.sqrt(a),+Math.sqrt(1-a));
++++float+dist+=+(float)+(earthRadius+*+c);

++++return+dist;
++++}|code-block|syntax|javascript|3114083|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/120283/^0|2|X|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Based on <a href="https://stackoverflow.com/questions/120283/">another question on stackoverflow</a>, I got this code.. This calculates the result in meters, not in miles :)

<pre><code> public static float distFrom(float lat1, float lng1, float lat2, float lng2) {
 double earthRadius = 6371000; //meters
 double dLat = Math.toRadians(lat2-lat1);
 double dLng = Math.toRadians(lng2-lng1);
 double a = Math.sin(dLat/2) * Math.sin(dLat/2) +
 Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) *
 Math.sin(dLng/2) * Math.sin(dLng/2);
 double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
 float dist = (float) (earthRadius * c);

 return dist;
 }
</code></pre>

blocks|key|3114094|text|在C%2B%2B中，它是这样完成的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3114095|#define+LOCAL_PI+3.1415926535897932385+

double+ToRadians(double+degrees)+
{
++double+radians+=+degrees+*+LOCAL_PI+/+180;
++return+radians;
}

double+DirectDistance(double+lat1,+double+lng1,+double+lat2,+double+lng2)+
{
++double+earthRadius+=+3958.75;
++double+dLat+=+ToRadians(lat2-lat1);
++double+dLng+=+ToRadians(lng2-lng1);
++double+a+=+sin(dLat/2)+*+sin(dLat/2)+%2B+
+++++++++++++cos(ToRadians(lat1))+*+cos(ToRadians(lat2))+*+
+++++++++++++sin(dLng/2)+*+sin(dLng/2);
++double+c+=+2+*+atan2(sqrt(a),+sqrt(1-a));
++double+dist+=+earthRadius+*+c;
++double+meterConversion+=+1609.00;
++return+dist+*+meterConversion;
}|code-block|syntax|javascript|3114096|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

In C++ it is done like this:

<pre><code>#define LOCAL_PI 3.1415926535897932385 

double ToRadians(double degrees) 
{
 double radians = degrees * LOCAL_PI / 180;
 return radians;
}

double DirectDistance(double lat1, double lng1, double lat2, double lng2) 
{
 double earthRadius = 3958.75;
 double dLat = ToRadians(lat2-lat1);
 double dLng = ToRadians(lng2-lng1);
 double a = sin(dLat/2) * sin(dLat/2) + 
 cos(ToRadians(lat1)) * cos(ToRadians(lat2)) * 
 sin(dLng/2) * sin(dLng/2);
 double c = 2 * atan2(sqrt(a), sqrt(1-a));
 double dist = earthRadius * c;
 double meterConversion = 1609.00;
 return dist * meterConversion;
}
</code></pre>

blocks|key|3114098|text|你可以使用Java+Geodesy+Library+for+GPS，它使用的是考虑了地球表面曲率的Vincenty's+formulae。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3114099|实现是这样的：|3114100|import+org.gavaghan.geodesy.*;

...

GeodeticCalculator+geoCalc+=+new+GeodeticCalculator();

Ellipsoid+reference+=+Ellipsoid.WGS84;++

GlobalPosition+pointA+=+new+GlobalPosition(latitude,+longitude,+0.0);+//+Point+A

GlobalPosition+userPos+=+new+GlobalPosition(userLat,+userLon,+0.0);+//+Point+B

double+distance+=+geoCalc.calculateGeodeticCurve(reference,+userPos,+pointA).getEllipsoidalDistance();+//+Distance+between+Point+A+and+Point+B|code-block|syntax|javascript|3114101|生成的距离以米为单位。|3114102|entityMap|0|LINK|mutability|MUTABLE|url|http://www.gavaghan.org/blog/free-source-code/geodesy-library-vincentys-formula-java/|1|http://en.wikipedia.org/wiki/Vincenty%2527s_formulae^0|5|S|0|1D|J|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]|$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|6|7|13|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|14|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|15|8|@]|9|@]|C|$]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

You can use the <a href="http://www.gavaghan.org/blog/free-source-code/geodesy-library-vincentys-formula-java/">Java Geodesy Library for GPS</a>, it uses the <a href="http://en.wikipedia.org/wiki/Vincenty%27s_formulae">Vincenty's formulae</a> which takes account of the earths surface curvature.

Implementation goes like this:

<pre><code>import org.gavaghan.geodesy.*;

...

GeodeticCalculator geoCalc = new GeodeticCalculator();

Ellipsoid reference = Ellipsoid.WGS84; 

GlobalPosition pointA = new GlobalPosition(latitude, longitude, 0.0); // Point A

GlobalPosition userPos = new GlobalPosition(userLat, userLon, 0.0); // Point B

double distance = geoCalc.calculateGeodeticCurve(reference, userPos, pointA).getEllipsoidalDistance(); // Distance between Point A and Point B
</code></pre>

The resulting distance is in meters.

<blockquote>
Possible Duplicate: 
<a href="https://stackoverflow.com/questions/120283/working-with-latitude-longitude-values-in-java">Working with latitude/longitude values in Java</a>
</blockquote>

<h3>Duplicate:</h3>
<ul>
<li><a href="https://stackoverflow.com/questions/120283/">Working with latitude/longitude values in Java</a></li>
<li><a href="https://stackoverflow.com/questions/27928/">How do I calculate distance between two latitude longitude points?</a></li>
</ul>
I need to calculate the distance between two points given by two coordinates. The project I am working on is a Java-project, so Java-code will be great, but pseudo-code can also be given, then I can implement it myself :)
As you probably know, there are three ways to represent coordinates:
<ul>
<li>Degrees:Minutes:Seconds (49°30'00&quot;N, 123°30'00&quot;W)</li>
<li>Degrees:Decimal Minutes (49°30.0', -123°30.0'), (49d30.0m,-123d30.0')</li>
<li>Decimal Degrees (49.5000°,-123.5000°), generally with 4-6 decimal numbers.</li>
</ul>
It's the third way my coordinates are given in, so the code for this values will be preferred :)

Calculate distance in meters when you know longitude and latitude in java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 可能重复：重复：我需要计算由两个坐标给出的两点之间的距离。我正在做的项目是一个Java项目，所以Java代码会很棒，但也可以给出伪代码，然后我可以自己实现它:)您可能知道，有三种表示坐标的方法：Degrees:Minutes:Seconds (北纬49°30‘00“，123°30'00"W)Degrees:Decim...

问在java中知道经度和纬度时，以米为单位计算距离
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问在java中知道经度和纬度时，以米为单位计算距离
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